Linear polynomials: terms and values
A taxi charges ₹20 to start plus ₹12 per km. The bill for x km is 12x + 20. Put in a number for x and you get the bill.
A linear polynomial in x has the form ax + b (a ≠ 0). x is the variable, a is the coefficient and b is the constant term. Its value at x = k is ak + b.
Formula: p(x) = ax + b, p(k) = ak + b
In the figure: For p(x) = 3x + 2: coefficient 3, constant 2, and p(4) = 3 × 4 + 2 = 14.
Rule 1: Find the value — Replace x by the number and calculate; mind the signs.
- Easy: p(x) = 2x + 5: p(3) = 11.
- Medium: p(x) = 4x − 7: p(−2) = −8 − 7 = −15.
- Exam-type: p(x) = 5 − 3x: p(2) = 5 − 6 = −1.
Rule 2: Real-life rule — Fixed part is the constant; the part that changes with x carries the coefficient.
- Easy: ₹20 + ₹12 per km: p(x) = 12x + 20; for 5 km ₹80.
- Medium: Pencils at ₹5 each: cost = 5x.
- Exam-type: A pack of 10 sweets plus x more: total = x + 10.
A linear polynomial has x only to the power 1. x² or 1/x makes it non-linear.
Writing p(−2) for 4x − 7 as 4 × 2 − 7 and forgetting the minus sign.
"Bracket first": put the number in brackets before multiplying.
Practice questions
- 1Pick the expression that is a polynomial of degree 1 in y.
- 2What is the constant term of the polynomial −8t − 6?
- 3Evaluate p(x) = −7x − 3 at x = −3.
- 4For the polynomial p(x) = 4x + b, it is known that p(3) = 9. Find b.
- 5If p(x) is a linear polynomial with p(1) = −1 and p(6) = −21, find p(8).
- 6If p(x) = −6x + 4 and q(x) = −6x + 4, find p(x) + q(x).
- 7A linear polynomial p(x) has p(1) = −4 and p(−1) = −10. Find p(0).
- 8Let p(x) = 4x − 3. Find p(p(2)).
Show answers (try them yourself first)
- 13y + 5
- 2−6
- 318
- 4−3
- 5−29
- 6−12x + 8
- 7−7
- 817
Linear patterns and the n-th term
Make squares from matchsticks in a row: 1 square needs 4 sticks, 2 need 7, 3 need 10. Each new square adds 3 sticks. A rule gives the sticks for any number of squares.
If a pattern grows by the same amount d each time, its n-th term is dn + (first term − d), a linear polynomial in n. The step d is the coefficient of n.
Formula: n-th term = dn + (a − d), where a = first term
In the figure: The pattern 5, 8, 11, 14 adds 3 each time, so the n-th term is 3n + 2 (n = 1 gives 5).
Rule 1: Find the rule — Subtract consecutive terms to get d, then use dn + (a − d).
- Easy: 2, 5, 8, …: d = 3, rule 3n − 1.
- Medium: 10, 20, 30, …: rule 10n.
- Exam-type: 7, 5, 3, …: d = −2, rule −2n + 9.
Rule 2: Use the rule — Put the value of n into the rule, or solve for n when a term is given.
- Easy: Rule 3n + 2: 10th term = 32.
- Medium: Rule 4n − 1 = 39 gives n = 10.
- Exam-type: Sticks for 6 squares: 3 × 6 + 1 = 19.
Always test the rule on the first two terms before using it.
Writing the rule as dn only and forgetting the (a − d) part.
"Step times n, then fix the start."
Practice questions
- 1In the pattern 7, 1, −5, −11, … what is the constant difference between consecutive terms?
- 2The n-th term of a pattern is T(n) = 5n + 6. Find T(13).
- 3A pattern has first term 12 and each next term is 5 more than the previous one. Which rule gives the n-th term?
- 4For which value of n does the rule 3n + 8 give 56?
- 5A pattern of shapes uses 6 sticks for the first shape, and each next shape needs 3 more sticks than the one before. How many sticks are needed for shape number 11?
- 6A pattern of shapes uses 3 sticks for the first shape, and each next shape needs 2 more sticks than the one before. How many sticks are needed for shape number 10?
- 7A linear pattern has T(2) = 12 and T(6) = 36. Find T(12).
- 8The n-th term of a pattern is 7n − 4. By how much does the 14-th term exceed the 6-th term?
Show answers (try them yourself first)
- 1−6
- 271
- 35n + 7
- 416
- 536
- 621
- 772
- 856
Linear growth and decay
A plant 10 cm tall grows 2 cm every week. A tank with 100 L loses 5 L every minute. One grows steadily, the other empties steadily.
When a quantity starts at b and changes by the same rate a each unit of time, its value is a·t + b. Positive a means growth, negative a means decay.
Formula: Value = (rate) × time + (start)
In the figure: Green line: 10 + 2w rises 2 per week. Red line: 100 − 5t falls 5 per minute.
Rule 1: Build the rule — Start value is the constant; rate per unit is the coefficient (negative for loss).
- Easy: ₹500 saved, +₹50 per month: 50m + 500.
- Medium: Candle 30 cm, burns 2 cm per hour: 30 − 2h.
- Exam-type: Phone at 80%, falls 4% per hour: 80 − 4h.
Rule 2: Answer questions — Substitute the time to find the value, or set the value and solve for time.
- Easy: 10 + 2w after 6 weeks: 22 cm.
- Medium: 100 − 5t = 0 gives t = 20 minutes.
- Exam-type: When does 30 − 2h = 10? h = 10 hours.
Same change per unit time means linear. If the change itself keeps changing, it is not linear.
Using the rate as the start value, e.g. writing 2w + 10 as 10w + 2.
"Start stays, rate travels with the variable."
Practice questions
- 1Bhavna's plant is 9 cm tall today and grows 3 cm every week. How tall will it be after 3 weeks?
- 2A candle is 36 cm long. It burns 4 cm every hour. What is its length after 2 hours?
- 3A cab charges a fixed ₹27 plus ₹17 for every kilometre. What is the fare for 9 km?
- 4A tank holds 476 litres and leaks 17 litres every hour. After how many hours will exactly 306 litres be left?
- 5A sapling is 19 cm tall and grows 3 cm every week. In how many weeks will it be 43 cm tall?
- 6A bike costs ₹76 thousand today and its resale value drops by ₹7 thousand every year. Which formula gives the value V after t years (in ₹ thousand)?
- 7Anil's sapling is 18 cm tall and grows 3 cm a week. Firoz's sapling is 26 cm tall and grows 2 cm a week. After how many weeks are both equally tall?
- 8Plan A costs ₹187 per month plus ₹13 per GB. Plan B costs ₹43 per month plus ₹25 per GB. For how many GB do both plans cost the same?
Show answers (try them yourself first)
- 118
- 228
- 3180
- 410
- 58
- 6V = 76 − 7t
- 78
- 812
Zeros of a linear polynomial
A shopkeeper asks: for how many items does the bill 2x − 6 become ₹0 after the discount? The answer is the number that makes the expression zero.
A zero of p(x) is a number k with p(k) = 0. A linear polynomial ax + b has exactly one zero, x = −b/a.
Formula: ax + b = 0 ⇒ x = −b/a
In the figure: For 2x − 6: a = 2, b = −6, so the zero is −(−6)/2 = 3, and 2(3) − 6 = 0.
Rule 1: Find the zero — Set the polynomial equal to 0 and solve for x.
- Easy: 3x + 9: zero −3.
- Medium: 5x − 2: zero 2/5.
- Exam-type: 7 − x: zero 7.
Rule 2: Check a zero — Put the number in; if the value is 0 it is a zero.
- Easy: Is 4 a zero of 2x − 8? 2(4) − 8 = 0, yes.
- Medium: Is 1 a zero of 3x + 1? Value 4, no.
- Exam-type: If k is a zero of ax + b with k = 2 and b = −10, then a = 5.
The zero is where the line crosses the x-axis. A linear polynomial never has two zeros.
Giving the zero as b/a and missing the minus sign.
"Move the constant, then divide by the coefficient."
Practice questions
- 1How many zeros does a linear polynomial ax + b (a ≠ 0) have?
- 2Find the zero of 5x − 35.
- 3Find the zero of the polynomial 2x + 6.
- 4If x = 4 is a zero of the polynomial 7x + b, find b.
- 5Solve 6x + 9 = 2x − 8 for x.
- 6A block of ice at the temperature 25 °C is cooled so that its temperature falls by 5 °C every minute. After how many minutes does the temperature reach 0 °C?
- 7p(x) = 4x + 3 and q(x) = 4x + 1. Find the zero of p(x) + q(x).
- 8A linear polynomial p(x) has zero x = 3 and p(0) = −12. Find p(5).
Show answers (try them yourself first)
- 1exactly one
- 27
- 3−3
- 4−28
- 5−17/4
- 65
- 7−1/2
- 88
Graphs of linear relationships
A taxi bill plotted against distance makes a straight line. It starts at ₹20 and rises steadily.
The graph of y = ax + b is a straight line. b is where it cuts the y-axis (intercept); a decides the tilt: rising if a > 0, falling if a < 0. The zero is where it meets the x-axis.
Formula: y = ax + b: y-intercept b, zero −b/a
In the figure: The line y = 2x + 1 cuts the y-axis at 1 and passes through (1, 3). Its zero is −1/2.
Rule 1: Plot two points — Any two points are enough; join them and extend the line.
- Easy: y = x + 2: (0, 2) and (1, 3).
- Medium: y = 2x: (0, 0) and (2, 4).
- Exam-type: y = 3 − x: (0, 3) and (3, 0).
Rule 2: Read the graph — Find b where x = 0, and the zero where y = 0.
- Easy: Line through (0, 4) and (2, 0): y = 4 − 2x.
- Medium: Falling line: a is negative.
- Exam-type: Horizontal line y = 3 has a = 0 (not a linear polynomial in x).
Two points fix a straight line. Check with a third point.
Joining points with a curve or a broken line.
"b is where it begins on the y-axis, a is how steep."
Practice questions
- 1At which point does the graph of y = 2x + 2 cut the y-axis?
- 2A point on the line y = x + 7 has x-coordinate −3. What is its y-coordinate?
- 3Find the x-coordinate of the point where y = 5x + 5 meets the x-axis.
- 4A straight line passes through (3, 2) and (7, 10). By how much does y change when x increases by 1?
- 5A straight line passes through (3, 2) and (5, 6). By how much does y change when x increases by 1?
- 6A line passes through (3, 2) and (5, 4). Which is its equation?
- 7The lines y = 2x + 1 and y = 5x − 5 meet at a point. What is its x-coordinate?
- 8The line y = x − 3 together with the two coordinate axes encloses a triangle. Find its area (in square units).
Show answers (try them yourself first)
- 1(0, 2)
- 24
- 3−1
- 42
- 52
- 6y = x − 1
- 72
- 89/2