Work done by a constant force
A porter lifts a box onto a shelf, a girl pushes a trolley down an aisle, and a boy tries to push a parked truck that does not budge. Only some of these count as work in science.
In science, work is done when a force makes an object move in the direction of the force. For a constant force F and a displacement s along the force, W = F × s. The SI unit of work is the joule (J), where 1 J = 1 N × 1 m. Work has magnitude only, with a positive or negative sign. If there is no displacement, there is no work. On a force-displacement graph, the work done is the area under the graph.
In the figure : Work = force × displacement along the force, measured in joules.
Work done by a constant force
In the app you can move this figure with your finger.
Open in the appRule 1: Force and movement both needed — Work is done only when the object moves in the direction of the force, so W = F × s.
- Easy : A force of 25 N pushing a trolley 4 m does 100 J of work.
- Medium : A force of 8 N over 0.5 m does 4 J, the area of the rectangle on the graph.
- Exam-type : No movement means W = 0, however large the force.
Rule 2: Work grows with force and distance — Doubling the force or doubling the distance doubles the work.
- Easy : Lifting three identical bags to the same height takes 3 times the work of lifting one.
- Medium : Lifting one bag to 3 m takes 3 times the work of lifting it to 1 m.
- Exam-type : A porter lifting a 12 kg box 1.5 m does 180 J (g = 10 m/s²).
Work needs both a force and a displacement along it; the unit is the joule.
Thinking that any effort counts as work. If the object does not move, no work is done on it.
Memory clue: W = F × s — work needs a Force and a Shift (displacement).
Spot the difference
| Quantity | Symbol | SI unit |
|---|---|---|
| Work | W | joule (J) |
| Force | F | newton (N) |
| Displacement | s | metre (m) |
Practice questions
- 1What is the SI unit of work?
- 2Write the formula for work done by a constant force along the displacement.
- 3When is the work done by a force zero even though the force acts?
- 4Express 1 joule in newtons and metres.
- 5A force of 25 N pushes a trolley 4 m in its own direction. Find the work done.
- 6Why does a student who holds a heavy bag still do no work on it?
- 7A porter lifts a 12 kg box slowly through 1.5 m. Find the work done. Take g = 10 m/s².
- 8A constant force of 8 N acts over a displacement of 0.5 m. Find the area under the force-displacement graph and say what it represents.
Show answers (try them yourself first)
- 1The joule (J).
- 2W = F × s.
- 3When there is no displacement in the direction of the force.
- 41 J = 1 N × 1 m.
- 5100 J.
- 6Because the bag does not move, so there is no displacement.
- 7180 J.
- 84 J; it is the work done by the force.
Positive, negative and zero work
A boy pulls a sledge across snow while friction drags it back, and a waiter carries a tray straight along a corridor. The same word 'work' has different signs in these cases.
The work done by a force can be positive, negative or zero. If the displacement is in the direction of the force, the work is positive and the energy of the object increases. If the displacement is opposite to the force, the work is negative and the energy decreases. If the object does not move, or the force is at right angles to the displacement, the work is zero. Pushing a wall that does not move does no work on the wall, though the muscles still use up energy.
In the figure : Work is positive along the force, negative against it and zero at right angles.
Rule 1: Sign comes from direction — Work is positive along the force, negative against it and zero at right angles to it.
- Easy : A girl pushes a trolley forward: positive work on the trolley.
- Medium : Friction on a sliding box: negative work.
- Exam-type : A waiter carries a tray along a level floor: the upward force of the hand does zero work.
Rule 2: No displacement means no work — Even a very large force does no work if the object does not move.
- Easy : Pushing a fixed wall: no work on the wall.
- Medium : Holding a barbell steady overhead: no work on it.
- Exam-type : Pressing a book on a table: no work on the book.
Work is positive along the force, negative against it and zero at right angles or with no movement.
Thinking that tiredness means work was done on the object. Work on the object needs displacement.
Memory clue: Along +, Against −, Across 0 — the three A's of the sign of work.
Spot the difference
| Displacement | Sign of work | Example |
|---|---|---|
| Along the force | Positive | Pushing a trolley forward |
| Against the force | Negative | Friction on a sliding box |
| At right angles | Zero | Carrying a tray on a level floor |
Practice questions
- 1When is the work done by a force positive?
- 2What is the work done by a force when the displacement is zero?
- 3Is the work done by friction on a sliding box positive or negative?
- 4A box slides 4 m against a friction of 12 N. Find the work done by friction.
- 5Why is the work done by the hand zero when a waiter carries a tray along a level floor at constant velocity?
- 6A girl pushes a rigid wall hard but it does not move. Is any work done on the wall? Why does she feel tired?
- 7A 2 kg book is raised slowly through 1.5 m. Find the work done by gravity on it. Take g = 10 m/s².
- 8For the same book, find the net work done on it while it is lifted slowly, and explain.
Show answers (try them yourself first)
- 1When the displacement is along the force.
- 2Zero.
- 3Negative.
- 4−48 J.
- 5Because the force on the tray is upward while the displacement is horizontal, at right angles to it.
- 6No, the wall does not move; she feels tired because her muscles use internal energy.
- 7−30 J.
- 8Zero, because the positive work by the lifter cancels the negative work by gravity.
The work-energy theorem and forms of energy
A catapult flings a pebble, a solar panel charges a torch and a student climbs the stairs after a meal. In all three, energy is changing its form.
Energy is the capacity to do work, and its SI unit is the joule. The work-energy theorem says that the work done on an object equals the change in its energy. Positive work raises the energy and negative work lowers it. Energy exists in many forms such as kinetic, potential, heat, light, sound, chemical and electrical energy, and it can change from one form to another. Energy can pass from one object to another by doing work, by heat flow from a hotter to a colder body, or by radiation such as sunlight.
In the figure : Work done on an object equals the change in its energy.
Rule 1: Work equals change in energy — W = final energy − initial energy.
- Easy : A cart's energy rises from 60 J to 150 J, so the work done on it is 90 J.
- Medium : An object's energy falls from 500 J to 320 J, so the work done is −180 J.
- Exam-type : A stationary trolley given 250 J of work gains 250 J of energy.
Rule 2: Energy changes form — In a change, energy is not lost; it appears in another form.
- Easy : A heater turns electrical energy into heat.
- Medium : A green leaf turns light into chemical energy.
- Exam-type : Rubbing palms turns mechanical energy into heat.
Work done equals change in energy, and energy changes form without being lost.
Believing that energy is used up and disappears. It only changes form or moves to other objects.
Memory clue: W = ΔE — the work done is the energy changed.
Spot the difference
| Form of energy | Where found | Changes into |
|---|---|---|
| Chemical | Food in the body | Movement of muscles |
| Electrical | Electric heater | Heat |
| Light | Solar panel | Electrical energy |
Practice questions
- 1Define energy.
- 2What does the work-energy theorem state?
- 3Name the SI unit of energy.
- 4The energy of a trolley rises from 60 J to 150 J. Find the work done on it.
- 5Name the energy change that takes place in a solar panel.
- 6Water flows down from a dam. Which form of energy changes into which?
- 7A car has a net work of −400 J done on it. What is the change in its energy?
- 8Name three ways in which energy can be transferred from one object to another.
Show answers (try them yourself first)
- 1The capacity to do work.
- 2Work done on an object equals the change in its energy.
- 3The joule.
- 490 J.
- 5Light energy changes into electrical energy.
- 6Potential energy changes into kinetic energy.
- 7−400 J.
- 8By doing work, by heat flow and by radiation.
Kinetic energy
A cricket ball racing to the boundary stings the fielder's palm far more than the same ball rolled gently along the grass.
Kinetic energy is the energy a body has because of its motion. For a body of mass m moving with speed v, K = ½ m v². A body at rest has zero kinetic energy, and kinetic energy has no direction. It is proportional to the mass but to the square of the speed, so doubling the speed makes the kinetic energy four times as large. By the work-energy theorem, the work done on a body equals its change in kinetic energy.
In the figure : Kinetic energy K = ½ m v² depends on mass and the square of speed.
Rule 1: Square the speed — Kinetic energy depends on v², so a change in speed matters much more than the same change in mass.
- Easy : Speed doubled: K becomes 4 times.
- Medium : Speed tripled: K becomes 9 times.
- Exam-type : Speed halved: K becomes one-quarter.
Rule 2: Work changes kinetic energy — W = K final − K initial.
- Easy : Raising a 4 kg object from rest to 5 m/s needs 50 J of work.
- Medium : Taking a 3 kg object from 2 m/s to 6 m/s needs 48 J of work.
- Exam-type : A brake does negative work and reduces K.
K = ½ m v²; doubling the speed makes the kinetic energy four times.
Thinking that doubling the speed doubles the kinetic energy. It makes it four times.
Memory clue: half m v squared — say it in full, so that the square of the speed is never forgotten.
Spot the difference
| Change | Effect on K | Reason |
|---|---|---|
| Mass doubled | K doubles | K is proportional to m |
| Speed doubled | K becomes 4 times | K is proportional to v² |
| Speed halved | K becomes one-quarter | K is proportional to v² |
Practice questions
- 1Write the formula for kinetic energy.
- 2What is the kinetic energy of an object at rest?
- 3What happens to the kinetic energy if the speed is tripled?
- 4Find the kinetic energy of a 2 kg object moving at 3 m/s.
- 5A 0.5 kg ball moves at 10 m/s. Find its kinetic energy.
- 6Which has more kinetic energy at the same speed, a truck or a bicycle? Why?
- 7A 1000 kg car moves at 10 m/s. Find its kinetic energy.
- 8A 2 kg object has kinetic energy 64 J. Find its speed.
Show answers (try them yourself first)
- 1K = ½ m v².
- 2Zero.
- 3It becomes 9 times.
- 49 J.
- 525 J.
- 6The truck, because it has the greater mass.
- 750000 J.
- 88 m/s.
Potential energy
A water tank on a roof, a stretched catapult band and a drawn bow all hold energy while they are still, ready to release it.
Potential energy is the energy stored in an object or a system because of its position or shape. Near the Earth's surface, the gravitational potential energy of a mass m raised to a height h is U = m g h. It is proportional to both mass and height, and it depends only on the height, not on the path taken to reach it. A stretched or compressed spring and a bent bow store potential energy because of their changed shape. When the object or spring is released, the stored energy changes into kinetic energy.
In the figure : Potential energy U = m g h is stored by position or shape.
Rule 1: Height matters, path does not — The gain in potential energy is mgh whether the object is lifted straight up, by stairs or by a lift.
- Easy : A 40 kg student gains 2400 J climbing 6 m of stairs.
- Medium : The same student gains 2400 J going up the same 6 m by lift.
- Exam-type : Raising 300 kg of water by 6 m stores 18000 J.
Rule 2: Proportional to m and h — Doubling either the mass or the height doubles the potential energy.
- Easy : A 2 kg object at 5 m has 100 J.
- Medium : A 2 kg object at 10 m has 200 J.
- Exam-type : A 4 kg object at 5 m has 200 J.
U = m g h; stored by position or shape, and it depends only on the height.
Using mgh at any height. It holds near the Earth's surface, where g is nearly constant.
Memory clue: m × g × h — the three things to multiply: mass, gravity and height.
Spot the difference
| Situation | Type | Example |
|---|---|---|
| Object raised up | Gravitational | Water tank on a roof |
| Compressed spring | Elastic | Spring inside a pen |
| Bent bow | Elastic | Arrow ready to fly |
Practice questions
- 1Define potential energy.
- 2Write the formula for gravitational potential energy near the Earth.
- 3Does potential energy depend on the path taken to reach a height?
- 4Find the potential energy of a 2 kg object at a height of 5 m. Take g = 10 m/s².
- 5Why does a ball dropped from a greater height make a deeper dent in sand?
- 6A stretched rubber band is released. Where does its stored energy go?
- 7A pump lifts 300 kg of water to a tank 6 m high. Find the increase in potential energy. Take g = 10 m/s².
- 8A 4 kg object has potential energy 120 J. Find its height. Take g = 10 m/s².
Show answers (try them yourself first)
- 1Energy stored because of position or shape.
- 2U = m g h.
- 3No, only on the height.
- 4100 J.
- 5Because it starts with more stored energy, which becomes more kinetic energy.
- 6It changes into the kinetic energy of the moving object.
- 718000 J.
- 83 m.
Conservation of mechanical energy
A child slides down a smooth slide, a pendulum bob swings to and fro, and a ball thrown upward slows down near the top.
The mechanical energy of an object is the sum of its kinetic and potential energies, E = K + U. If no external force such as friction or air resistance acts, the mechanical energy stays constant. This is the conservation of mechanical energy. In a fall, the potential energy decreases while the kinetic energy increases by the same amount. At the top of a thrown ball's path the kinetic energy is zero and the potential energy is maximum. If friction or air resistance acts, some mechanical energy changes to heat, so the motion dies out, but the total energy of the whole system stays constant.
In the figure : K + U stays constant without friction; what one loses, the other gains.
Rule 1: Loss in U equals gain in K — In a frictionless fall, the potential energy lost appears as kinetic energy, so mgh = ½ m v².
- Easy : A girl sliding down a smooth 5 m slide reaches the bottom at 10 m/s.
- Medium : A ball dropped from 20 m hits the ground at 20 m/s.
- Exam-type : A ball dropped from 1.8 m hits the ground at 6 m/s.
Rule 2: Speed does not depend on mass — The final speed depends only on the height dropped, not on the mass or the shape of the slope.
- Easy : Two smooth slides of equal height give the same speed at the bottom.
- Medium : A heavy and a light ball dropped from the same height reach the ground at the same speed (no air resistance).
- Exam-type : A ball thrown up at 15 m/s rises 11.25 m.
K + U stays constant when no friction acts; what one loses, the other gains.
Thinking that mechanical energy is lost for ever when a pendulum stops. It changes to heat, and the total energy stays constant.
Memory clue: K + U = constant — like a see-saw: when one goes down, the other goes up.
Spot the difference
| Falling ball | KE | PE |
|---|---|---|
| Top, about to fall | Zero | Maximum |
| Halfway down | Some | Some |
| Just before the ground | Maximum | Least |
Practice questions
- 1What is the mechanical energy of an object?
- 2State the law of conservation of mechanical energy.
- 3What is the kinetic energy of a ball at the highest point of its upward throw?
- 4A girl slides down a smooth 5 m slide from rest. Find her speed at the bottom. Take g = 10 m/s².
- 5A 2 kg stone is dropped from 10 m. Find its kinetic energy just before it reaches the ground. Take g = 10 m/s².
- 6Why does a real pendulum slowly come to rest?
- 7A ball is thrown straight up at 15 m/s. Find the maximum height. Take g = 10 m/s² and ignore air resistance.
- 8A 3 kg ball is dropped from 4 m. Find its kinetic energy when it is 1 m above the ground. Take g = 10 m/s².
Show answers (try them yourself first)
- 1The sum of its kinetic and potential energies.
- 2If no friction or air resistance acts, the mechanical energy stays constant.
- 3Zero.
- 410 m/s.
- 5200 J.
- 6Friction and air resistance change some mechanical energy to heat.
- 711.25 m.
- 890 J.
Conservation of mechanical energy
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Open in the appPower
Two students climb the same staircase carrying the same bags, but one runs up and the other walks up slowly.
Power is the rate of doing work: P = W ÷ t. Its SI unit is the watt (W), and 1 W = 1 J per second. Larger units are the kilowatt (1 kW = 1000 W) and the horsepower (1 hp ≈ 746 W). The runner and the walker do the same work, but the runner does it in less time and so has greater power. The work done can be found from W = P × t.
In the figure : Power is work per second, measured in watts.
Rule 1: Same work, less time, more power — Since P = W ÷ t, halving the time doubles the power.
- Easy : A motor doing 600 J in 20 s has a power of 30 W.
- Medium : A machine doing 4500 J in 90 s has a power of 50 W.
- Exam-type : A crane doing 2000 J in 10 s has a power of 200 W.
Rule 2: Work from power and time — W = P × t, so a device of power P running for time t does work P × t.
- Easy : A 40 W device running for 10 s does 400 J.
- Medium : A 60 W bulb lit for 5 minutes uses 18000 J.
- Exam-type : A 3000 W engine running for 2 minutes does 360000 J.
Power is work per second; the same work in less time needs more power.
Confusing work with power. Work is the total done; power is how fast it is done.
Memory clue: P = W ÷ t — power is work per unit time.
Spot the difference
| Quantity | Formula | SI unit |
|---|---|---|
| Work | F × s | joule (J) |
| Power | W ÷ t | watt (W) |
| Kinetic energy | ½ m v² | joule (J) |
Practice questions
- 1Define power.
- 2What is the SI unit of power?
- 3How many watts are in 1 kilowatt?
- 4A motor does 600 J of work in 20 s. Find its power.
- 5A 40 W device runs for 10 s. How much work does it do?
- 6Why does a person running upstairs use more power than one walking up?
- 7A crane lifts a 50 kg load through 4 m in 10 s. Find its power. Take g = 10 m/s².
- 8A pump lifts 200 kg of water through 12 m in 40 s. Find its power. Take g = 10 m/s².
Show answers (try them yourself first)
- 1The rate of doing work.
- 2The watt (W).
- 31000 W.
- 430 W.
- 5400 J.
- 6The work is the same but it is done in less time.
- 7200 W.
- 8600 W.
Simple machines: pulley, inclined plane and lever
A flag goes up a pole by pulling a rope downward, a heavy drum rolls up a plank into a lorry, and a crowbar lifts a stone.
A simple machine makes work easier by changing the size or the direction of the force. The force we apply is the effort and the force we overcome is the load. The mechanical advantage is MA = load ÷ effort. A fixed pulley only changes the direction of the effort, so its MA is 1. An inclined plane of length L and height h has MA = L ÷ h, so a longer ramp needs less force but a longer path. A lever turns about a fixed point called the fulcrum and balances when effort × effort arm = load × load arm. A machine cannot create energy, so it does not reduce the total work.
In the figure : Simple machines change the size or direction of force, not the total work.
Simple machines: pulley, inclined plane and lever
In the app you can move this figure with your finger.
Open in the appSimple machines: pulley, inclined plane and lever
In the app you can move this figure with your finger.
Open in the appSimple machines: pulley, inclined plane and lever
In the app you can move this figure with your finger.
Open in the appRule 1: Less force, more distance — The work is the same, so a smaller effort must move through a larger distance.
- Easy : A 200 N load raised 1 m up a 5 m ramp needs about 40 N, ignoring friction.
- Medium : A ramp 6 m long and 2 m high has MA 3.
- Exam-type : A ramp 130 cm long and 50 cm high has MA 2.6.
Rule 2: The lever law — A lever balances when effort × effort arm = load × load arm.
- Easy : A 120 N load with arms 30 cm (load) and 90 cm (effort) needs 40 N.
- Medium : A 20 kg child at 3 m balances a 30 kg child at 2 m on a see-saw.
- Exam-type : A lever with arms 80 cm and 20 cm has MA 4.
Machines trade force for distance; effort × effort arm = load × load arm for a lever.
Thinking that a machine gives extra work. It only changes the size or direction of the force; no machine creates energy.
Memory clue: Effort × its arm = Load × its arm — a long arm gives a small effort.
Spot the difference
| Machine | What it does | Mechanical advantage |
|---|---|---|
| Fixed pulley | Changes direction of effort | 1 |
| Inclined plane | Longer path, smaller force | L ÷ h |
| Lever | Balances turning effects | Effort arm ÷ load arm |
Practice questions
- 1Define mechanical advantage.
- 2What does a fixed pulley change?
- 3State the law of the lever.
- 4A ramp is 6 m long and 2 m high. Find its mechanical advantage.
- 5A lever has an effort arm of 80 cm and a load arm of 20 cm. Find its mechanical advantage.
- 6Why does a longer ramp need less effort to raise the same load to the same height?
- 7A 120 N load is lifted with a lever whose load arm is 30 cm and effort arm is 90 cm. Find the effort.
- 8A 20 kg child sits 3 m from the fulcrum of a see-saw. Where must a 30 kg child sit to balance it?
Show answers (try them yourself first)
- 1Load divided by effort.
- 2Only the direction of the effort.
- 3Effort × effort arm = load × load arm.
- 43.
- 54.
- 6The work is the same, so a longer distance means a smaller force.
- 740 N.
- 82 m from the fulcrum.