Reflection of light & spherical mirrors
You see your face in a steel plate, and in a shiny spoon the inside shows you upside down while the outside shows you small and upright. Both bounce light back to your eyes; the curve of the surface decides the picture.
Reflection is the bouncing back of light from a polished surface. Laws: (1) the angle of incidence equals the angle of reflection; (2) the incident ray, the normal and the reflected ray lie in one plane. A spherical mirror is a part of a hollow sphere: a concave mirror reflects from the inner curved face, a convex mirror from the outer bulging face.
Equation / formula : angle i = angle r ; R = 2f
In the figure : The focal length f is the distance PF, and the radius R is twice as long.
Rule 1 : Laws of reflection and the plane mirror — Angles are always measured from the normal, not from the surface. A plane mirror makes a virtual, erect image of the same size, as far behind the mirror as the object is in front; left and right appear interchanged (lateral inversion).
- Easy : A ray hits a mirror at 25 degrees to the normal and leaves at 25 degrees.
- Medium : A ray makes 35 degrees with the mirror surface, so its angle of incidence is 90 - 35 = 55 degrees; the angle between incident and reflected rays is 110 degrees.
- For exams : A girl 4 m from a plane mirror walks 1.5 m towards it. She is now 2.5 m away, so her image is 2.5 + 2.5 = 5 m from her.
Rule 2 : Terms of a spherical mirror — The focus F lies midway between P and C, so R = 2f. A concave mirror brings parallel rays together at F; a convex mirror spreads them so that they seem to come from a point F behind the mirror. Distances f and R are measured from the pole.
- Easy : Radius of curvature 30 cm gives focal length 15 cm.
- Medium : A concave mirror has f = 12 cm: its centre of curvature C is 2 x 12 = 24 cm in front. A convex mirror with f = 8 cm has its focus 8 cm behind it.
- For exams : Sunlight focused by a concave mirror makes a bright spot 9 cm away. So f = 9 cm and R = 18 cm.
Never look at the Sun, or a mirror reflecting it, while finding the focal length.
Thinking the centre of curvature is a part of the mirror. It is a point in space, at the centre of the sphere.
Angles from the normal; i = r; R = 2f. Memory clue : "P-F-C": Pole, Focus, Centre. Each step outwards doubles the distance: f, then 2f.
Spot the difference
| Point | Concave mirror | Convex mirror |
|---|---|---|
| Reflecting face | curved inwards | bulges outwards |
| Parallel rays | meet at F in front | spread, seem to come from F behind |
Practice questions
- 1State the two laws of reflection.
- 2What is the radius of curvature of a mirror with focal length 7 cm?
- 3Which spoon surface acts as a concave mirror?
- 4A ray strikes a mirror with angle of incidence 48 degrees. Find the angle between the incident and the reflected ray.
- 5A boy stands 2.5 m from a plane mirror. How far is he from his image?
- 6Why must angles of incidence be measured from the normal?
- 7A concave mirror makes a sharp spot of sunlight 14 cm from it. Find f and R.
- 8Why does a convex mirror never form a spot of burning sunlight on paper?
Show answers (try them yourself first)
- 1Angle i = angle r; incident ray, normal and reflected ray lie in one plane.
- 2R = 2f = 14 cm.
- 3The inner hollow face.
- 448 + 48 = 96 degrees.
- 5Image is 2.5 m behind the mirror: 2.5 + 2.5 = 5 m.
- 6The surface may be curved, but the normal at each point gives a fixed reference line.
- 7f = 14 cm, R = 28 cm.
- 8It spreads parallel rays instead of bringing them together.
Image formation by mirrors & their uses
A torch throws a long beam, a dentist’s mirror makes a tooth look big, and a bus mirror shows the whole road behind. All are curved mirrors; where the object stands decides the picture.
To find an image, draw two rays: one parallel to the axis (reflects through F), and one through C (returns along itself); a ray through F goes out parallel. The image is where the reflected rays meet (real) or seem to meet (virtual). A concave mirror gives real, inverted images for objects beyond F and a virtual, erect, enlarged image inside F; a convex mirror always gives a virtual, erect, smaller image.
Equation / formula : Concave: beyond F real and inverted; inside F virtual, erect, enlarged. Convex: always virtual, erect, diminished.
In the figure : Blue arrow is the object, red arrow the image (dashed means virtual), orange lines are rays. Here the object height is drawn small so the rays fit.
Rule 1 : Image positions for a concave mirror — Object at infinity: image at F, point-sized. Beyond C: between F and C, diminished. At C: at C, same size. Between C and F: beyond C, enlarged. At F: image at infinity. Between P and F: behind the mirror, enlarged and erect. All real images are inverted.
- Easy : A candle 50 cm from a concave mirror of radius 40 cm is beyond C, so its image is between F and C, smaller and upside down.
- Medium : With f = 10 cm, a candle at 15 cm lies between F (10) and C (20), so the image is beyond C, enlarged, real and inverted.
- For exams : For a big real image on a screen, keep the object between F and C. Inside F the image is virtual and cannot be caught on a screen.
Rule 2 : Convex mirror and uses of mirrors — A convex mirror always forms a small, upright, virtual image between P and F, so it shows a wide area: rear-view mirrors, road-bend mirrors. Concave mirrors: torch and headlight (bulb at F gives a parallel beam), shaving and dentist mirrors (object inside F gives an enlarged erect image), solar furnace (sunlight focused at F).
- Easy : A scooter’s side mirror is convex and shows a wide view.
- Medium : Why is the headlight bulb at the focus? Rays from F leave the concave reflector parallel, so the beam travels far without spreading.
- For exams : Which mirror can never form a real image? The convex mirror. Which gives a magnified erect image? A concave mirror with the object inside F.
A real image can be caught on a screen; a virtual image cannot.
Saying a concave mirror always gives a real image. Inside F it gives a virtual, enlarged image.
Concave: beyond F real, inside F virtual. Convex: always virtual and small. Memory clue : "Real = Reversed": real images are upside down, virtual ones are upright.
Spot the difference
| Point | Concave mirror | Convex mirror |
|---|---|---|
| Image | real or virtual | always virtual |
| Typical use | torch, shaving mirror, solar furnace | rear-view mirror |
Practice questions
- 1Where is the image when the object is at infinity in front of a concave mirror?
- 2Name two uses of concave mirrors.
- 3Why is a convex mirror used as a rear-view mirror?
- 4A concave mirror has f = 18 cm. An object is 50 cm away. Is it beyond C, between C and F, or inside F?
- 5Describe the image when an object is placed at C of a concave mirror.
- 6A dentist wants an enlarged erect view of a tooth. Where must the tooth be relative to the mirror?
- 7A concave mirror forms a real image on a screen. Can the object be inside F? Explain.
- 8A student says "a convex mirror gave a magnified image". Is this possible? Explain.
Show answers (try them yourself first)
- 1At the focus F, highly diminished, real and inverted.
- 2Torch or headlight reflector, shaving mirror, dentist mirror, solar furnace (any two).
- 3It gives a wide field of view and an erect image.
- 4C is at 36 cm, so 50 cm is beyond C.
- 5At C, real, inverted, same size as the object.
- 6Between the pole and the focus (inside f).
- 7No. Inside F the image is virtual, so it cannot form on a screen; the object must be beyond F.
- 8No. A convex mirror always gives a diminished image; the student may have used a concave mirror.
Sign convention, mirror formula & magnification
On a number line, steps to the right are plus and steps to the left are minus. In optics we do the same from the mirror, so the sign of an answer tells you at once which side the image is on.
New Cartesian sign convention: the pole is the origin; light travels left to right (+); distances against the light are negative; heights above the axis are positive. The object is always on the left, so u is negative; f is negative for a concave and positive for a convex mirror. Mirror formula: 1/v + 1/u = 1/f. Magnification: m = h'/h = -v/u.
Equation / formula : 1/v + 1/u = 1/f ; m = h'/h = -v/u
In the figure : Always write the signs first and only then put the numbers in the formula.
Rule 1 : Using the mirror formula — Write u and f with signs, then 1/v = 1/f - 1/u. A negative v means a real image in front of the mirror; a positive v means a virtual image behind it.
- Easy : Concave, f = -10 cm, u = -30 cm: 1/v = -1/10 + 1/30 = -2/30, so v = -15 cm (real, in front).
- Medium : Concave, f = -10 cm, u = -6 cm: 1/v = -1/10 + 1/6 = 2/30, so v = +15 cm (virtual, behind the mirror).
- For exams : Convex, f = +24 cm, u = -24 cm: 1/v = 1/24 + 1/24 = 1/12, so v = +12 cm and m = +0.5.
Rule 2 : Reading the magnification — m = h'/h = -v/u. A negative m means a real, inverted image; a positive m means a virtual, erect image. If the number part is more than 1 the image is enlarged; less than 1, diminished; exactly 1, same size.
- Easy : Object 4 cm tall and m = -2: the image is 8 cm tall and inverted.
- Medium : u = -20 cm and v = +10 cm: m = -10/(-20) = +0.5, a virtual, erect image half the size; 1/f = 1/10 - 1/20 gives f = +20 cm, a convex mirror.
- For exams : Which mirror can give m = +2? A concave mirror with the object inside F; a convex mirror only gives m between 0 and 1.
The object distance u is always negative for a real object in front of the mirror.
Writing u = +30 cm for an object in front of the mirror. This flips every answer.
u always -; concave f -; convex f +; negative v = real. Memory clue : "Cave goes down, so concave f is minus; convex has a plus bump."
Spot the difference
| Point | Real image | Virtual image |
|---|---|---|
| Sign of v | negative (in front) | positive (behind) |
| Sign of m | negative, inverted | positive, erect |
Practice questions
- 1Write the mirror formula and the formula for magnification.
- 2What is the sign of f for a concave mirror, and why?
- 3What does a negative magnification tell you about the image?
- 4A concave mirror has f = -15 cm and the object is at u = -30 cm. Find v and m.
- 5A convex mirror has f = +20 cm and the object is 60 cm in front. Find v and m.
- 6An object 6 cm tall gives m = -0.5. Find the image height and describe it.
- 7A concave mirror forms a real image 40 cm in front of it for an object 20 cm in front. Find f and m.
- 8A mirror forms a virtual image 9 cm behind it for an object 18 cm in front. Is it concave or convex? Find f.
Show answers (try them yourself first)
- 11/v + 1/u = 1/f ; m = -v/u.
- 2Negative, because its focus lies in front, against the direction of the light.
- 3The image is real and inverted.
- 41/v = -1/15 + 1/30 = -1/30, so v = -30 cm; m = -1 (object at C, same size, inverted).
- 51/v = 1/20 + 1/60 = 4/60, so v = +15 cm; m = -15/(-60) = +0.25.
- 6Height = -0.5 x 6 = -3 cm: 3 cm tall, inverted and real.
- 71/f = -1/40 - 1/20 = -3/40, so f is about -13.3 cm; m = -(-40)/(-20) = -2.
- 81/f = 1/9 - 1/18 = 1/18, so f = +18 cm: a convex mirror.
Refraction of light & refractive index
A spoon in a glass of tea looks bent at the surface, and a clear pond looks shallower than it is. Light changes speed when it passes from water to air, and so it changes direction.
Refraction is the bending of light when it goes obliquely from one transparent medium to another, because its speed changes. Going into a denser medium it bends towards the normal; into a rarer medium, away. Laws: the incident ray, refracted ray and normal lie in one plane, and sin i / sin r is constant (Snell’s law). The refractive index n = c / v, where c = 3 x 10^8 m/s is the speed of light in vacuum.
Equation / formula : sin i / sin r = n ; n = c / v
In the figure : The change of speed at the boundary is the only reason light bends.
Refraction of light & refractive index
In the app you can move this figure with your finger.
Open in the appRule 1 : Direction of bending and the glass slab — Rarer to denser: towards the normal, angle of refraction smaller than angle of incidence. Denser to rarer: away from the normal. A ray along the normal does not bend. In a rectangular glass slab the ray bends towards the normal on entering and away on leaving by the same amount, so the emergent ray is parallel to the incident ray but shifted sideways (lateral displacement); a thicker slab shifts it more.
- Easy : Light going from air into water bends towards the normal.
- Medium : A ray enters a glass slab at 40 degrees and leaves at 40 degrees, shifted sideways but parallel to the first ray.
- For exams : A ray entering a slab along the normal passes straight, with no bending and no lateral shift.
Rule 2 : Refractive index and optical density — n = c / v, so a larger n means slower light and an optically denser medium. n is never less than 1. For two media, n21 = v1 / v2 = n2 / n1. Optical density is not the same as mass density, and the frequency of light does not change on refraction.
- Easy : n = 1.5 gives v = 3 x 10^8 / 1.5 = 2 x 10^8 m/s.
- Medium : Light moves at 2.5 x 10^8 m/s in a liquid, so n = 3 x 10^8 / 2.5 x 10^8 = 1.2.
- For exams : Kerosene (n = 1.44) floats on water (n = 1.33) yet is optically denser: light travels at about 2.08 x 10^8 m/s in kerosene and 2.26 x 10^8 m/s in water.
Light always travels fastest in vacuum, about 3 x 10^8 m/s.
Thinking a medium that is heavier is always optically denser. The two are different properties.
Denser means slower, and slower means bends towards the normal. Memory clue : "Slow = Towards": into a slower medium the ray bends Towards the normal.
Spot the difference
| Point | Rarer to denser | Denser to rarer |
|---|---|---|
| Speed of light | decreases | increases |
| Bending | towards the normal | away from the normal |
Practice questions
- 1Define refraction of light.
- 2Light goes from air into water. Does it bend towards or away from the normal?
- 3Which is optically denser: a medium with n = 1.33 or one with n = 1.5?
- 4The refractive index of diamond is 2.4. Find the speed of light in it.
- 5Light moves at 2.4 x 10^8 m/s in a liquid. Find its refractive index.
- 6Why does a swimming pool look shallower than it really is?
- 7A ray enters a rectangular glass slab at 35 degrees. What is the angle of emergence, and why is the ray shifted?
- 8Light goes from medium A (n = 1.2) to medium B (n = 1.8). Does it bend towards or away from the normal? Find n of B with respect to A.
Show answers (try them yourself first)
- 1The change in direction of light when it passes obliquely from one transparent medium to another.
- 2Towards the normal, because water is denser.
- 3The one with n = 1.5.
- 4v = 3 x 10^8 / 2.4 = 1.25 x 10^8 m/s.
- 5n = 3 / 2.4 = 1.25.
- 6Light from the bottom bends away from the normal at the surface, so the bottom appears nearer.
- 735 degrees; the two bends at the two faces are equal and opposite, but the ray moves along a slanted path inside the slab.
- 8Towards the normal, since B is denser; n of B with respect to A = 1.8 / 1.2 = 1.5.
Lenses, lens formula & power
A magnifying glass makes small print look big, a camera focuses a scene on its sensor, and spectacles help weak eyes. All use lenses, which bend light with two curved faces.
A lens is a transparent material bounded by two spherical surfaces. A convex lens (thicker in the middle) converges light; a concave lens (thinner in the middle) diverges it. A ray through the optical centre O goes straight; a lens has two foci F1 and F2. Lens formula: 1/v - 1/u = 1/f; magnification: m = v/u; power: P = 1/f with f in metres, measured in dioptre (D).
Equation / formula : 1/v - 1/u = 1/f ; m = v/u ; P = 1/f
In the figure : The ray through O goes straight; the ray parallel to the axis bends through F2 (convex) or seems to come from F1 (concave).
Lenses, lens formula & power
In the app you can move this figure with your finger.
Open in the appRule 1 : Image positions for a convex lens — Object at infinity: image at F2, point-sized. Beyond 2F1: between F2 and 2F2, diminished. At 2F1: at 2F2, same size. Between F1 and 2F1: beyond 2F2, enlarged. At F1: image at infinity. Between F1 and O: virtual, erect, enlarged on the same side (magnifying glass). A concave lens always gives a virtual, erect, smaller image between O and F1.
- Easy : An object at 2F1 gives an image at 2F2, real, inverted and the same size.
- Medium : f = 12 cm and u = -36 cm: 1/v = 1/12 - 1/36 = 2/36, so v = +18 cm and m = 18/(-36) = -0.5 (diminished, real, inverted).
- For exams : For an enlarged real image keep the object between F1 and 2F1. To use the lens as a magnifying glass, keep the object between F1 and O.
Rule 2 : Lens formula and power — Signs: u is negative, f is positive for a convex and negative for a concave lens. Use 1/v = 1/f + 1/u. Power P = 1/f (f in metres): positive for convex, negative for concave; 1 dioptre is the power of a lens of focal length 1 m. The powers of lenses in contact add.
- Easy : f = 0.25 m gives P = 1/0.25 = +4 D.
- Medium : Lenses of +3.5 D and -1.5 D in contact give +2 D, so f = 1/2 = 0.5 m = 50 cm.
- For exams : Concave lens, f = -10 cm, u = -30 cm: 1/v = -1/10 - 1/30 = -4/30, so v = -7.5 cm and m = (-7.5)/(-30) = +0.25: virtual, erect, diminished.
Always change the focal length into metres before finding power in dioptre.
Using the mirror formula 1/v + 1/u = 1/f for a lens. For a lens it is 1/v - 1/u = 1/f.
Lens: 1/v - 1/u = 1/f, m = v/u. Convex +, concave -. Memory clue : "Mirror has a minus in m; lens has a minus in the formula."
Spot the difference
| Point | Convex lens | Concave lens |
|---|---|---|
| Shape and effect | thick middle, converges | thin middle, diverges |
| f and power | positive | negative |
Practice questions
- 1Which lens is thicker in the middle than at the edges?
- 2What is the sign of the focal length of a concave lens?
- 3Define one dioptre.
- 4A convex lens has f = 20 cm and the object is 30 cm away. Find v and m.
- 5Find the power of a concave lens of focal length 40 cm.
- 6Two lenses of power +4.5 D and -2 D are in contact. Find the combined power.
- 7A convex lens has f = 15 cm and the object is at 10 cm. Find v and describe the image.
- 8A concave lens has f = -20 cm and the object is 20 cm away. Find v and m.
Show answers (try them yourself first)
- 1The convex lens.
- 2Negative.
- 3The power of a lens of focal length 1 metre.
- 41/v = 1/20 - 1/30 = 1/60, so v = +60 cm; m = 60/(-30) = -2.
- 5f = -0.4 m, so P = 1/(-0.4) = -2.5 D.
- 64.5 + (-2) = +2.5 D.
- 71/v = 1/15 - 1/10 = -1/30, so v = -30 cm: virtual, erect, enlarged 3 times.
- 81/v = -1/20 - 1/20 = -1/10, so v = -10 cm; m = (-10)/(-20) = +0.5.