Mid-point of a segment
The meeting point halfway between two friends’ houses on a grid map is the average of their positions.
The mid-point of A(x₁, y₁) and B(x₂, y₂) is M((x₁ + x₂)/2, (y₁ + y₂)/2): the average of the x’s and the average of the y’s.
Formula: M = ((x₁ + x₂)/2, (y₁ + y₂)/2)
In the figure: Equal tick marks show M is halfway between A and B.
Mid-point of a segment
In the app you can move this figure with your finger.
Open in the appRule 1: Find the mid-point — Add the two x’s and halve; add the two y’s and halve.
- Easy: (2, 3) and (8, 7): M = (5, 5).
- Medium: (−4, 6) and (2, −2): M = (−1, 2).
- Exam-type: (0, 0) and (6, −8): M = (3, −4).
Rule 2: Find the other end — Put the mid-point in the formula and solve for the unknown end.
- Easy: M(−2, 8), A(1, 4): B = (−5, 12).
- Medium: M(3, 1), A(−1, −2): B = (7, 4).
- Exam-type: M(2, −3), A(5, 0): B = (−1, −6).
Other end = 2 × mid-point − known end.
Forgetting to halve, giving the sum of the coordinates.
"Mid-point: add and halve, x and y separately."
Practice questions
- 1Find the mid-point of the line segment joining the points A(−9, −5) and B(−23, −19).
- 2Find the mid-point of the line segment joining the points A(6, 1) and B(4, −11).
- 3Find the mid-point of the line segment joining the points A(9, 1) and B(21, 1).
- 4Find the mid-point of the line segment joining the points A(−1, −3) and B(−15, −3).
- 5Find the mid-point of the line segment joining the points A(9, −8) and B(11, −20).
- 6The mid-point of the line segment AB is M(−2, 8). If A is (1, 4), find the coordinates of B.
- 7The mid-point of the line segment AB is M(2, 7). If A is (7, 2), find the coordinates of B.
- 8The mid-point of the line segment AB is M(−10, 10). If A is (−7, 4), find the coordinates of B.
Show answers (try them yourself first)
- 1(−16, −12)
- 2(5, −5)
- 3(15, 1)
- 4(−8, −3)
- 5(10, −14)
- 6(−5, 12)
- 7(−3, 12)
- 8(−13, 16)
Point dividing a segment in a given ratio
A signboard placed one-third of the way from the school to the market divides the road in the ratio 1 : 2.
If P divides AB internally in the ratio m : n (AP : PB), then P = ((mx₂ + nx₁)/(m + n), (my₂ + ny₁)/(m + n)). Note the cross pattern: m goes with the far end B.
Formula: P = ((mx₂ + nx₁)/(m + n), (my₂ + ny₁)/(m + n))
In the figure: AP : PB = 2 : 3, so P is 2/5 of the way from A to B.
Point dividing a segment in a given ratio
In the app you can move this figure with your finger.
Open in the appRule 1: Use the formula — Put m, n and the coordinates carefully; m multiplies the second point.
- Easy: A(1, 2), B(7, 8), 1 : 2: P = (3, 4).
- Medium: A(−3, 5), B(9, −7), 1 : 3: P = (0, 2).
- Exam-type: A(2, −1), B(6, 7), 3 : 1: P = (5, 5).
Rule 2: Fraction-of-the-way shortcut — A ratio m : n means P is m/(m + n) of the way from A to B.
- Easy: A(0, 0), B(9, 6), ratio 1 : 2: one-third of the way: (3, 2).
- Medium: A(0, 0), B(10, 5), ratio 2 : 3: two-fifths of the way: (4, 2).
- Exam-type: Ratio 1 : 1 gives the mid-point.
The part next to A (m) multiplies B’s coordinate, and the part next to B (n) multiplies A’s.
Swapping m and n, which gives the point from the wrong end.
"m with the far end, n with the near end."
Practice questions
- 1Find the coordinates of the point P which divides the line segment joining A(−3, −4) and B(−3, 6) internally in the ratio 2 : 3 (that is, AP : PB = 2 : 3).
- 2Find the coordinates of the point P which divides the line segment joining A(−7, 7) and B(−15, 15) internally in the ratio 3 : 1 (that is, AP : PB = 3 : 1).
- 3Find the coordinates of the point P which divides the line segment joining A(1, 1) and B(6, 1) internally in the ratio 2 : 3 (that is, AP : PB = 2 : 3).
- 4Find the coordinates of the point P which divides the line segment joining A(−4, −2) and B(6, −7) internally in the ratio 3 : 2 (that is, AP : PB = 3 : 2).
- 5Find the coordinates of the point P which divides the line segment joining A(4, −5) and B(16, −9) internally in the ratio 3 : 1 (that is, AP : PB = 3 : 1).
- 6Find the coordinates of the point P which divides the line segment joining A(5, −4) and B(11, −4) internally in the ratio 2 : 1 (that is, AP : PB = 2 : 1).
- 7Find the coordinates of the point P which divides the line segment joining A(0, −3) and B(−7, −31) internally in the ratio 5 : 2 (that is, AP : PB = 5 : 2).
- 8Find the coordinates of the point P which divides the line segment joining A(0, −3) and B(−12, 15) internally in the ratio 5 : 1 (that is, AP : PB = 5 : 1).
Show answers (try them yourself first)
- 1(−3, 0)
- 2(−13, 13)
- 3(3, 1)
- 4(2, −5)
- 5(13, −8)
- 6(9, −4)
- 7(−5, −23)
- 8(−10, 12)
Finding the ratio, the axis point or an unknown end
If you know where a point sits on the road, you can work backwards to find the ratio, or the missing end.
Put the known coordinates in the section formula and solve for m : n or for the unknown end. The x-axis divides a segment where y = 0, giving m : n = −y₁ : y₂; the y-axis where x = 0, giving −x₁ : x₂.
Formula: m : n = −y₁ : y₂
In the figure: x-axis cuts A(2, −3), B(5, 6) in the ratio 3 : 6 = 1 : 2, at the point (3, 0).
Rule 1: Find the ratio — Use the one coordinate that tells you where P is.
- Easy: P(3, 4) divides A(1, 2), B(7, 8): m : n = 1 : 2.
- Medium: x-axis divides A(2, −3), B(5, 6): 1 : 2, at (3, 0).
- Exam-type: y-axis divides A(−2, 4), B(6, −2): 1 : 3, at (0, 2.5).
Rule 2: Find an unknown end — Put the ratio and P in the formula and solve for B.
- Easy: P(3, 4) divides AB in 1 : 2, A(1, 2): B = (7, 8).
- Medium: P(4, 6) divides AB in 2 : 1, A(0, 0): B = (6, 9).
- Exam-type: Check by putting B back in the formula.
On an axis the other coordinate is 0, so only one coordinate gives the ratio.
Forgetting the minus sign in m : n = −y₁ : y₂; a negative ratio means the point is outside the segment.
"y zero on the x-axis, x zero on the y-axis."
Practice questions
- 1The mid-point of the line segment joining A(−2, y) and B(−8, 1) is M(−5, 2). Find y.
- 2The mid-point of the line segment joining A(9, y) and B(−3, −5) is M(3, 0). Find y.
- 3In what ratio does the x-axis divide the line segment joining A(5, −6) and B(−7, 7)?
- 4The point P(−3, 25) lies on the line segment joining A(−3, 5) and B(−3, 33). Find the ratio AP : PB.
- 5In what ratio does the y-axis divide the line segment joining A(−6, −4) and B(8, −2)?
- 6The point P(0, −12) divides the line segment joining A(−6, −6) and B in the ratio 3 : 1 (AP : PB). Find the coordinates of B.
- 7The point P(−9, 1) divides the line segment joining A(−1, −3) and B in the ratio 2 : 1 (AP : PB). Find the coordinates of B.
- 8The point P(−6, −1) divides the line segment joining A(−6, 5) and B in the ratio 2 : 5 (AP : PB). Find the coordinates of B.
Show answers (try them yourself first)
- 13
- 25
- 36 : 7
- 45 : 2
- 53 : 4
- 6(2, −14)
- 7(−13, 3)
- 8(−6, −16)
Trisection, parallelograms and circles
Two poles placed at one-third and two-thirds along a wire divide it into three equal pieces.
The points of trisection divide AB in the ratios 1 : 2 and 2 : 1. In a parallelogram the diagonals share the same mid-point. If AB is a diameter, the centre is its mid-point and the radius is half of AB.
In the figure: Trisection of A(2, −2), B(−7, 4): P = (−1, 0), Q = (−4, 2).
Rule 1: Trisection and parallelogram — Use 1 : 2 and 2 : 1, or equate the two diagonal mid-points.
- Easy: A(2, −2), B(−7, 4): P (1 : 2) = (−1, 0), Q (2 : 1) = (−4, 2).
- Medium: A(1, 2), B(4, 3), C(6, 6): fourth vertex D = (3, 5).
- Exam-type: A(−1, 0), B(2, 1), C(3, 5): D = (0, 4).
Rule 2: Circle with a diameter — Centre = mid-point of the diameter; radius = half the distance AB.
- Easy: A(2, −3), B(−4, 5): centre (−1, 1), radius 5.
- Medium: A(−3, 2), B(5, 6): centre (1, 4), radius √20.
- Exam-type: Centre (2, 3), one end (6, 6): other end (−2, 0).
In every parallelogram, vertex A + vertex C = vertex B + vertex D.
Pairing the wrong vertices: the diagonals join opposite vertices, not neighbours.
"Diagonals bisect each other: A + C = B + D."
Practice questions
- 1In △ABC, A is (1, 2), B is (0, −6) and C is (8, 8). D is the mid-point of BC. Find the coordinates of D.
- 2In △ABC, A is (4, 6), B is (2, 5) and C is (−10, −5). D is the mid-point of BC. Find the coordinates of D.
- 3Find the points of trisection of the line segment joining A(−5, 5) and B(−11, 20) (the two points that divide it into three equal parts).
- 4AB is a diameter of a circle, with A(−4, 5) and B(−16, −5). Find the centre of the circle.
- 5Find the points of trisection of the line segment joining A(3, 1) and B(6, 7) (the two points that divide it into three equal parts).
- 6The centre of a circle is O(1, 0) and one end of a diameter is A(−4, 3). Find the other end of the diameter.
- 7Three vertices of a parallelogram ABCD, taken in order, are A(5, −5), B(5, 6) and C(1, −6). Find the fourth vertex D.
- 8Three vertices of a parallelogram ABCD, taken in order, are A(−5, 5), B(−6, −4) and C(4, 1). Find the fourth vertex D.
Show answers (try them yourself first)
- 1(4, 1)
- 2(−4, 0)
- 3(−7, 10) and (−9, 15)
- 4(−10, 0)
- 5(4, 3) and (5, 5)
- 6(6, −3)
- 7(1, −17)
- 8(5, 10)
Applications of the section formula
Planning a metro station a fixed fraction of the way between two towns, or finding the balance point of a triangular plate, both use this formula.
Turn the story into a segment with a ratio. For the centroid of a triangle use the average of the three vertices: ((x₁ + x₂ + x₃)/3, (y₁ + y₂ + y₃)/3). In a rhombus the diagonals bisect each other; the mid-point of the hypotenuse of a right triangle is equidistant from all three vertices.
Formula: G = ((x₁ + x₂ + x₃)/3, (y₁ + y₂ + y₃)/3)
In the figure: Triangle (0, 0), (6, 0), (3, 6): centroid = (9/3, 6/3) = (3, 2).
Rule 1: Real situations — Pick the two ends and the ratio from the story, then use the formula.
- Easy: A(2, 3), B(10, 7): a point one-fourth of the way (1 : 3): (4, 4).
- Medium: Triangle (0, 0), (6, 0), (3, 6): centroid (3, 2).
- Exam-type: Midpoint of (4, 0) and (4, 10) is (4, 5).
Rule 2: Shapes and proofs — Use mid-points of the diagonals to prove properties.
- Easy: A(0, 0), B(4, 3), C(8, 0), D(4, −3): both diagonals have mid-point (4, 0); with equal sides it is a rhombus.
- Medium: Right triangle A(0, 0), B(6, 0), C(0, 8): mid-point of BC is (3, 4), at distance 5 from A, half of BC = 10.
- Exam-type: The same mid-point for two diagonals means a parallelogram.
Draw the points on a grid first so the ratio is visible.
Using 3 vertices’ sum without dividing by 3 for the centroid.
"Centroid is the average of the three corners."
Practice questions
- 1On a map (1 unit = 1 km), village A is at (5, 3) and village B is at (13, 11). A water tank stands exactly half-way along the straight path AB. Find its coordinates.
- 2On a map (1 unit = 1 km), village A is at (8, 7) and village B is at (12, 3). A bridge stands exactly half-way along the straight path AB. Find its coordinates.
- 3On a map (1 unit = 1 km), village A is at (9, 5) and village B is at (13, 13). A well stands exactly half-way along the straight path AB. Find its coordinates.
- 4On a map (1 unit = 1 km), town A is at (2, 8) and town B is at (29, 26). A petrol pump lies on the straight road from A to B, at 4/9 of the way from A. Find the coordinates of the petrol pump.
- 5On a map (1 unit = 1 km), town A is at (8, 9) and town B is at (−19, 36). A rest house lies on the straight road from A to B, at 4/9 of the way from A. Find the coordinates of the rest house.
- 6On a map (1 unit = 1 km), towns A and B are at (8, −9) and (2, −15). A rest house is built at the mid-point of AB. How far is it from the origin of the map (in km)?
- 7On a map (1 unit = 1 km), towns A and B are at (−12, 6) and (−18, 10). A bus stop is built at the mid-point of AB. How far is it from the origin of the map (in km)?
- 8On a map (1 unit = 1 km), towns A and B are at (8, −5) and (16, −13). A petrol pump is built at the mid-point of AB. How far is it from the origin of the map (in km)?
Show answers (try them yourself first)
- 1(9, 7)
- 2(10, 5)
- 3(11, 9)
- 4(14, 16)
- 5(−4, 21)
- 613
- 717
- 815