Perimeter of plane shapes
A farmer needs wire to go once round a field. The wire length is the perimeter, the distance round the boundary.
Perimeter is the total length of the boundary. Rectangle: 2(l + b). Square: 4a. Triangle: sum of sides. Regular polygon: n × side.
Formula: Rectangle 2(l + b); square 4a; unit: cm, m
In the figure: A rectangle 8 by 5 has perimeter 2(8 + 5) = 26 units.
Rule 1: Find the perimeter — Add all outer sides; use the formula for rectangles and squares.
- Easy: Square side 9 cm: 36 cm.
- Medium: Triangle 5, 12, 13: 30.
- Exam-type: Regular hexagon, side 4: 24.
Rule 2: Work backwards — Divide the perimeter by the number of equal sides, or use P = 2(l + b) to find a side.
- Easy: Square perimeter 48: side 12.
- Medium: Rectangle P = 30, l = 9: b = 6.
- Exam-type: Fence 100 m around a square field: side 25 m.
Perimeter is a length (cm, m), not an area.
Using only l + b for a rectangle and forgetting to double.
"Walk all the way round."
Practice questions
- 1A rectangle is 28 cm long and 14 cm wide. Find its perimeter.
- 2A rectangle is 20 cm long and 18 cm wide. Find its perimeter.
- 3The perimeter of a square is 40 cm. What is the length of its side?
- 4The perimeter of a rectangle is 60 cm and its length is 15 cm. Find its width.
- 5The perimeter of a rectangle is 84 cm and its length is 21 cm. Find its width.
- 6A regular pentagon has each side 12 cm. Find its perimeter.
- 7A regular octagon has each side 10 cm. Find its perimeter.
- 8The length of a rectangle is 8 cm more than twice its width, and its perimeter is 124 cm. Find its width.
Show answers (try them yourself first)
- 184 cm
- 276 cm
- 310 cm
- 415 cm
- 521 cm
- 660 cm
- 780 cm
- 818 cm
Circumference of a circle and π
Roll a coin once along a ruler: it covers about 3.14 times its width. That ratio is the same for every circle.
The distance round a circle is its circumference C. The ratio C/d is the same for all circles and is called π (≈ 22/7 or 3.14). So C = πd = 2πr.
Formula: C = 2πr = πd; π ≈ 22/7 ≈ 3.14
In the figure: With diameter d the circle has circumference πd, a little over 3 diameters.
Rule 1: Find C — Use 22/7 when the radius is a multiple of 7; otherwise 3.14.
- Easy: r = 7: C = 2 × 22/7 × 7 = 44.
- Medium: d = 10: C = 31.4 (π = 3.14).
- Exam-type: r = 3.5: C = 22.
Rule 2: Find r from C or wheel turns — r = C/(2π). Distance = turns × circumference.
- Easy: C = 88: r = 14.
- Medium: Wheel C = 2 m, 50 turns: 100 m.
- Exam-type: Wire of 44 cm bent into a circle: r = 7 cm.
π is irrational: 22/7 and 3.14 are only approximations.
Using the radius in C = πd without doubling it.
"Circle edge = pi times diameter."
Practice questions
- 1For every circle, the ratio of the circumference to the diameter is the same number, called
- 2The circumference of a circle of radius r is
- 3π is
- 4Find the circumference of a circle of radius 56 cm. (Take π = 22/7.)
- 5Find the circumference of a circle of radius 28 cm. (Take π = 22/7.)
- 6Find the circumference of a circle of radius 49 cm. (Take π = 22/7.)
- 7Find the circumference of a circle of radius 14 cm. (Take π = 22/7.)
- 8Find the circumference of a circle of diameter 21 cm. (Take π = 22/7.)
Show answers (try them yourself first)
- 1π
- 22πr
- 3an irrational number, about 3.14159
- 4352 cm
- 5176 cm
- 6308 cm
- 788 cm
- 866 cm
Length of an arc
A pizza slice has a curved crust. Its crust is a fraction of the full circle edge, the same fraction as the angle at the tip is of 360°.
An arc making angle θ at the centre has length (θ/360) × 2πr. Perimeter of a sector = arc + 2r.
Formula: l = (θ/360) × 2πr
In the figure: θ = 60° is one sixth of the whole circle, so the arc is 1/6 of the circumference.
Rule 1: Arc length — Take the fraction θ/360 of the full circumference.
- Easy: r = 7, θ = 90°: (1/4) × 44 = 11.
- Medium: r = 21, θ = 60°: (1/6) × 132 = 22.
- Exam-type: Semicircle r = 14: 44.
Rule 2: Find the angle or radius — Rearrange: θ = l × 360 / (2πr).
- Easy: Arc 11, r = 7: θ = 90°.
- Medium: Sector perimeter: arc 11 + 2 × 7 = 25.
- Exam-type: Arc 22, θ = 180°: r = 7.
A bigger angle at the centre means a longer arc, for the same radius.
Forgetting to add the two radii when asked for the perimeter of a sector.
"Slice fraction times the whole edge."
Practice questions
- 1A semicircular arc is what fraction of the full circumference?
- 2What fraction of the full circumference is an arc that subtends 72° at the centre?
- 3What fraction of the full circumference is an arc that subtends 45° at the centre?
- 4What fraction of the full circumference is an arc that subtends 90° at the centre?
- 5What fraction of the full circumference is an arc that subtends 270° at the centre?
- 6The length of an arc that subtends θ° at the centre of a circle of radius r is
- 7A quarter-circle arc has radius 7 cm. Find its length. (Take π = 22/7.)
- 8A quarter-circle arc has radius 14 cm. Find its length. (Take π = 22/7.)
Show answers (try them yourself first)
- 1one half
- 20.2
- 30.125
- 40.25
- 50.75
- 6(θ/360) × 2πr
- 711 cm
- 822 cm
Area of rectangles and parallelograms
Tiles needed to cover a floor depend on its area, the number of unit squares inside.
Area measures the surface inside a shape in square units. Rectangle l × b; square a²; parallelogram base × height (height is the perpendicular distance, not the slanted side).
Formula: Rectangle l × b; square a²; parallelogram b × h
In the figure: The slanted side is not the height; the dashed perpendicular h is.
Rule 1: Find the area — Multiply the two perpendicular measures.
- Easy: Rectangle 12 × 5 = 60 sq units.
- Medium: Parallelogram b = 10, h = 6: 60.
- Exam-type: Square side 7: 49.
Rule 2: Compare and convert — Same base and same height give equal areas. 1 m² = 10 000 cm².
- Easy: Rectangle and parallelogram on base 8 with height 5: both 40.
- Medium: Floor 4 m × 5 m with 50 cm square tiles: 20 ÷ 0.25 = 80 tiles.
- Exam-type: Area 72, b = 9: h = 8.
Area is in square units (cm², m²); perimeter is in plain length units.
Using the slanted side instead of the perpendicular height.
"Base times straight-up height."
Practice questions
- 1A rectangle is 35 m by 21 m. Find its area.
- 2A parallelogram has base 7 cm and height 11 cm. Find its area.
- 3The area of a rectangle is 342 cm² and its length is 19 cm. Find its width.
- 4A rectangular lawn is 29 m by 11 m. A path 3 m wide surrounds the lawn on the outside. Find the area of the path.
- 5In a parallelogram, one side 14 cm has a corresponding height of 6 cm. The adjacent side is 12 cm. Find the height corresponding to that side.
- 6In a parallelogram, one side 9 cm has a corresponding height of 8 cm. The adjacent side is 12 cm. Find the height corresponding to that side.
- 7A rectangle has a diagonal of 25 cm and one side 7 cm. Find its area.
- 8The length of a rectangle is increased by 10% and its width is decreased by 20%. What is the percentage change in the area?
Show answers (try them yourself first)
- 1735 m²
- 277 cm²
- 318 cm
- 4276 m²
- 57 cm
- 66 cm
- 7168 cm²
- 812% decrease
Area of a triangle and Heron's formula
A triangle is half of a parallelogram made by joining two copies. When the height is hard to measure, the three sides are enough.
Area = ½ × base × height. With sides a, b, c and semi-perimeter s = (a + b + c)/2, Heron's formula: Area = √[s(s − a)(s − b)(s − c)]. Equilateral triangle: (√3/4)a².
Formula: A = ½bh; A = √[s(s−a)(s−b)(s−c)]
In the figure: Use Heron's formula when you know a, b and c but not the height.
Rule 1: Base and height — Half of base times the perpendicular height.
- Easy: b = 10, h = 6: 30.
- Medium: Right triangle, legs 6 and 8: 24.
- Exam-type: Area 40, b = 10: h = 8.
Rule 2: Heron's formula — Find s first, then the three differences.
- Easy: 3, 4, 5: s = 6, area √(6·3·2·1) = 6.
- Medium: 13, 14, 15: s = 21, area √(21·8·7·6) = 84.
- Exam-type: Equilateral side 4: (√3/4)·16 = 4√3.
Sides must satisfy the triangle inequality: the two shorter sides add to more than the longest.
Using s = a + b + c instead of half of it.
"Half-perimeter first, then multiply the gaps."
Practice questions
- 1A triangle has base 6 cm and height 25 cm. Find its area.
- 2A right-angled triangle has perpendicular sides 7 cm and 11 cm. Find its area.
- 3Use Heron's formula to find the area of a triangle with sides 17 cm, 17 cm and 16 cm.
- 4The area of a triangle is 142.5 cm² and its base is 15 cm. Find the corresponding height.
- 5Find the area of an equilateral triangle of side 14 cm.
- 6A median of a triangle of area 110 cm² divides it into two triangles. What is the area of each?
- 7A triangle has sides 5 cm, 5 cm and 6 cm (its area is 12 cm²). Find the altitude drawn to the side of length 5 cm.
- 8In quadrilateral ABCD, the diagonal AC = 25 cm. The perpendiculars from B and D to AC are 6 cm and 8 cm. Find the area of ABCD.
Show answers (try them yourself first)
- 175 cm²
- 238.5 cm²
- 3120 cm²
- 419 cm
- 549√3 cm²
- 655 cm²
- 74.8 cm
- 8175 cm²
Area of a circle and a sector
A round pizza of radius 15 cm covers more than a square one of side 15 cm. A slice covers a fraction of it.
Area of a circle = πr². A sector of angle θ has area (θ/360) × πr². A ring between circles of radii R and r has area π(R² − r²).
Formula: A = πr²; sector = (θ/360)πr²; ring = π(R² − r²)
In the figure: The red slice is the fraction θ/360 of the full circle area.
Rule 1: Circle area — Square the radius first, then multiply by π.
- Easy: r = 7: 154.
- Medium: d = 20: r = 10, area 314 (π = 3.14).
- Exam-type: Area 616: r² = 196, r = 14.
Rule 2: Sector and ring — Take the fraction for the sector; subtract inner from outer for a ring.
- Easy: r = 14, θ = 90°: (1/4) × 616 = 154.
- Medium: Semicircle r = 7: 77.
- Exam-type: Ring R = 10, r = 7: π × 51 ≈ 160.1.
Doubling the radius makes the area four times as big.
Using πr × 2 (circumference) for area, or forgetting to square r.
"Area has a square: r squared."
Practice questions
- 1A sector has radius 28 cm and arc length 84 cm. Find its area using A = ½ × arc length × radius.
- 2A sector has radius 7 cm and arc length 14 cm. Find its area using A = ½ × arc length × radius.
- 3A sector has radius 14 cm and arc length 56 cm. Find its area using A = ½ × arc length × radius.
- 4A sector has radius 21 cm and arc length 105 cm. Find its area using A = ½ × arc length × radius.
- 5A sector has radius 7 cm and arc length 35 cm. Find its area using A = ½ × arc length × radius.
- 6The area of a circle of radius r is
- 7The area of a sector with angle θ in a circle of radius r is
- 8Find the area of a circle of radius 21 cm. (Take π = 22/7.)
Show answers (try them yourself first)
- 11176 cm²
- 249 cm²
- 3392 cm²
- 41102.5 cm²
- 5122.5 cm²
- 6πr²
- 7(θ/360) × πr²
- 81386 cm²
Area of a circle and a sector
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