Purifying solids: filtration
A tea strainer separates leaves from liquid; the lab does the same with filter paper.
Filtration separates insoluble solid from a liquid using filter paper. Suction filtration uses a Büchner funnel and pump for speed and a drier residue.
In the figure : Filtration.
Rule 1: Simple filtration — A folded filter paper in a funnel; insoluble impurity stays as residue and liquid passes as filtrate.
- Easy : Filtering muddy water.
- Medium : Powder + water.
- Exam-type : Dry the residue.
Rule 2: Suction filtration — Büchner funnel, suction flask and pump; fine particles are filtered fast and air pulls the residue dry.
- Easy : Collecting crystals.
- Medium : Minutes instead of hours.
- Exam-type : Reduced pressure in the flask.
Rule 3: Limits — Separates only insoluble solids; soluble mixtures need distillation or crystallisation.
- Easy : Salt in water cannot be filtered out.
- Medium : Sand + salt: filter, then evaporate.
- Exam-type : Only suspended particles are removed.
Calculation: residue percentage
- Step 1: 10.0 g of mixture is filtered.
- Step 2: Dry residue 3.2 g.
- Step 3: 3.2 ÷ 10.0 × 100 = 32 %.
CET level (MCQ)
- CET 1) For suction filtration? 1) Büchner funnel 2) separating funnel 3) condenser 4) column — Answer: 1).
- CET 2) A dissolved solid is recovered by? 1) filtering 2) evaporation 3) sieving 4) hand — Answer: 2).
Real-life use: Water treatment, lab preparation.
Filtration = insoluble; suction = fast and dry.
Thinking dissolved salt can be filtered out.
Wet the filter paper first in suction filtration.
Memory clue: "filter = solids, distil = liquids".
Spot the difference
| Method | Speed | Residue |
|---|---|---|
| Simple | slow | wet |
| Suction | fast | drier |
Practice questions
- 1What is filtration?
- 2Why suction filtration?
- 3What is a residue?
- 4What is the filtrate?
- 5How separate salt from water?
- 63.2 g residue in 10 g ⇒ %?
- 7Separating sand and salt?
- 8Use of a Büchner funnel?
Show answers (try them yourself first)
- 1Separating insoluble particles.
- 2Speed and drier residue.
- 3Solid left on the paper.
- 4The liquid passing through.
- 5Evaporation or distillation.
- 632 %.
- 7Filter, then evaporate.
- 8Suction filtration.
Crystallisation and fractional crystallisation
Rock candy forms as hot sugar solution cools slowly; that is crystallisation.
Crystallisation obtains pure crystals from a hot saturated solution on cooling. Fractional crystallisation separates two solutes by their solubility difference, one after the other.
In the figure : Solubility curves.
Rule 1: Steps — Dissolve in hot solvent ⇒ saturate ⇒ filter hot ⇒ cool slowly ⇒ filter and dry the crystals.
- Easy : Impure sugar ⇒ pure.
- Medium : Alum crystals.
- Exam-type : Slow cooling ⇒ large crystals.
Rule 2: Solubility and yield — Yield = hot solubility − cold solubility (per 100 g solvent).
- Easy : 80 g (373 K), 20 g (293 K) ⇒ 60 g crystals.
- Medium : Steeper curve ⇒ larger yield.
- Exam-type : Flat curve ⇒ small yield.
Rule 3: Fractional crystallisation — Two solutes with different solubility: the less soluble crystallises first; repeat to separate fully.
- Easy : KNO₃ + NaCl: cool ⇒ KNO₃ crystals.
- Medium : NaCl stays in solution.
- Exam-type : The mother liquor remains.
Calculation: yield
- Step 1: 100 g water dissolves 80 g at 373 K.
- Step 2: Only 20 g stays at 293 K.
- Step 3: Crystals = 80 − 20 = 60 g.
CET level (MCQ)
- CET 1) Crystallisation depends on? 1) boiling point 2) solubility 3) density 4) colour — Answer: 2).
- CET 2) Large crystals come from? 1) fast cooling 2) slow cooling 3) stirring 4) boiling — Answer: 2).
Real-life use: Purifying sugar, salt and drugs.
Hot saturated ⇒ cool ⇒ crystals; slow = large.
Expecting large crystals from rapid cooling.
Crystallisation purifies; the fractional version separates.
Memory clue: "dissolve hot, crystallise cold".
Spot the difference
| Item | Simple | Fractional |
|---|---|---|
| Solutes | one | two |
| Basis | solubility | solubility gap |
Practice questions
- 1What is crystallisation?
- 2State the steps.
- 3Why cool slowly?
- 480 g / 20 g ⇒ yield?
- 5What is fractional?
- 6How separate KNO₃ and NaCl?
- 7What is mother liquor?
- 8How are crystals dried?
Show answers (try them yourself first)
- 1Getting pure crystals from solution.
- 2Dissolve, filter, cool, filter.
- 3Large pure crystals.
- 460 g.
- 5Separation by solubility difference.
- 6Cool and collect KNO₃.
- 7Liquid left after crystallising.
- 8Press between filter papers or air-dry.
Simple distillation
Rain comes from water vapour cooling to liquid; distillation does the same on a bench.
Distillation boils a liquid and condenses the vapour to collect the pure liquid. Simple distillation works when the boiling points differ widely (rule of thumb: more than about 40 K) or the impurity is non-volatile.
In the figure : Simple distillation.
Rule 1: Apparatus — Flask ⇒ thermometer ⇒ condenser (water in at the bottom, out at the top) ⇒ receiver. Add boiling chips.
- Easy : The condenser jacket stays full.
- Medium : The thermometer bulb sits at the side arm.
- Exam-type : Chips keep boiling smooth.
Rule 2: When to use — Non-volatile impurities (seawater) or a wide boiling-point gap.
- Easy : Seawater ⇒ pure water.
- Medium : CHCl₃ (334 K) + aniline (457 K).
- Exam-type : Salt water.
Rule 3: Principle — The lower-boiling component vaporises first; a pure liquid boils at a constant temperature.
- Easy : Pure water holds 373 K.
- Medium : A changing temperature ⇒ a mixture.
- Exam-type : First fraction = lower boiling point.
Reasoning: why do CHCl₃ and aniline separate?
- Step 1: Boiling points 334 K and 457 K.
- Step 2: Gap = 123 K, very large ⇒ simple distillation is enough.
- Step 3: Simple distillation suffices; CHCl₃ distils first.
CET level (MCQ)
- CET 1) Water enters the condenser from? 1) top 2) bottom 3) both 4) none — Answer: 2).
- CET 2) How do you separate two miscible liquids with close boiling points? 1) fractional distillation 2) simple distillation 3) filtration 4) crystallisation — Answer: 1).
Real-life use: Drinking water, spirit purification.
Simple: a wide b.p. gap; condenser water from the bottom.
Feeding water from the top; the jacket does not fill.
Place the thermometer bulb at the vapour side arm.
Memory clue: "in at the bottom, out at the top".
Spot the difference
| Method | b.p. gap |
|---|---|
| Simple | wide |
| Fractional | small |
Practice questions
- 1What is distillation?
- 2When use simple distillation?
- 3Which way does water flow?
- 4Why boiling chips?
- 5CHCl₃ + aniline?
- 6Which fraction first?
- 7Temperature of a pure liquid?
- 8Purifying seawater?
Show answers (try them yourself first)
- 1Boil and condense vapour.
- 2A wide b.p. gap.
- 3From the bottom.
- 4To smooth boiling.
- 5Simple distillation.
- 6The lower-boiling one.
- 7Constant.
- 8Distillation.
Fractional, reduced-pressure and steam distillation
Petrol, diesel and kerosene come from crude oil as fractions, again by distillation.
Fractional: boiling points close together (small gap), with a fractionating column. Reduced pressure: high-boiling or decomposing liquids. Steam: immiscible liquids that carry over with steam.
In the figure : Fractional, reduced pressure, steam.
Rule 1: Fractional distillation — Repeated vaporisation-condensation in the column; the lower-boiling liquid collects at the top.
- Easy : Benzene (353 K) + toluene (384 K).
- Medium : Crude oil fractions.
- Exam-type : Liquid air.
Rule 2: Reduced pressure — Lower pressure ⇒ lower boiling point ⇒ no decomposition. Glycerol decomposes at 563 K ⇒ distil near 453 K under reduced pressure.
- Easy : Glycerol.
- Medium : Sugar syrups.
- Exam-type : Heat-labile drugs.
Rule 3: Steam distillation — Immiscible liquid + water ⇒ total vapour pressure is the sum ⇒ boiling below 373 K.
- Easy : Aniline.
- Medium : Clove and eucalyptus oil.
- Exam-type : Natural fragrances.
Reasoning: why boil below 373 K in steam distillation?
- Step 1: Two immiscible liquids ⇒ P(total) = P₁ + P₂.
- Step 2: Boiling starts when P(total) equals atmospheric pressure.
- Step 3: Each pressure is below atmospheric ⇒ temperature stays under 373 K.
CET level (MCQ)
- CET 1) To purify glycerol? 1) simple 2) reduced pressure 3) filtration 4) extraction — Answer: 2).
- CET 2) Aniline is purified by? 1) steam distillation 2) crystallisation 3) filtration 4) chromatography — Answer: 1).
Real-life use: Petroleum refining, essential oils.
Fractional = close b.p.; reduced pressure = decomposing; steam = immiscible.
Treating all three as the same case.
Reduced pressure lowers the boiling point, never raises it.
Memory clue: "small gap ⇒ column; heat-sensitive ⇒ low pressure".
Spot the difference
| Type | When |
|---|---|
| Fractional | close b.p. |
| Reduced pressure | decomposes |
| Steam | immiscible |
Practice questions
- 1When use fractional distillation?
- 2Why reduced pressure for glycerol?
- 3What is steam distillation?
- 4One example of each.
- 5How is crude oil separated?
- 6Function of the column?
- 7Why below 373 K?
- 8Boiling point of aniline?
Show answers (try them yourself first)
- 1Boiling points close together.
- 2It decomposes at 563 K.
- 3Collecting an immiscible liquid with steam.
- 4Benzene–toluene, glycerol, aniline.
- 5Fractional distillation.
- 6Repeated vaporisation-condensation.
- 7Total pressure equals atmospheric.
- 8457 K.
Solvent extraction
In tea making the colour moves from leaves into water — a solvent pulling out a component.
Extraction moves a compound from one solvent into another immiscible one. K = C(organic) ÷ C(aqueous).
In the figure : Extraction.
Rule 1: Principle — Distribution law: K is constant at a fixed temperature. Organic compounds dissolve more in ether.
- Easy : K = 4 ⇒ ether holds 4×.
- Medium : Shake in a separating funnel.
- Exam-type : Let layers settle.
Rule 2: Once or many times — Fraction left = [V ÷ (V + Kv)]ⁿ; several small portions extract more.
- Easy : 1 × 50 mL ⇒ 66.7 %.
- Medium : 2 × 25 mL ⇒ 75 %.
- Exam-type : 4 × 12.5 mL ⇒ 80 %.
Rule 3: Procedure — Aqueous solution + ether ⇒ shake ⇒ separate ⇒ evaporate the ether ⇒ compound. Ether is flammable: no flame.
- Easy : Caffeine.
- Medium : Medicinal oils.
- Exam-type : Benzoic acid.
Calculation: 100 mL aqueous, K = 4, 50 mL ether
- Step 1: Left = V ÷ (V + Kv) = 100 ÷ (100 + 200) = 0.333.
- Step 2: Extracted = 66.7 %.
- Step 3: 2 × 25 mL ⇒ left (100 ÷ 200)² = 0.25 ⇒ 75 %.
CET level (MCQ)
- CET 1) Apparatus for extraction? 1) separating funnel 2) condenser 3) Büchner 4) column — Answer: 1).
- CET 2) More efficient? 1) one large 2) several small 3) same 4) none — Answer: 2).
Real-life use: Caffeine extraction, herbal medicine.
K = C(org)/C(aq); several small portions.
Using miscible solvents.
For equal total solvent, many small portions extract more.
Memory clue: "little and often".
Spot the difference
| Method | % extracted |
|---|---|
| 1 × 50 mL | 66.7 |
| 2 × 25 mL | 75 |
| 4 × 12.5 mL | 80 |
Practice questions
- 1What is extraction?
- 2What is K?
- 3K = 4, 50 mL ether ⇒ %?
- 42 × 25 mL ⇒ %?
- 5Why several times?
- 6Safety with ether?
- 7One example.
- 8Why immiscible?
Show answers (try them yourself first)
- 1Moving between solvents.
- 2C(organic)/C(aqueous).
- 366.7 %.
- 475 %.
- 5Less is left.
- 6Flammable.
- 7Caffeine from tea.
- 8To give two separable layers.
Chromatography: principle and adsorption
A drop of ink spreading on wet paper separates colours by distance — that is chromatography.
Chromatography separates a mixture by its distribution between a stationary and a mobile phase; components move at different rates.
In the figure : Chromatography.
Rule 1: Adsorption chromatography — Stationary phase Al₂O₃ or silica gel; components adsorb with different strengths ⇒ different speeds.
- Easy : Weakly adsorbed ⇒ elutes first.
- Medium : Al₂O₃ column.
- Exam-type : TLC: thin layer.
Rule 2: Column and TLC — Column: adsorbent in a tube, mixture on top, solvent flows ⇒ bands. TLC: thin layer on a plate, small spot.
- Easy : Separating pigments.
- Medium : TLC is fast, needs little sample.
- Exam-type : Collect components separately.
Rule 3: Uses — Dyes, drug purity, pesticide residue and forensic analysis.
- Easy : Spinach pigments.
- Medium : Drug purity.
- Exam-type : Ink analysis.
Reasoning: why does the weakly adsorbed one elute first?
- Step 1: A component distributes between adsorbent and solvent.
- Step 2: Weaker adsorption ⇒ more time in the solvent.
- Step 3: It moves faster ⇒ comes out first.
CET level (MCQ)
- CET 1) A stationary phase? 1) Al₂O₃ 2) solvent 3) gas 4) air — Answer: 1).
- CET 2) A strongly adsorbed component moves? 1) first 2) slowly 3) equally 4) never — Answer: 2).
Real-life use: Pigment analysis, pharmaceuticals.
Stationary + mobile; stronger adsorption ⇒ slower.
Calling the solvent the stationary phase.
In TLC keep the spot above the solvent level.
Memory clue: "sticky = slow, free = fast".
Spot the difference
| Phase | Example |
|---|---|
| Stationary | Al₂O₃, silica |
| Mobile | solvent |
Practice questions
- 1What is chromatography?
- 2Example of a stationary phase.
- 3What is TLC?
- 4Which elutes first?
- 5Two uses.
- 6How is a column set up?
- 7The mobile phase?
- 8Why do components separate?
Show answers (try them yourself first)
- 1Separation by distribution between phases.
- 2Al₂O₃ or silica gel.
- 3Thin-layer chromatography.
- 4The weakly adsorbed.
- 5Dye analysis, drug purity.
- 6Pack adsorbent in a tube.
- 7The flowing solvent.
- 8Different adsorption strengths.
Partition (paper) chromatography and Rf
On filter paper, ink separates into colour rings; each colour has its own Rf.
Paper chromatography: water held in the paper is the stationary phase and an organic solvent is mobile. Rf = distance moved by the solute ÷ distance moved by the solvent.
In the figure : Paper chromatography, Rf.
Rule 1: Partition principle — A solute partitions between water (stationary) and organic solvent (mobile); more soluble in the solvent ⇒ moves farther.
- Easy : Separating amino acids.
- Medium : Pigments.
- Exam-type : Sugar types.
Rule 2: Rf calculation — Rf < 1; fixed for a compound under fixed solvent, temperature and paper.
- Easy : A: 2.0 ÷ 8 = 0.25.
- Medium : B: 5.2 ÷ 8 = 0.65.
- Exam-type : Higher Rf ⇒ more soluble in the mobile phase.
Rule 3: Locating spots — Coloured spots directly; for invisible ones use ninhydrin (amino acids), iodine vapour or UV.
- Easy : Ninhydrin ⇒ purple.
- Medium : Iodine ⇒ brown spots.
- Exam-type : UV lamp.
Calculation: Rf
- Step 1: Solvent front = 8.0 cm.
- Step 2: B spot = 5.2 cm.
- Step 3: Rf = 5.2 ÷ 8.0 = 0.65.
CET level (MCQ)
- CET 1) Rf is? 1) > 1 2) < 1 3) = 1 4) negative — Answer: 2).
- CET 2) Reagent for amino acids? 1) ninhydrin 2) iodine 3) Fehling 4) Tollens — Answer: 1).
Real-life use: Drug purity, food-colour testing.
Rf = d(solute) ÷ d(solvent) < 1.
Expecting an Rf above 1; it cannot happen.
Measure from the start line, not the paper edge.
Memory clue: "Rf = solute ÷ solvent".
Spot the difference
| Spot | Distance | Rf |
|---|---|---|
| A | 2.0 cm | 0.25 |
| B | 5.2 cm | 0.65 |
Practice questions
- 1What is Rf?
- 2Why is Rf never above 1?
- 32.0 cm, 8 cm ⇒ Rf?
- 4Stationary phase in paper?
- 5How to see invisible spots?
- 6What does a high Rf mean?
- 7What is the solvent front?
- 8What does Rf depend on?
Show answers (try them yourself first)
- 1Solute distance ÷ solvent distance.
- 2A solute never outruns the solvent.
- 30.25.
- 4Water held in the paper.
- 5Ninhydrin, iodine, UV.
- 6More soluble in the solvent.
- 7The line the solvent reached.
- 8Solvent, temperature, paper.
Quick revision of the whole lesson
| Concept | Key formula / fact |
|---|---|
| Filtration | insoluble solid |
| Crystallisation | solubility gap |
| Simple distillation | large Δbp |
| Fractional | small Δbp |
| Reduced pressure | glycerol |
| Steam | aniline |
| Extraction | K = C(org)/C(aq) |
| Rf | d(solute)/d(solvent) |
🚀 Quick revision of the whole lesson
In the app you can move this figure with your finger.
Open in the app🎯 Most important points for the exam
- Filtration.
- Crystallisation.
- Simple distillation.
- Fractional, reduced, steam.
- Extraction.
- Chromatography.
- Paper chromatography, Rf.
understand the idea → remember the formula → solve the example → solve problems yourself.