Applying the Basic Proportionality Theorem
A shelf parallel to the floor in a triangular roof cuts both slanting sides in the same proportion.
The Basic Proportionality Theorem (Thales): if a line is drawn parallel to one side of a triangle, it divides the other two sides in the same ratio. In ΔABC with DE ∥ BC: AD/DB = AE/EC.
Formula: AD/DB = AE/EC
In the figure: DE ∥ BC: 4/6 = 2/x, so x = 3.
Applying the Basic Proportionality Theorem
In the app you can move this figure with your finger.
Open in the appRule 1: Find the missing part — Use upper part / lower part on both sides.
- Easy: AD = 4, DB = 6, AE = 2: EC = 3.
- Medium: AD = 3, DB = 5, AE = 6: EC = 10.
- Exam-type: AD = 2, DB = 3, EC = 6: AE = 4.
Rule 2: Other triangles — The names change, the rule does not: parallel line, same ratio.
- Easy: ΔPQR, ST ∥ QR: PS = 3, SQ = 2, PT = 6 gives TR = 4.
- Medium: ΔXYZ, MN ∥ YZ: XM = 5, MY = 10, XN = 4 gives NZ = 8.
- Exam-type: ΔABC, DE ∥ BC: AD = 2, AB = 8, AE = 3 gives EC = 9.
Always parts of the same side compared with parts of the other side.
Comparing AD/DB with EC/AE, which is upside down.
"Parallel line cuts both sides in the same ratio."
Practice questions
- 1In △MLC, WT ∥ LC with W on ML and T on MC. If WL = 6 cm, MT = 8 cm, TC = 4 cm, find MW (in cm).
- 2In △EZT, PB ∥ ZT with P on EZ and B on ET. If EP = 5 cm, PZ = 10 cm, BT = 10 cm, find EB (in cm).
- 3In △AHF, TD ∥ HF with T on AH and D on AF. If AT = 8 cm, TH = 6 cm, DF = 9 cm, find AD (in cm).
- 4In △PQX, TF ∥ QX with T on PQ and F on PX. If PT = 3 cm, TQ = 5 cm, PF = 15 cm, find FX (in cm).
- 5In △CWT, PG ∥ WT with P on CW and G on CT. If CP = 18 cm, PW = 15 cm, GT = 15 cm, find CG (in cm).
- 6In △ZCD, YG ∥ CD. If ZG = 3 cm, GD = 4 cm, ZY = 6 cm, find the full length ZC (in cm).
- 7In △SZQ, PA ∥ ZQ. If SA = 6 cm, AQ = 7 cm, SP = 24 cm, find the full length SZ (in cm).
- 8In △KDE, TB ∥ DE. If KT = 15 cm, TD = 30 cm, KB = 3 cm, find the full length KE (in cm).
Show answers (try them yourself first)
- 112
- 25
- 312
- 425
- 518
- 614
- 752
- 89
Converse: is the line parallel?
To check that a shelf is level, measure the parts it cuts on both sides; equal ratios prove it is parallel.
The converse: if a line divides two sides of a triangle in the same ratio, it is parallel to the third side. If AD/DB = AE/EC then DE ∥ BC.
Formula: AD/DB = AE/EC ⇒ DE ∥ BC
In the figure: 3/6 = 2/4 = 1/2, so DE ∥ BC.
Rule 1: Compare the ratios — Simplify both ratios and see if they match.
- Easy: AD = 3, DB = 6, AE = 2, EC = 4: 1/2 = 1/2, parallel.
- Medium: AD = 2, DB = 3, AE = 3, EC = 5: 2/3 ≠ 3/5, not parallel.
- Exam-type: AD = 6, DB = 9, AE = 4, EC = 6: 2/3 = 2/3, parallel.
Rule 2: Using the whole side — AD/AB = AE/AC gives the same conclusion.
- Easy: AD = 2, AB = 6, AE = 3, AC = 9: 1/3 = 1/3, parallel.
- Medium: AD = 3, AB = 8, AE = 2, AC = 6: 3/8 ≠ 1/3, not parallel.
- Exam-type: Unequal ratios always mean the line is not parallel.
The converse needs the ratios to be equal on both sides.
Concluding "parallel" after checking only one ratio.
"Equal ratios on both sides: line is parallel."
Practice questions
- 1In △UQK, F lies on UQ and X lies on UK. UF = 20 cm, FQ = 15 cm, UX = 4 cm and XK = 5 cm. Is FX ∥ QK?
- 2In △QHN, W lies on QH and C lies on QN. QW = 12 cm, WH = 2 cm, QC = 36 cm and CN = 9 cm. Is WC ∥ HN?
- 3In △YNC, D lies on YN and L lies on YC. YD = 6 cm, DN = 36 cm, YL = 3 cm and LC = 18 cm. Is DL ∥ NC?
- 4In △AHD, W lies on AH and G lies on AD. AW = 6 cm, WH = 2 cm, AG = 6 cm and GD = 4 cm. Is WG ∥ HD?
- 5In △VUP, D is on VU and T is on VP with VU = 32 cm, VD = 20 cm, VP = 32 cm and VT = 20 cm. Is DT ∥ UP?
- 6In △HEX, Z is on HE and G is on HX with HE = 28 cm, HZ = 8 cm, HX = 35 cm and HG = 10 cm. Is ZG ∥ EX?
- 7In △BVZ, R is on BV and H is on BZ with BV = 30 cm, BR = 25 cm, BZ = 19 cm and BH = 16 cm. Is RH ∥ VZ?
- 8In △VAF, M is on VA and B is on VF with VA = 10 cm, VM = 2 cm, VF = 30 cm and VB = 6 cm. Is MB ∥ AF?
Show answers (try them yourself first)
- 1No
- 2No
- 3Yes
- 4No
- 5Yes
- 6Yes
- 7No
- 8Yes
Equivalent forms of the ratios
If a 10 m pole is cut into 4 m and 6 m, then the part-to-whole ratios 4/10 and 6/10 tell the same story as 4/6.
From AD/DB = AE/EC you can also write AD/AB = AE/AC, DB/AB = EC/AC, and flipped forms such as AB/AD = AC/AE. All say the same thing.
Formula: AD/AB = AE/AC
In the figure: Add 1 to both sides: (AD + DB)/DB = (AE + EC)/EC, that is AB/DB = AC/EC.
Rule 1: Part to whole — Use AB = AD + DB and AC = AE + EC.
- Easy: AD = 2, DB = 4, AE = 3: AD/AB = 2/6, so AC = 9, EC = 6.
- Medium: AD = 3, DB = 3, AE = 4: AD/AB = 1/2, so AC = 8.
- Exam-type: DB = 4, AB = 10, EC = 6: DB/AB = EC/AC gives AC = 15.
Rule 2: Flipped forms — Flipping both ratios keeps the equation true.
- Easy: AB = 12, AD = 4, AC = 15: AB/AD = AC/AE gives AE = 5.
- Medium: AB = 15, DB = 5, AC = 12: AB/DB = AC/EC gives EC = 4.
- Exam-type: All forms are the same equation written differently.
Use whichever form has the two known lengths on one side.
Mixing a part-to-part ratio with a part-to-whole ratio in one equation.
"Same kind on the left and on the right."
Practice questions
- 1In △UGQ, SR ∥ GQ and US : SG = 8 : 6. Find RQ : UQ.
- 2In △CHD, SV ∥ HD and CS : SH = 1 : 2. Find CH : CS.
- 3In △ZBS, MF ∥ BS and ZM : MB = 4 : 8. Find ZF : ZS.
- 4In △ZHD, TV ∥ HD and ZT : TH = 2 : 7. Find ZH : TH.
- 5In △TWY, NL ∥ WY and TN : NW = 4 : 1. Find LY : TY.
- 6In △YGD, UQ ∥ GD and YU : UG = 8 : 2. Find YQ : YD.
- 7In △LKN, VT ∥ KN and LV : VK = 4 : 8. Find LK : VK.
- 8In △FNQ, AB ∥ NQ and FA : AN = 5 : 2. Find BQ : FQ.
Show answers (try them yourself first)
- 13 : 7
- 23 : 1
- 31 : 3
- 49 : 7
- 51 : 5
- 64 : 5
- 73 : 2
- 82 : 7
Algebraic problems with the theorem
When lengths are given as expressions in x, the theorem turns the picture into an equation to solve.
Put the lengths in AD/DB = AE/EC, cross-multiply, simplify (the x² often cancels), solve, and check that every length is positive.
In the figure: x/(x − 2) = (x + 2)/(x − 1) gives x² − x = x² − 4, so x = 4.
Rule 1: Form and solve — Expand both sides and collect x terms.
- Easy: AD = x, DB = x − 2, AE = x + 2, EC = x − 1: x = 4.
- Medium: AD = x, DB = 6, AE = x + 2, EC = 9: 9x = 6x + 12, x = 4.
- Exam-type: AD = 2x − 1, DB = 3, AE = x, EC = 2: 4x − 2 = 3x, x = 2.
Rule 2: Check the answer — Put x back and see that both ratios match and no length is negative.
- Easy: x = 4: lengths 4, 2, 6, 3 give 4/2 = 6/3 = 2.
- Medium: x = 2: lengths 3, 3, 2, 2 give 3/3 = 2/2 = 1.
- Exam-type: A root making a length zero or negative is rejected.
Lengths are positive, so an answer giving a negative length is rejected.
Expanding (x − 2)(x + 2) wrongly; it equals x² − 4.
"Cross-multiply, cancel x squared, solve, check."
Practice questions
- 1In △WXQ, EM ∥ XQ, WE = 6 cm, WM = 3 cm and MQ = 9 cm. Find EX (in cm).
- 2In △BMP, NH ∥ MP, BN = 4 cm, BH = 8 cm and HP = 6 cm. Find NM (in cm).
- 3In △ZGD, XA ∥ GD, ZX = 20 cm, ZA = 20 cm and AD = 30 cm. Find XG (in cm).
- 4In △ZVE, YS ∥ VE with ZY = x + 8, YV = x − 1, ZS = x and SE = x − 3 (all in cm). Find x.
- 5In △TSK, RP ∥ SK with TR = x + 12, RS = x + 8, TP = x + 4 and PK = x + 2 (all in cm). Find x.
- 6In △RWY, US ∥ WY with RU = x + 1, UW = x + 10, RS = x and SY = x + 8 (all in cm). Find x.
- 7In △PVC, TU ∥ VC with PT = x + 5, TV = x + 7, PU = x and UC = x + 1 (all in cm). Find x.
- 8In △FND, KC ∥ ND with FK = x, KN = x − 2, FC = x + 11 and CD = x + 7 (all in cm). Find x.
Show answers (try them yourself first)
- 118
- 23
- 330
- 44
- 54
- 68
- 75
- 811
Mid-points, trapeziums and other uses
A shelf at the half-way height of a triangular roof is exactly parallel to the base, and the same idea works in a trapezium.
If D and E are mid-points of AB and AC, then AD/DB = AE/EC = 1, so DE ∥ BC. In a trapezium ABCD with AB ∥ DC, a line parallel to AB cuts the legs in the same ratio, and the diagonals satisfy AO/OC = BO/OD.
Formula: AO/OC = BO/OD
In the figure: Equal tick marks show D and E are mid-points, so DE ∥ BC.
Rule 1: Mid-points — Equal parts on two sides mean the joining line is parallel to the third.
- Easy: AB = 12, D mid-point: AD = 6, DB = 6.
- Medium: AD = DB and AE = EC: DE ∥ BC.
- Exam-type: BC = 14: the mid-point line DE = 7.
Rule 2: Trapezium and diagonals — Treat the parallel line as the line in the triangle theorem.
- Easy: AB ∥ DC, EF ∥ AB: AE = 3, ED = 6, BF = 4 gives FC = 8.
- Medium: Diagonals meet at O: AO = 6, OC = 3, BO = 4 gives OD = 2.
- Exam-type: AO = 10, OC = 5, OD = 3 gives BO = 6.
In every trapezium problem find the two parallel sides first.
Using the theorem when the line is not parallel to any side.
"Parallel sides first, then ratios."
Practice questions
- 1In △LMV, E is the mid-point of LM and EU ∥ MV, with U on LV. If LV = 24 cm, find LU (in cm).
- 2In △KGS, F is the mid-point of KG and FU ∥ GS, with U on KS. If KS = 52 cm, find KU (in cm).
- 3In △BHK, L is the mid-point of BH and LN ∥ HK, with N on BK. If BK = 12 cm, find BN (in cm).
- 4In △EUZ, HW ∥ UZ, EH = 11 cm and HU = 2 cm. In what ratio does W divide EZ (that is, EW : WZ)?
- 5In △HDV, FG ∥ DV, HF = 6 cm and FD = 12 cm. In what ratio does G divide HV (that is, HG : GV)?
- 6In trapezium MZAU, MZ ∥ UA and the diagonals meet at F. If FM = 12 cm, FA = 10 cm, FU = 25 cm, find FZ (in cm).
- 7In trapezium NFUQ, NF ∥ QU and the diagonals meet at G. If GU = 24 cm, GF = 18 cm, GQ = 36 cm, find GN (in cm).
- 8In trapezium SPZU, SP ∥ UZ and the diagonals meet at E. If ES = 16 cm, EP = 16 cm, EU = 8 cm, find EZ (in cm).
Show answers (try them yourself first)
- 112
- 226
- 36
- 411 : 2
- 51 : 2
- 630
- 712
- 88