Sound waves
When a drum is beaten, the skin shakes and you hear a sound far away. The shaking pushes the air in front of it, and the push travels through the air up to your ear. Sound is not a thing that flies; it is a push that passes on.
Sound (ध्वनी) is a form of energy that creates the sensation of hearing. It travels as waves and needs a medium (माध्यम).
In the figure : In the figure compressions and rarefactions form a sound wave.
Rule 1: Sound waves — Sound waves form a chain of compressions (higher density) and rarefactions (lower density). The particles of the medium oscillate parallel to the direction of propagation, so these are longitudinal waves (अनुदैर्ध्य). When a stone is dropped in still water, the particles move up and down, perpendicular to the propagation, so these are transverse waves (अनुप्रस्थ).
- Easy : Sound in air is longitudinal; water ripples are transverse.
- Medium : Where air is squeezed we get a compression; where it is spread out we get a rarefaction. A sound wave is a series of both.
- Exam-type : Sound cannot travel in a vacuum because there are no particles to compress and rarefy.
Rule 2: Wave terms — Wavelength λ is the distance between two successive compressions. Frequency ν is the number of oscillations per second. Amplitude A is the maximum pressure or density change. Time period T is the time for one oscillation. Frequency decides the pitch; amplitude decides the loudness.
- Easy : A high-pitched whistle has a high frequency; a drum has a low frequency.
- Medium : Turning up the volume increases the amplitude, so the sound is louder but the pitch stays the same.
- Exam-type : If 50 oscillations occur in 1 second, ν = 50 Hz and T = 1 ÷ 50 = 0.02 s.
Sound waves
In the app you can move this figure with your finger.
Open in the appSound: longitudinal wave, needs a medium. Frequency → pitch; amplitude → loudness.
Mixing up pitch and loudness. Pitch depends on frequency; loudness on amplitude.
Memory clue: "Frequency = Fineness (pitch); Amplitude = Amount (loudness)".
Spot the difference
| Quantity | Decides |
|---|---|
| Frequency ν | Pitch |
| Amplitude A | Loudness |
| Wavelength λ | Distance between compressions |
| Time period T | Time of one oscillation |
Practice questions
- 1What is sound?
- 2Why does sound need a medium?
- 3Name the two kinds of waves.
- 4Which kind of wave is sound in air?
- 5What decides the pitch of a sound?
- 6What decides the loudness?
- 7A source makes 200 oscillations in 4 seconds. Find its frequency and time period.
- 8Two sounds have equal frequency but one is louder. What is different?
Show answers (try them yourself first)
- 1A form of energy that creates the sensation of hearing.
- 2It travels by the oscillation of particles of the medium.
- 3Longitudinal and transverse.
- 4Longitudinal.
- 5Frequency.
- 6Amplitude.
- 7ν = 200 ÷ 4 = 50 Hz; T = 1 ÷ 50 = 0.02 s.
- 8Amplitude, and not the frequency.
Velocity of sound
In a thunderstorm you see the lightning first and hear the thunder a little later. Light is much faster. By counting the seconds between them, you can judge how far the lightning struck.
Speed of sound v = distance ÷ time = wavelength × frequency (v = νλ).
In the figure : In the figure speed comes from wavelength and frequency.
Rule 1: Speed and the medium — Sound is heard through an iron pipe before it is heard through air, so it travels faster in iron. Velocity = wavelength × frequency, v = νλ. At fixed conditions the velocity of sounds of different frequencies is nearly the same. It is highest in solids, least in gases and increases with temperature. Borelli and Viviani first calculated the speed of sound in the 1660s as 350 m/s; today it is 346 m/s in air.
- Easy : ν = 500 Hz and λ = 0.68 m give v = 500 × 0.68 = 340 m/s.
- Medium : λ = 2 m and v = 340 m/s give ν = 340 ÷ 2 = 170 Hz.
- Exam-type : Thunder is heard 3 s after the lightning. At 340 m/s the distance is 340 × 3 = 1020 m.
Rule 2: Speed in a gas — In a gas, v is directly proportional to √T (absolute temperature) and inversely proportional to √density and √molecular weight. Four times the temperature doubles the velocity; four times the density or molecular weight halves it. At a fixed temperature it does not depend on pressure.
- Easy : Nine times the temperature triples the speed, since √9 = 3.
- Medium : Sixteen times the density makes the speed one-fourth, since √16 = 4.
- Exam-type : Speed is 300 m/s. If the absolute temperature becomes 4 times, the new speed is 300 × 2 = 600 m/s.
v = νλ. Fastest in solids, slowest in gases. Gas: v ∝ √T.
Believing sound is faster in air than in iron. It is faster in solids.
Memory clue: "Solid, then Liquid, then Gas: closer particles pass sound faster".
Spot the difference
| Medium | Speed |
|---|---|
| Solids | Highest |
| Liquids | Medium |
| Gases | Least |
Practice questions
- 1Write the formula connecting speed, wavelength and frequency.
- 2In which type of medium is sound fastest?
- 3What happens to the speed of sound when temperature rises?
- 4Who first calculated the speed of sound, and when?
- 5Does the speed of sound in a gas depend on pressure at a fixed temperature?
- 6Find v if ν = 250 Hz and λ = 1.36 m.
- 7Thunder is heard 5 s after the lightning at 340 m/s. How far is the storm?
- 8Why is the sound heard sooner through an iron pipe than through air?
Show answers (try them yourself first)
- 1v = νλ.
- 2In solids.
- 3It increases.
- 4Borelli and Viviani, in the 1660s.
- 5No.
- 6250 × 1.36 = 340 m/s.
- 7340 × 5 = 1700 m.
- 8Sound travels faster in a solid like iron than in air.
Audible sound, infrasound and ultrasound
A dog can hear a whistle that you cannot hear. Our ears hear only a certain band of sounds, and there are sounds above and below it that we cannot sense.
The human ear hears 20 Hz to 20,000 Hz: audible sound (श्राव्य). Below 20 Hz is infrasound (अवश्राव्य); above 20 kHz is ultrasound (पराश्राव्य).
In the figure : In the figure the three frequency ranges of sound.
Rule 1: Three ranges — The human ear hears 20 Hz to 20,000 Hz, which is audible sound. Below 20 Hz is infrasound, for example a pendulum, or the earth's crust before an earthquake. Above 20 kHz is ultrasound. Children under 5 can hear up to 25 kHz. Bats, mice and dolphins produce ultrasound. Spallanzani found that bats fly in the dark by using their ears: ultrasound reflected from obstacles is received by their ears.
- Easy : 50 Hz is audible; 10 Hz is infrasound; 30 kHz is ultrasound.
- Medium : A 22 kHz sound is ultrasound for most adults, but a child under 5 can still hear it, as the limit for them is 25 kHz.
- Exam-type : Classify 15 Hz, 8000 Hz, 40 kHz: 15 Hz infrasound; 8000 Hz audible; 40 kHz ultrasound.
Rule 2: Uses of ultrasound — Communication between ships, joining plastic surfaces, sterilizing milk by killing bacteria, echocardiography and images of internal organs, cleaning intricate machine parts and locating cracks in metal blocks.
- Easy : Ultrasound cleans small parts of watches and machines.
- Medium : Ultrasound reflected from a crack inside a metal block shows where the crack is, without cutting the block.
- Exam-type : A heart doctor uses ultrasound to see the heart's working: this is called echocardiography.
Audible sound, infrasound and ultrasound
In the app you can move this figure with your finger.
Open in the appAudible: 20 Hz to 20 kHz. Below: infrasound; above: ultrasound.
Saying ultrasound is a very loud sound. It is a high-frequency sound, not a loud one.
Memory clue: "Infra = Inside (below 20 Hz); Ultra = Up (above 20 kHz)".
Spot the difference
| Type | Frequency |
|---|---|
| Infrasound | Below 20 Hz |
| Audible | 20 Hz to 20 kHz |
| Ultrasound | Above 20 kHz |
Practice questions
- 1What range of frequency can the human ear hear?
- 2What is infrasound?
- 3What is ultrasound?
- 4Name two animals that produce ultrasound.
- 5Who found that bats fly in the dark using their ears?
- 6Give three uses of ultrasound.
- 7Classify 5 Hz, 500 Hz and 50 kHz as infrasound, audible or ultrasound.
- 8Why can a child under 5 hear a 24 kHz sound while most adults cannot?
Show answers (try them yourself first)
- 120 Hz to 20,000 Hz.
- 2Sound below 20 Hz.
- 3Sound above 20 kHz.
- 4Bats and dolphins (also mice).
- 5Spallanzani.
- 6Cleaning machine parts, finding cracks in metal, imaging internal organs.
- 75 Hz infrasound; 500 Hz audible; 50 kHz ultrasound.
- 8A young child's ear can hear up to about 25 kHz, while the adult limit is about 20 kHz.
Reflection of sound, SONAR and sonography
Shout in front of a big, empty hall wall and a moment later your voice comes back. That returning voice is an echo. Sound bounces off hard surfaces just like a ball.
An echo (प्रतिध्वनी) is the repetition of a sound by reflection. SONAR uses ultrasound echoes to find depth and direction under water.
In the figure : In the figure an echo needs a wall at least 17.2 m away.
Rule 1: Reflection of sound and echo — Sound reflects from solid and liquid surfaces and follows the laws of reflection. A hard, flat surface is a good reflector; clothes, paper, curtains, carpets and furniture absorb sound and are bad reflectors. The brain retains a sound for 0.1 s. At 22 °C the speed of sound is 344 m/s, so the minimum distance to the reflecting surface is 17.2 m. Multiple reflections cause reverberation (अनुरणन), a continuous, louder, unclear sound. Golghumat at Vijapur gives multiple echoes.
- Easy : In a hall full of curtains and carpets the echo is weak, because they absorb sound.
- Medium : Minimum distance for an echo = v × t ÷ 2 = 344 × 0.1 ÷ 2 = 17.2 m.
- Exam-type : You clap and hear the echo after 0.5 s. At 344 m/s, distance = 344 × 0.5 ÷ 2 = 86 m.
Rule 2: SONAR and sonography — SONAR (Sound Navigation and Ranging) uses ultrasound to find the direction, distance and speed of underwater objects and the depth of the sea. Sonography uses ultrasound with a probe and gel to image internal organs. Its misuse for female foeticide is an offence under the PNDT Act.
In the figure : In the figure SONAR finds the depth of the sea.
- Easy : A 4 s echo in sea water at 1550 m/s gives depth = 1550 × 4 ÷ 2 = 3100 m.
- Medium : A ship gets an echo after 2 s. Depth = 1550 × 2 ÷ 2 = 1550 m.
- Exam-type : Why divide by 2? The sound goes down and comes back up, so the total path is twice the depth.
Reflection of sound, SONAR and sonography
In the app you can move this figure with your finger.
Open in the appEcho needs at least 17.2 m. d = v × t ÷ 2. SONAR uses ultrasound.
Forgetting to halve the time: the sound travels to the surface and back.
Memory clue: "Echo = Go and Back, so half".
Spot the difference
| Point | Echo | Reverberation |
|---|---|---|
| Nature | One repeated sound | Many reflections, unclear |
| Needs | At least 17.2 m | Many reflecting surfaces |
Practice questions
- 1What is an echo?
- 2Why are curtains and carpets bad reflectors of sound?
- 3For how long does the brain retain a sound?
- 4What is the minimum distance for an echo at 22 °C?
- 5What is reverberation?
- 6What does SONAR stand for?
- 7An echo returns from a cliff after 1 s at 344 m/s. How far is the cliff?
- 8The echo of a ship's SONAR returns after 6 s at 1550 m/s. Find the depth of the sea.
Show answers (try them yourself first)
- 1The repetition of a sound by reflection.
- 2They absorb sound.
- 30.1 s.
- 417.2 m.
- 5A continuous, louder, unclear sound caused by multiple reflections.
- 6Sound Navigation and Ranging.
- 7344 × 1 ÷ 2 = 172 m.
- 81550 × 6 ÷ 2 = 4650 m.
The human ear
If you cover your ear with your hand and listen to the sea in a shell, you hear a faint sound. Your ear is a clever machine that collects sound, shakes with it and sends a message to the brain.
The ear has three parts: outer ear, middle ear and inner ear.
In the figure : In the figure how sound travels through the ear.
Rule 1: Parts of the ear — The outer ear (pinna) collects sound with its funnel shape. In the middle ear, the eardrum is pushed inwards by a compression and pulled outwards by a rarefaction, so it vibrates. The inner ear has the snail-shaped cochlea (शंखिका), which converts vibrations into electrical signals that the auditory nerve carries to the brain.
- Easy : The pinna collects sound like a funnel.
- Medium : Order: pinna → eardrum → cochlea → auditory nerve → brain.
- Exam-type : A compression pushes the eardrum in; the next rarefaction pulls it out. So the drum vibrates at the frequency of the sound.
Rule 2: Care of the ears — Never insert sticks or pointed objects into the ear, and avoid very loud music with earphones.
- Easy : Cleaning the ear with a pin can pierce the eardrum.
- Medium : Loud music for long hours through earphones can damage hearing.
- Exam-type : Keep the volume low, take breaks, and see a doctor if there is pain or reduced hearing.
Ear: outer (pinna), middle (eardrum), inner (cochlea). Do not put sharp things in the ear.
Thinking the cochlea gathers sound. The pinna collects; the cochlea converts to signals.
Memory clue: "Pinna Picks, Drum Drives, Cochlea Converts".
Spot the difference
| Part | Work |
|---|---|
| Outer ear (pinna) | Collects sound |
| Eardrum (middle ear) | Vibrates |
| Cochlea (inner ear) | Makes electrical signals |
| Auditory nerve | Takes signals to brain |
Practice questions
- 1Name the three parts of the ear.
- 2What is the work of the pinna?
- 3What happens to the eardrum when a compression arrives?
- 4Which part converts vibrations into electrical signals?
- 5Which nerve carries the signals to the brain?
- 6Give two ways to protect your ears.
- 7Arrange in order: cochlea, brain, eardrum, pinna, auditory nerve.
- 8Why does the eardrum vibrate with the same frequency as the sound?
Show answers (try them yourself first)
- 1Outer ear, middle ear and inner ear.
- 2It collects sound with its funnel shape.
- 3It is pushed inwards.
- 4The cochlea.
- 5The auditory nerve.
- 6Do not insert sharp objects; keep earphone volume low.
- 7Pinna → eardrum → cochlea → auditory nerve → brain.
- 8Each compression pushes it in and each rarefaction pulls it out, one cycle for one wave.
Quick revision
- v = ν × λ; sound is a longitudinal wave needing a medium.
- Audible: 20 Hz–20 kHz; infrasound below, ultrasound above.
- Echo needs at least 17.2 m at 22 °C; SONAR and sonography use ultrasound.