Think of a number tricks
At a fair a magician says: "Think of your age, add 5, double it and subtract 10. Tell me the answer and I will tell your age." You say 36. He replies 18 instantly. Algebra is his secret.
Call the secret number n and write each step as an expression. After simplifying, the letter n either stays (so we can work backwards from the answer) or cancels out (so the answer is fixed).
In the figure: Add 5, double, subtract 10, halve: you return to n.
Rule 1: Write the steps — Turn each word into an operation on n. Use brackets when a later step applies to everything before it.
- Easy: Add 3, then multiply by 4: 4(n + 3) = 4n + 12.
- Medium: Double, then add 6: 2n + 6.
- Exam-type: Subtract 5, then triple: 3(n − 5) = 3n − 15.
Rule 2: Simplify to find the secret — Expand brackets and combine like terms. See what is left.
- Easy: (n + 7) × 2 − 14 = 2n: twice the start.
- Medium: (3n + 12) ÷ 3 − 4 = n: the start itself.
- Exam-type: (2n + 10) ÷ 2 − n = 5: always 5.
Rule 3: Work backwards — Undo the steps in reverse order, with the opposite operation.
Think of a number tricks
In the app you can move this figure with your finger.
Open in the appIn the figure: Do the same to both sides, like undoing the trick.
- Easy: ×4 then +9 gives 37: (37 − 9) ÷ 4 = 7.
- Medium: ×3 then −5 gives 22: (22 + 5) ÷ 3 = 9.
- Exam-type: Half of a number plus 6 is 15: (15 − 6) × 2 = 18.
If the letter n cancels out, the answer is the same whatever number you start with, and that is what makes a trick look like magic.
Forgetting brackets: "add 3 then multiply by 4" is 4(n + 3), not 4n + 3.
Write, simplify, look. Memory clue: "n goes in, if n cancels, magic comes out".
Spot the difference
| Point | n stays | n cancels |
|---|---|---|
| Example | 2n | (2n + 10) ÷ 2 − n = 5 |
| Answer depends on the start? | yes | no |
| Use | guess the start from the answer | predict the answer |
Practice questions
- 1Write as an expression: 5 more than a number tripled.
- 2Start with 6, add 4, multiply by 3, subtract 12. Find the result.
- 3A number times 5, plus 2, is 37. Find the number.
- 4Simplify 2(n + 5) − 10.
- 5Think of n, add 9, double, subtract 18, halve. What is the result in terms of n?
- 6A number times 3, minus 8, is 31. Find the number.
- 7Think of n, multiply by 4, add 20, divide by 4, subtract n. Find the result.
- 8A number times 6, minus 14, then halved gives 20. Find the number.
Show answers (try them yourself first)
- 13n + 5
- 218
- 37
- 42n
- 5n
- 613
- 75
- 89
Number pyramids
In a shop, tins are stacked so that each tin rests on two tins below. In a number pyramid each box holds the sum of the two boxes just below it.
For bottom row a, b, c of a 3-row pyramid the middle row is a + b, b + c and the top is a + 2b + c. For a 4-row pyramid with bottom row a, b, c, d the top is a + 3b + 3c + d.
In the figure: Bottom 2, 3, 4 gives 5, 7 and then 12. Check: 2 + 2 × 3 + 4 = 12.
Rule 1: Fill upward — Add each pair of neighbours to get the box above them.
Number pyramids
In the app you can move this figure with your finger.
Open in the appIn the figure: Combine like terms the way the pyramid adds them.
- Easy: Bottom 2, 5, 3: middle 7, 8; top 15.
- Medium: Bottom 4, 1, 6: middle 5, 7; top 12.
- Exam-type: Bottom 1, 9, 2: middle 10, 11; top 21.
Rule 2: Find a missing number — Use top = a + 2b + c and solve for the missing letter.
- Easy: Top 22, bottom 3, ?, 5: 3 + 2b + 5 = 22, so b = 7.
- Medium: Top 30, left middle 14: right middle is 30 − 14 = 16.
- Exam-type: Top 17, bottom 2, 4, ?: 2 + 8 + c = 17, so c = 7.
Rule 3: Four rows — The two middle bottom numbers count 3 times each.
- Easy: Bottom 1, 2, 3, 4: 1 + 6 + 9 + 4 = 20.
- Medium: Bottom 2, 0, 1, 5: 2 + 0 + 3 + 5 = 10.
- Exam-type: Bottom 3, 1, 1, 3: 3 + 3 + 3 + 3 = 12.
The counts 1, 2, 1 (three rows) and 1, 3, 3, 1 (four rows) tell how many times each bottom number is used in the top.
Adding all the bottom numbers once: 2 + 3 + 4 = 9, but the top is 12, because the middle number counts twice.
Three rows: 1-2-1. Four rows: 1-3-3-1. Memory clue: "121 for three, 1331 for four".
Spot the difference
| Point | 3-row pyramid | 4-row pyramid |
|---|---|---|
| Top number | a + 2b + c | a + 3b + 3c + d |
| Example bottom row | 2, 3, 4 | 1, 2, 3, 4 |
| Top | 12 | 20 |
Practice questions
- 1Bottom row 1, 4, 2 of a 3-row pyramid. Find the top.
- 2The middle row is 6, 9. Find the top.
- 3Bottom row 5, 5, 5. Find the top.
- 4The top is 24 and the bottom row is 3, ?, 5. Find the missing number.
- 5A 4-row pyramid has bottom row 1, 1, 1, 1. Find the top.
- 6The top is 30 and the left number of the middle row is 12. Find the right number.
- 7Every bottom number of a 4-row pyramid is increased by 2. By how much does the top increase?
- 8A 3-row pyramid has top 40 and bottom row x, 6, x with the same x on both sides. Find x.
Show answers (try them yourself first)
- 111
- 215
- 320
- 48
- 58
- 618
- 716
- 814
Grids and calendar tricks
A friend covers a 2 × 2 square on a calendar and says "the four dates add up to 52". You instantly say the smallest date is 9. The calendar has a pattern: one step right adds 1, one row down adds 7.
If the top-left date is a, the 2 × 2 square holds a, a + 1, a + 7, a + 8, with sum 4a + 16. So a = (sum − 16) ÷ 4.
In the figure: Sum: a + (a + 1) + (a + 7) + (a + 8) = 4a + 16.
Rule 1: Find the start from the sum — Subtract 16 and divide by 4.
- Easy: Sum 76: (76 − 16) ÷ 4 = 15.
- Medium: Sum 100: (100 − 16) ÷ 4 = 21.
- Exam-type: Sum 44: (44 − 16) ÷ 4 = 7.
Rule 2: Other shapes — Write each date using a, then add. For a 3 × 3 square the sum is 9 times the middle date.
- Easy: Three dates in a column from 5: 5 + 12 + 19 = 36 = 3a + 21.
- Medium: Three dates in a row from 10: 10 + 11 + 12 = 33 = 3a + 3.
- Exam-type: 3 × 3 square with middle 16: 9 × 16 = 144.
Rule 3: Grids with rules — Write what each rule says as an equation, then solve for the unknown.
- Easy: Last = sum of first two; 6, ?, 15: ? = 15 − 6 = 9.
- Medium: Each row adds to 15; 6, ?, 4: ? = 15 − 10 = 5.
- Exam-type: Each row adds to 21; ?, 9, 7: ? = 21 − 16 = 5.
Every 2 × 2 calendar sum is a multiple of 4, because 4a + 16 = 4(a + 4). A sum such as 70 is impossible.
Using +10 for the date below. A row down on a calendar adds 7 (days in a week), not 10.
Right is +1, down is +7. Memory clue: "One step right, a week down".
Spot the difference
| Point | 2 × 2 square | 3 × 3 square |
|---|---|---|
| Sum | 4a + 16 | 9 × middle |
| Find the start | (sum − 16) ÷ 4 | middle = sum ÷ 9 |
| Example | start 5: 36 | middle 16: 144 |
Practice questions
- 1On a calendar, what date is directly below 12?
- 2A 2 × 2 square has top-left date 3. Find the sum.
- 3What date is just to the right of 20?
- 4A 2 × 2 square has sum 60. Find the smallest date.
- 5A 3 × 3 square has middle date 10. Find the sum.
- 6Three dates in a row start at 8. Find their sum.
- 7A 2 × 2 square has sum 92. Find its largest date.
- 8Can a 2 × 2 calendar square have sum 70?
Show answers (try them yourself first)
- 119
- 228
- 321
- 411
- 590
- 627
- 727
- 8No (a = 13.5 is not a whole number)
The largest product
A game gives you three digit cards, say 2, 4 and 6. You must place them as a two-digit number times a one-digit number. Which placement gives the biggest score?
For three different digits in □□ × □, the largest product comes when the largest digit is the multiplier and the other two form the two-digit number in decreasing order (larger digit in the tens place).
In the figure: The six products: the largest, 252, is 42 × 6.
Rule 1: Apply the rule — Pick the largest digit as the multiplier, then arrange the others big to small.
- Easy: Digits 3, 4, 8: 43 × 8 = 344.
- Medium: Digits 1, 5, 9: 51 × 9 = 459.
- Exam-type: Digits 2, 6, 7: 62 × 7 = 434.
Rule 2: Compare by expanding — Split each two-digit number into tens and units. If the first parts match, compare the second parts.
- Easy: 42 × 6 = 240 + 12 and 62 × 4 = 240 + 8, so 42 × 6 wins.
- Medium: 43 × 8 = 320 + 24 and 83 × 4 = 320 + 12.
- Exam-type: 31 × 8 = 240 + 8 and 81 × 3 = 240 + 3.
Rule 3: Why it works — With digits p < q < r, qp × r = 10qr + pr and rp × q = 10qr + pq. The first terms match; pr is bigger than pq because r > q.
- Easy: Digits 2, 4, 6: difference = 2 × (6 − 4) = 4 (252 − 248).
- Medium: Digits 1, 3, 8: 248 − 243 = 5 = 1 × (8 − 3).
- Exam-type: Four digits 1, 2, 3, 4 in □□ × □□: 41 × 32 = 1312.
The rule works for any three different digits. For two two-digit numbers, put the two largest digits in the tens places.
Putting the largest digit in the tens place of the two-digit number. For 2, 4, 6 that gives 62 × 4 = 248, which is smaller than 252.
The biggest digit is the boss multiplier; the rest line up big to small. Memory clue: "Boss multiplies, the rest descend".
Spot the difference
| Point | Largest digit is multiplier | Largest digit in tens place |
|---|---|---|
| Placement | 42 × 6 | 62 × 4 |
| Product | 252 | 248 |
| Result | the largest | smaller |
Practice questions
- 1Digits 2, 5, 8 in □□ × □. Which digit is the multiplier for the largest product?
- 2Find the largest product with digits 3, 6, 7 in □□ × □.
- 3Which is larger, 41 × 6 or 61 × 4?
- 4Find the largest product with digits 1, 6, 9 in □□ × □.
- 5By how much is 43 × 8 larger than 83 × 4?
- 6Expand (10q + p) × r.
- 7Use 1, 2, 3, 4 once each in □□ × □□. Find the largest product.
- 8Digits 1, 8, 9 in □□ × □. Find the largest product.
Show answers (try them yourself first)
- 18
- 2441
- 341 × 6
- 4549
- 512
- 610qr + pr
- 71312
- 8729
Divisibility tricks
Asha says: "Write a two-digit number, say 83. Reverse it to 38. Subtract: 83 − 38 = 45. Divide by 9." There is never a remainder! Algebra explains why.
A two-digit number with tens digit a and units digit b is 10a + b. Its reverse is 10b + a. Difference: 9a − 9b = 9(a − b). Sum: 11a + 11b = 11(a + b). For a 3-digit number abc, adding its two cyclic numbers gives 111(a + b + c).
In the figure: 83 − 38 = 45 and 45 ÷ 9 = 5: the difference of the digits.
Rule 1: Difference with the reverse — The difference is 9 times the difference of the digits.
- Easy: 83 − 38 = 45 = 9 × 5.
- Medium: 91 − 19 = 72 = 9 × 8.
- Exam-type: 52 − 25 = 27 = 9 × 3.
Rule 2: Sum with the reverse — The sum is 11 times the sum of the digits.
- Easy: 42 + 24 = 66 = 11 × 6.
- Medium: 19 + 91 = 110 = 11 × 10.
- Exam-type: 65 + 56 = 121 = 11 × 11.
Rule 3: Cyclic numbers — abc + bca + cab = 111(a + b + c) = 3 × 37 × (a + b + c), so it is divisible by 3 and 37.
- Easy: 123 + 231 + 312 = 666 = 37 × 18.
- Medium: 245 + 452 + 524 = 1221 = 37 × 33.
- Exam-type: 507 + 075 + 750 = 1332 = 37 × 36.
10a + b = 9a + (a + b). The part 9a is always a multiple of 9 and of 3, so the digit sum a + b decides divisibility by 9 and by 3.
Trying a few examples and calling it proved. Examples can only suggest; the algebra with a and b proves it for every number.
Difference: 9. Sum: 11. Cyclic: 111. Memory clue: "Minus 9, Plus 11, Rotate 111".
Spot the difference
| Point | Reverse difference | Reverse sum |
|---|---|---|
| Expression | 9(a − b) | 11(a + b) |
| Always divisible by | 9 | 11 |
| Example with 52 | 27 | 77 |
Practice questions
- 1Take 83, reverse to 38, subtract and divide by 9. Find the quotient.
- 2Add 42 and 24, then divide by 11. Find the quotient.
- 3Is 738 divisible by 9?
- 4Add 123 and its two cyclic numbers. Divide the sum by 37.
- 5Write the difference of the number 10a + b and its reverse.
- 6Is 123 divisible by 3? By 9?
- 7The number 91 and its reverse differ by 72. Write 72 as 9 times the difference of the digits.
- 8Why is the sum of a two-digit number and its reverse always divisible by 11?
Show answers (try them yourself first)
- 15
- 26
- 3Yes (7 + 3 + 8 = 18)
- 418
- 59a − 9b
- 6By 3 only (digit sum 6)
- 772 = 9 × 8
- 8Because it equals 11(a + b)