Mendel and the monohybrid cross
Std 11 covered cell division (meiosis); here we use it to study Mendel's laws, linkage, sex determination and genetic disorders.
Children look like their parents yet differ from siblings — genes follow rules.
Heredity = transmission of traits across generations. A monohybrid cross involves pure parents differing in one pair of contrasting traits.
In the figure : Mendel, Tt × Tt and the Punnett square.
Rule 1 : Terminology and why Mendel succeeded — Character = feature (height); trait = its form (tall/dwarf); gene = segment of DNA; alleles = alternative forms of a gene (at the same locus); dominant = expressed in F1; recessive = masked in F1. Phenotype = what is seen (tall), genotype = genetic make-up (TT/Tt). Homozygous = identical alleles (pure; one type of gamete); heterozygous = different alleles (hybrid; two types of gametes). Mendel (1822, Moravia) succeeded with the pea, 7 clear trait pairs, large samples, careful records and ratios. He proposed ‘factors’ (today's genes) occur in pairs and do not blend.
- Easy : Phenotype = seen; genotype = written.
- Medium : TT, tt = homozygous; Tt = heterozygous.
- Exam-type (CET) : 7 pairs = 7 traits.
Rule 2 : Monohybrid cross: F1 and F2 — Pure tall (TT) × pure dwarf (tt) → gametes T and t → F1 all Tt (tall). Selfing F1 gives F2: Punnett square TT : Tt : Tt : tt. Phenotypic ratio 3 tall : 1 dwarf; genotypic ratio 1 : 2 : 1. The dwarf trait was not lost in F1, only masked; it returned in F2 = factors do not blend. A Punnett square is a probability table of fertilizations. A pure line is a line from a single pure parent by self-fertilization.
- Easy : F1 = 100% tall.
- Medium : F2: 3:1 and 1:2:1.
- Exam-type (CET) : 1 TT + 2 Tt = 3 tall.
3:1 visible, 1:2:1 genetic: P = 3:1, G = 1:2:1.
‘The recessive trait is lost in F1’ is wrong. Trap: ‘Tt is homozygous’ is wrong (heterozygous).
Memory clue : "Homo = same alleles; hetero = hybrid".
Spot the difference
| Point | Phenotype | Genotype |
|---|---|---|
| Meaning | Visible | Genetic make-up |
| Example | Tall | TT / Tt |
| F2 ratio | 3 : 1 | 1 : 2 : 1 |
Practice questions
- 1What is an allele?
- 2Heterozygous means?
- 3F1 phenotype of TT × tt?
- 4F2 phenotypic ratio?
- 5F2 genotypic ratio?
- 6Use of Punnett square?
- 7What is a pure line?
- 8Plant used by Mendel?
Show answers (try them yourself first)
- 1Alternative form of a gene.
- 2Different alleles (Tt).
- 3All tall.
- 43 : 1.
- 51 : 2 : 1.
- 6Shows probable offspring.
- 7True-breeding line.
- 8Garden pea (Pisum sativum).
Dihybrid cross, Mendel's laws and test cross
Tracking two traits makes new pairings, like picking a shirt and a cap.
A dihybrid cross involves two pairs of contrasting traits (RRYY × rryy). A test cross = F1 × homozygous recessive, used to find an unknown genotype.
In the figure : Dihybrid 9:3:3:1 and test cross.
Dihybrid cross, Mendel's laws and test cross
In the app you can move this figure with your finger.
Open in the appRule 1 : Dihybrid cross and 9:3:3:1 — Round-yellow (RRYY) × wrinkled-green (rryy) → gametes RY and ry → F1 RrYy, all round-yellow. F1 makes 4 gamete types: RY, Ry, rY, ry. 4 × 4 = 16 combinations: 9 round-yellow : 3 round-green : 3 wrinkled-yellow : 1 wrinkled-green; 4 phenotypes, 9 genotypes. The new combinations (round-green, wrinkled-yellow) show the two trait pairs do not depend on each other.
- Easy : 9 + 3 + 3 + 1 = 16.
- Medium : 4 phenotypes; 9 genotypes.
- Exam-type (CET) : Gametes = 2 × 2 = 4.
Rule 2 : Mendel's 3 laws; test cross and back cross — 1. Dominance: of two contrasting traits from pure parents, the one seen in F1 is dominant. 2. Segregation (purity of gametes): alleles separate at gamete formation; each gamete is pure (one allele). 3. Independent assortment: in a dihybrid, the two pairs are distributed independently (9:3:3:1). Test cross: F1 (or a dominant-looking plant) × tt; all dominant offspring = pure (TT); 1:1 = hybrid (Tt). Back cross: F1 × either parent; a test cross is a type of back cross. Mendel's laws are not universal.
- Easy : Test cross: × tt (recessive).
- Medium : Segregation = purity.
- Exam-type (CET) : Test cross ⊂ back cross.
D-S-I: Dominance, Segregation, Independent assortment. Test cross = ‘× recessive’.
‘Every back cross is a test cross’ is wrong (the reverse holds). Trap: dihybrid ratio 3:1 is wrong.
Memory clue : "Test = recessive tester (tt)".
Spot the difference
| Cross | F2 / result |
|---|---|
| Monohybrid | 3 : 1 |
| Dihybrid | 9 : 3 : 3 : 1 |
| Test cross Tt × tt | 1 : 1 |
Practice questions
- 1Dihybrid F2 ratio?
- 2Gametes of RrYy?
- 3Combinations in F2?
- 4How many genotypes?
- 5Law of segregation states?
- 6Aim of test cross?
- 7Phenotype ratio of Tt × tt?
- 8Independent assortment is based on?
Show answers (try them yourself first)
- 19:3:3:1.
- 2RY, Ry, rY, ry.
- 316.
- 49.
- 5Gametes are pure.
- 6Identify genotype.
- 71 : 1.
- 8Dihybrid cross.
Deviations from Mendelism (Neo-Mendelism)
A pink flower looks like red and white blended, yet the genes are not mixed.
Neo-Mendelism = exceptions found after Mendel: incomplete dominance, co-dominance, multiple alleles, pleiotropy, polygenic inheritance.
In the figure : Deviations from Mendel.
Rule 1 : Incomplete dominance, co-dominance, multiple alleles — Incomplete dominance: both alleles partly expressed; intermediate phenotype. Mirabilis jalapa: red (RR) × white (rr) → F1 pink (Rr); F2 1 red : 2 pink : 1 white. Co-dominance: both alleles fully expressed; in cattle red × white → F1 roan (RW) (red + white hairs); F2 1:2:1. In both, genotypic = phenotypic ratio. Multiple alleles: more than 2 alleles at one locus (from mutation); e.g. human A, B, O blood groups, Drosophila wings (vg).
- Easy : Incomplete = blend-like; co-dominance = both.
- Medium : Both give 1 : 2 : 1.
- Exam-type (CET) : A, B, O = multiple alleles.
Rule 2 : Pleiotropy and polygenic inheritance — Pleiotropy: one gene, several unrelated traits. Sickle-cell anaemia: HbA (normal, dominant) and HbS; the carrier (HbA HbS) shows mild anaemia (RBCs sickle only at low O₂); HbS HbS dies. Carrier × carrier → 1 normal : 2 carrier : 1 anaemic (dies) ⇒ survivors 2 : 1, hence 1:2 instead of 3:1. Polygenic: one trait, many genes (human skin colour) — epistasis, additive. Intragenic interactions (alleles of one gene) and intergenic (different genes: pleiotropy, polygenes, epistasis, supplementary, complementary).
- Easy : Pleiotropy = one gene, many traits.
- Medium : Polygenic = many genes, one trait.
- Exam-type (CET) : HbS HbS = lethal.
Pleio = plenty of traits; poly = plenty of genes.
‘Genes blend in incomplete dominance’ is wrong. Trap: ‘co-dominance gives an intermediate colour’ is wrong (both appear).
Memory clue : "Incomplete = in between; co-dominance = both".
Spot the difference
| Type | F1 | Example |
|---|---|---|
| Incomplete | Pink | Mirabilis |
| Co-dominance | Roan | Cattle |
| Multiple alleles | > 2 alleles | A, B, O |
| Pleiotropy | One gene, many traits | Sickle-cell |
Practice questions
- 1Mirabilis F1 colour?
- 2F2 ratio in incomplete dominance?
- 3Example of co-dominance?
- 4Example of multiple alleles?
- 5What is pleiotropy?
- 6Survivor ratio in sickle-cell carrier cross?
- 7Example of polygenic trait?
- 8What is Neo-Mendelism?
Show answers (try them yourself first)
- 1Pink.
- 21 : 2 : 1.
- 3Roan cattle.
- 4ABO blood groups.
- 5One gene, many traits.
- 62 : 1.
- 7Skin colour.
- 8Post-Mendelian deviations.
Chromosomal theory, chromosomes and ploidy
Genes are lines of text and chromosomes are the book that holds them.
The chromosomal theory (Sutton–Boveri, 1903): genes lie on chromosomes. Ploidy = number of chromosome sets.
In the figure : Chromosome, centromere types and ploidy.
Rule 1 : Chromosomal theory — Mendel's work (1866) was ignored until 1900, when de Vries, Correns and Tschermak rediscovered it. Sutton and Boveri (1903): genes and chromosomes behave in parallel — chromosomes occur in pairs; in meiosis homologues pair, segregate and assort independently; each gamete gets one of each pair. Gametes link parents to offspring; fertilization restores the diploid number. So chromosomes carry hereditary material.
- Easy : Genes and chromosomes both occur in pairs.
- Medium : Gamete = one of each pair.
- Exam-type (CET) : 1866: published; 1900: rediscovered.
Rule 2 : Chromosome structure and ploidy — Chromosome (Waldeyer, 1888) = DNA + histone + non-histone proteins; clearest at metaphase; 2 chromatids joined at the centromere (primary constriction; kinetochore = spindle attachment). Secondary constriction: nucleolus; ends = telomeres. Shapes (centromere position): metacentric (V), submetacentric (L), acrocentric (j), telocentric (i). Euploidy: monoploid (n), diploid (2n), triploid (3n), tetraploid (4n). Aneuploidy: number is not a whole multiple of the set — monosomy (2n−1), nullisomy (2n−2), trisomy (2n+1), tetrasomy (2n+2).
- Easy : Kinetochore = spindle attachment.
- Medium : Euploid = whole sets.
- Exam-type (CET) : Trisomy = 2n + 1.
M-S-A-T: V, L, j, i. Mono = −1, tri = +1.
‘A chromosome is only DNA’ is wrong (proteins too). Trap: ‘trisomy = 2n−1’ is wrong.
Memory clue : "Acrocentric = ‘j’, telocentric = ‘i’ (centromere at the end)".
Spot the difference
| Type | Shape |
|---|---|
| Metacentric | V (middle) |
| Submetacentric | L |
| Acrocentric | j |
| Telocentric | i (terminal) |
Practice questions
- 1Who proposed the chromosomal theory?
- 2Who coined ‘chromosome’?
- 3Chromosomes are made of?
- 4Role of kinetochore?
- 5Which is V-shaped?
- 6What is a telomere?
- 7Example of euploidy?
- 8Monosomy = ?
Show answers (try them yourself first)
- 1Sutton and Boveri.
- 2Waldeyer (1888).
- 3DNA + proteins.
- 4Spindle attachment.
- 5Metacentric.
- 6End of chromosome.
- 73n (triploid).
- 82n − 1.
Linkage, crossing over and sex chromosomes
Beads on one string move together; they separate only if the string breaks.
Linkage = genes on one chromosome inherited together. Crossing over = exchange of segments between non-sister chromatids of homologous chromosomes.
In the figure : Crossing over and linkage.
Rule 1 : Linkage and Morgan's experiments — Linkage was found in plants by Bateson; Morgan tested it in Drosophila. Complete linkage: no crossing over (Drosophila male X). Incomplete linkage: distant genes, crossing over possible (maize: grain colour–shape). Linkage group = all linked genes of one chromosome; number = haploid number: Drosophila 4, pea 7, human 23. Morgan: close genes (yellow body–white eye) = 1.3% recombination; distant (white–miniature wing) = 37.2%. Close = stronger linkage, fewer recombinants.
- Easy : Close = fewer recombinants.
- Medium : Linkage groups = n.
- Exam-type (CET) : Parental combinations are more.
Rule 2 : Crossing over and sex chromosomes — Crossing over (term by Morgan): at pachytene (prophase I) between non-sister chromatids; steps: synapsis, tetrad, crossing over, terminalization. It increases variation → useful for natural selection. Sex chromosomes (allosomes): X and Y. X: straight, long, metacentric, rich in euchromatin (active). Y: acrocentric, rich in heterochromatin (genetically inert). Both have homologous (crossing over here) and non-homologous (X-linked / Y-linked genes) regions. The X's non-homologous region is longer.
- Easy : Pachytene = crossing over.
- Medium : X: metacentric; Y: acrocentric.
- Exam-type (CET) : Non-homologous = sex-linked.
Crossing over: S-T-C-T (synapsis, tetrad, crossing, terminalization).
‘Crossing over is between sister chromatids’ is wrong (non-sister). Trap: ‘close genes = more recombination’ is wrong.
Memory clue : "Close genes cling together".
Spot the difference
| Point | X | Y |
|---|---|---|
| Shape | Metacentric | Acrocentric |
| Chromatin | More euchromatin | More heterochromatin |
| Activity | Active | Inert |
Practice questions
- 1What is linkage?
- 2Example of complete linkage?
- 3Linkage groups in humans?
- 4When does crossing over occur?
- 5Between which chromatids?
- 6What are allosomes?
- 7Y chromosome shape?
- 8What does 1.3% recombination show?
Show answers (try them yourself first)
- 1Genes on one chromosome inherited together.
- 2Drosophila male X.
- 323.
- 4Pachytene (prophase I).
- 5Non-sister chromatids.
- 6Sex chromosomes.
- 7Acrocentric.
- 8Strong linkage.
Autosomal and sex-linked inheritance
Colour blindness is commoner in boys because they have only one X.
Autosomal = inheritance of genes on the 22 pairs of autosomes. Sex-linked = inheritance of genes on non-homologous parts of sex chromosomes (X-linked, Y-linked).
In the figure : Autosomal, X-linked and Y-linked inheritance.
Autosomal and sex-linked inheritance
In the app you can move this figure with your finger.
Open in the appRule 1 : Autosomal inheritance — Humans have 23 pairs: 22 autosomes + 1 sex pair. Autosomal recessive traits affect both sexes equally and may skip generations. Widow's peak (V-shaped hairline) = autosomal dominant (WW, Ww); ww = straight hairline. Phenylketonuria (PKU) = autosomal recessive; without phenylalanine hydroxylase phenylalanine is not converted to tyrosine, accumulates in blood and CSF, impairs brain development, and is excreted in urine.
- Easy : Autosomal: both sexes equal.
- Medium : PKU: missing enzyme.
- Exam-type (CET) : Widow's peak: dominant.
Rule 2 : X-linked and Y-linked inheritance — X-linked recessive: a female needs the gene on both X; with one it is a carrier (looks normal). Males are hemizygous (no allele on Y) → affected, hence commoner in males. Colour blindness (XcY, XcXc; red-green; cones fail) and haemophilia (clotting factor VIII/IX lacking; XhY). Genotypes: XCY, XcY; XCXC, XCXc, XcXc. Colour-blind man (XcY) × normal woman (XCXC) → all daughters carriers, sons normal. Carrier woman × normal man → ¼ normal daughter, ¼ carrier daughter, ¼ normal son, ¼ affected son. Criss-cross: grandfather → daughter → grandson. Y-linked (holandric): father to son (hypertrichosis).
- Easy : Carrier ♀ looks normal.
- Medium : Criss-cross = grandfather → grandson.
- Exam-type (CET) : Y-linked: only in males.
X-linked: a son's X comes from his mother, Y from his father.
‘Haemophilia is Y-linked’ is wrong (X). Trap: ‘a carrier woman is ill’ is wrong.
Memory clue : "Hemizygous = half-zygous (one X)".
Spot the difference
| Disorder | Type |
|---|---|
| PKU | Autosomal recessive |
| Colour blindness | X-linked recessive |
| Haemophilia | X-linked recessive |
| Hypertrichosis | Y-linked |
Practice questions
- 1Pairs of autosomes?
- 2Cause of PKU?
- 3Widow's peak is?
- 4Colours confused in colour blindness?
- 5Another name for haemophilia?
- 6Daughters of XcY × XCXC?
- 7What is hemizygous?
- 8Where are holandric genes?
Show answers (try them yourself first)
- 122.
- 2Lack of phenylalanine hydroxylase.
- 3Autosomal dominant.
- 4Red and green.
- 5Bleeder's disease.
- 6All carriers.
- 7Single X with no allele on Y.
- 8On the Y chromosome.
Sex determination and genetic disorders
Whether a baby is a boy or a girl depends on the father's sperm.
Sex determination = mechanism that fixes sex. Genetic disorders = Mendelian (gene changes) and chromosomal (number/structure) disorders.
In the figure : Sex-determination types and disorders.
Rule 1 : Sex determination — Humans: XX–XY. Female = 44 + XX (homogametic, one egg type); male = 44 + XY (heterogametic; 50% sperm X, 50% Y). X sperm + egg → girl; Y sperm → boy; hence a 1 : 1 sex ratio, and the father decides. Birds: ZW–ZZ — female heterogametic (ZW), male ZZ; the egg decides sex. Honey bee: haplo-diploid — fertilized egg (2n = 32) → female (queen/worker; royal jelly makes a queen); unfertilized egg (n = 16) by parthenogenesis → male (drone). Bonellia: environment (where the larva settles) decides sex.
- Easy : Male: XY (heterogametic).
- Medium : Birds: female = ZW.
- Exam-type (CET) : Bee drone = haploid.
Rule 2 : Genetic disorders — Mendelian (gene changes): thalassemia, sickle-cell, colour blindness, haemophilia, PKU. Thalassemia: autosomal recessive; α-globin (HBA1/HBA2, chromosome 16) or β-globin (HBB, chromosome 11) gene deleted/mutated; anaemia, pale-yellow skin; needs transfusions; differs from sickle-cell (a faulty globin). Chromosomal (number/structure): Down syndrome = trisomy 21, 47 chromosomes, non-disjunction (risk rises in mothers over 45); Turner = 44 + XO, female, short, webbed neck, underdeveloped ovaries; Klinefelter = 44 + XXY, male, tall, gynaecomastia, sterile.
- Easy : Down = 47; Turner = 45; Klinefelter = 47.
- Medium : Turner = female; Klinefelter = male.
- Exam-type (CET) : Thalassemia ≠ sickle-cell.
Turner = tiny (XO, female); Klinefelter = kinda extra (XXY, male).
‘The mother decides the child's sex’ is wrong (the father). Trap: ‘Turner = male’ is wrong.
Memory clue : "Down = trisomy 21; Klinefelter = XXY".
Spot the difference
| Disorder | Chromosomes | Sex |
|---|---|---|
| Down | 47 (trisomy 21) | Both |
| Turner | 45 (44+XO) | Female |
| Klinefelter | 47 (44+XXY) | Male |
Practice questions
- 1Who decides human sex?
- 2Who is heterogametic in humans?
- 3Female bird genotype?
- 4How does a drone arise?
- 5Cause of Down syndrome?
- 6Genotype of Turner?
- 7A Klinefelter feature?
- 8What is non-disjunction?
Show answers (try them yourself first)
- 1Father (sperm).
- 2Male (XY).
- 3ZW.
- 4From unfertilized egg (n = 16).
- 5Trisomy of chromosome 21.
- 644 + XO.
- 7Gynaecomastia / sterility.
- 8Failure of chromosomes to separate.
Quick revision of the whole lesson
| Concept | Key fact |
|---|---|
| Monohybrid | 3:1 and 1:2:1 |
| Dihybrid | 9:3:3:1; test cross 1:1 |
| Deviations | Incomplete, co-dominance, pleiotropy |
| Chromosomes | Sutton–Boveri; euploid/aneuploid |
| Linkage | Close = fewer recombinants |
| Sex-linked | Colour blindness, haemophilia (X) |
| Sex determination | XY, ZW, haplo-diploid |
🎯 Most important points for the exam
- Mendel, monohybrid cross.
- Dihybrid cross and test cross.
- Incomplete dominance, pleiotropy.
- Chromosomal theory, ploidy.
- Linkage, crossing over.
- X-linked disorders.
- Sex determination, Down/Turner/Klinefelter.
Understand the concept → draw the figure → memorise the key points → solve questions yourself.