Reflection and spherical mirrors
Look into a spoon's inside and your face is upside down; its outside shows a smaller erect face. Link to earlier classes : reflection, refraction and lenses of classes 9-10 are now handled with sign convention and formulas.
Reflection : i = r; a spherical mirror is a part of a sphere.
In the figure : Concave mirror : real, inverted image.
Reflection and spherical mirrors
In the app you can move this figure with your finger.
Open in the appRule 1: Sign convention — Pole P is the origin; distances along the incident light are +, opposite −. Object on the left ⇒ u is −. Concave : f −, convex : f +.
- Easy : Concave mirror, R = 20 cm ⇒ f = −10 cm.
- Medium : Convex R = 30 cm ⇒ f = +15 cm.
- Exam (CET) : f of a concave mirror? (1) − (2) + (3) 0 (4) infinite → answer 1)
Rule 2: Mirror formula — 1/v + 1/u = 1/f; m = − v/u = h'/h; f = R/2.
- Easy : f = −10, u = −30 ⇒ v = −15 cm; m = −0.5 (real, inverted, smaller).
- Medium : Convex f = +15, u = −30 ⇒ v = +10 cm; m = +1/3.
- Exam (CET) : u = 2f (concave) ⇒ m? (1) −1 (2) +1 (3) 0 (4) 2 → answer 1) Trick : object at C ⇒ image at C, same size.
Rule 3: Nature of images — Concave : u > f ⇒ real, inverted; u < f ⇒ virtual, erect, magnified. Convex : always virtual, erect, diminished.
- Easy : Shaving mirror : object inside F ⇒ magnified virtual image.
- Medium : Vehicle mirror : convex ⇒ wide field.
- Exam (CET) : Image in a convex mirror? (1) virtual (2) real (3) inverted (4) magnified → answer 1)
Derivation : Mirror formula (small aperture)
- Step 1 : From similar triangles : m = −v/u.
- Step 2 : From triangles at F : h'/h = (v − f)/f.
- Step 3 : −v/u = (v − f)/f ⇒ −v f = u v − u f.
- Step 4 : Divide by uvf : 1/v + 1/u = 1/f.
1/v + 1/u = 1/f; m = −v/u; f = R/2.
u is always −; f − for concave; negative m = inverted.
Memory clue : "1/v plus 1/u equals 1/f".
Spot the difference
| Mirror | f | Image |
|---|---|---|
| Concave | − | real/virtual |
| Convex | + | virtual, diminished |
| Plane | ∞ | virtual, same size |
Practice questions
- 1Mirror formula?
- 2Relation between f and R?
- 3Which mirror is a shaving mirror?
- 4f = −12, u = −24 : v?
- 5f = +20, u = −40 : v, m?
- 6R = 40 concave : f?
- 7Concave f = −10, m = −2 : u?
- 8Derive the mirror formula.
Show answers (try them yourself first)
- 11/v + 1/u = 1/f
- 2f = R/2
- 3Concave
- 4v = −24 cm
- 5v = 40/3 = 13.3 cm; m = +1/3
- 6−20 cm
- 7u = −15 cm (v = −30)
- 8Using similar triangles
Refraction and refractive index
A stick in water looks bent; a pond looks shallower.
Refraction is the change of direction of light on entering another medium.
In the figure : i and r are measured from the normal.
Rule 1: Snell's law — n₁ sin i = n₂ sin r; n = c ÷ v = sin i ÷ sin r; water 1.33, glass 1.5, diamond 2.42.
- Easy : Air → glass, i = 30°, n = 1.5 ⇒ sin r = 0.333 ⇒ r = 19.5°.
- Medium : v = 2.25 × 10⁸ in the medium ⇒ n = 1.33.
- Exam (CET) : In a denser medium the ray? (1) bends toward the normal (2) away (3) straight (4) reflects → answer 1) Trick : 'dense ⇒ toward normal'.
Rule 2: Real and apparent depth — Viewed normally : n = real depth ÷ apparent depth. Apparent = real ÷ n.
- Easy : 12 cm of water, n = 1.33 ⇒ apparent = 9.02 cm.
- Medium : Glass slab t, n ⇒ object shifts by t (1 − 1/n) = 6 × (1/3) = 2 cm (t = 6, n = 1.5).
- Exam (CET) : A pond looks? (1) shallower (2) deeper (3) same (4) zero → answer 1)
Rule 3: Glass slab — The emergent ray is parallel to the incident ray; lateral shift = t sin(i − r) ÷ cos r.
- Easy : t = 4 cm, i = 30°, r = 19.5° ⇒ shift = 0.78 cm.
- Medium : i = 0 ⇒ shift 0.
- Exam (CET) : Emergent ray? (1) parallel (2) perpendicular (3) deviated (4) none → answer 1)
Derivation : Apparent depth
- Step 1 : Object O at depth h; ray meets the surface at i, r (small angles).
- Step 2 : In water sin ≈ x/h; in air ≈ x/h'.
- Step 3 : n sin i = sin r ⇒ n (x/h) = x/h'.
- Step 4 : h' = h ÷ n (apparent depth).
n₁ sin i = n₂ sin r; n = c/v; apparent = real/n.
Angles from the normal, not the surface; f unchanged, λ changes.
Memory clue : "Dense = toward the normal".
Spot the difference
| Medium | n | v |
|---|---|---|
| Air | 1 | 3 × 10⁸ |
| Water | 1.33 | 2.25 × 10⁸ |
| Glass | 1.5 | 2 × 10⁸ |
| Diamond | 2.42 | 1.24 × 10⁸ |
Practice questions
- 1State Snell's law.
- 2Formula for n?
- 3Formula for apparent depth?
- 4i = 45°, n = 1.5 : r?
- 5v = 2 × 10⁸ in glass : n?
- 6Depth 8 cm, n = 1.33 : apparent?
- 7t = 9 cm, n = 1.5 : shift of the object?
- 8Derive apparent depth.
Show answers (try them yourself first)
- 1n₁ sin i = n₂ sin r
- 2c/v
- 3real ÷ n
- 428.1°
- 51.5
- 66.02 cm
- 73 cm
- 8Small angles; n = h/h'
Total internal reflection
Seen from under water, the surface can shine like a mirror.
TIR: light from a dense medium at i > C returns completely.
In the figure : Green : refraction; orange : i = C; red : TIR.
Total internal reflection
In the app you can move this figure with your finger.
Open in the appRule 1: Critical angle — Dense ⇒ rare; sin C = 1 ÷ n (n = dense/rare). i > C ⇒ total reflection.
- Easy : Glass n = 1.5 ⇒ C = 41.8°.
- Medium : Water 1.33 ⇒ 48.8°; diamond 2.42 ⇒ 24.4°.
- Exam (CET) : Larger n ⇒ C? (1) smaller (2) larger (3) same (4) 90° → answer 1) Trick : diamond sparkles because C is small.
Rule 2: Conditions — (1) dense ⇒ rare, (2) i > C. At i = C the ray grazes the surface (r = 90°).
- Easy : Air ⇒ water : no TIR.
- Medium : Water ⇒ air, i = 60° > 48.8° ⇒ TIR.
- Exam (CET) : TIR when? (1) dense→rare, i > C (2) rare→dense (3) any (4) i < C → answer 1)
Rule 3: Applications — Optical fibre (core n₁ > cladding n₂), sparkle of diamond, total-reflecting prisms, mirage.
- Easy : Fibre n₁ = 1.5, n₂ = 1.4 ⇒ sin C = 0.933 ⇒ C = 69.0°.
- Medium : Point source 2 m deep : circle radius = h tan C = 2.28 m.
- Exam (CET) : Fibre principle? (1) TIR (2) refraction (3) diffraction (4) polarisation → answer 1)
Derivation : sin C = 1/n
- Step 1 : At i = C, r = 90° : n_dense sin C = n_rare sin 90°.
- Step 2 : n_rare = 1 (air).
- Step 3 : n sin C = 1.
- Step 4 : sin C = 1 ÷ n.
sin C = 1/n; TIR : dense → rare, i > C.
TIR only dense → rare; n is the dense medium's.
Memory clue : "sin C = 1 over n".
Spot the difference
| Case | Condition | Result |
|---|---|---|
| Refraction | i < C | partial reflection |
| Critical | i = C | r = 90° |
| TIR | i > C | 100 % reflection |
Practice questions
- 1What is the critical angle?
- 2Conditions for TIR?
- 3State one use.
- 4n = 2 : C?
- 5n = 1.6 : sin C?
- 6n = 1.33, h = 3 m : circle radius?
- 7C = 30° : n?
- 8How does a mirage form?
Show answers (try them yourself first)
- 1The i for which r = 90°
- 2Dense→rare; i > C
- 3Optical fibre
- 430°
- 50.625
- 63.42 m
- 72
- 8Rare hot air below ⇒ TIR of rays
Refraction at spherical surfaces and lenses
A lens can focus the Sun's image on paper and burn it.
A lens is a transparent medium bounded by spherical surfaces.
In the figure : A real image from a convex lens.
Refraction at spherical surfaces and lenses
In the app you can move this figure with your finger.
Open in the appRule 1: Thin lens — 1/v − 1/u = 1/f; m = v/u; convex f +, concave f −.
- Easy : f = +20, u = −30 ⇒ v = +60; m = −2 (real, inverted, magnified).
- Medium : f = −20, u = −30 ⇒ v = −12; m = +0.4.
- Exam (CET) : Convex, u = −2f ⇒ v? (1) +2f (2) +f (3) −2f (4) infinite → answer 1) Trick : 2f ⇒ 2f.
Rule 2: Lens-maker's formula — 1/f = (n − 1)(1/R₁ − 1/R₂) (in air). P = 1/f (m⁻¹ = D).
- Easy : n = 1.5, R₁ = +20, R₂ = −20 cm ⇒ f = 20 cm.
- Medium : f = 40 cm ⇒ P = +2.5 D.
- Exam (CET) : Unit of P? (1) dioptre (2) m (3) cm (4) J → answer 1)
Rule 3: Combination of lenses — In contact : 1/f = 1/f₁ + 1/f₂, P = P₁ + P₂; m = m₁ × m₂.
- Easy : +4 D and −1.5 D ⇒ +2.5 D (f = 40 cm).
- Medium : f₁ = 10, f₂ = 10 ⇒ f = 5 cm.
- Exam (CET) : P₁ = +3, P₂ = +2 ⇒ P? (1) +5 D (2) +6 D (3) +1 D (4) 0 → answer 1)
Derivation : Thin lens : two refractions
- Step 1 : First surface : n/v' − 1/u = (n − 1)/R₁.
- Step 2 : Second surface : 1/v − n/v' = (1 − n)/R₂.
- Step 3 : Adding : 1/v − 1/u = (n − 1)(1/R₁ − 1/R₂).
- Step 4 : u = ∞ ⇒ v = f : 1/f = (n − 1)(1/R₁ − 1/R₂).
1/v − 1/u = 1/f; P = 1/f; P = P₁ + P₂.
Lens : 1/v − 1/u (mirror : +); use metres for dioptres.
Memory clue : "Lens = minus; mirror = plus".
Spot the difference
| Lens | f | P |
|---|---|---|
| Convex | + | + |
| Concave | − | − |
| Combination | 1/f₁ + 1/f₂ | P₁ + P₂ |
Practice questions
- 1Lens formula?
- 2Formula for P?
- 3P for a combination?
- 4f = 15, u = −45 : v, m?
- 5f = 50 cm : P?
- 6R₁ = 15, R₂ = −15, n = 1.5 : f?
- 7+5 D and −2 D in contact : f?
- 8Derive the lens-maker's formula.
Show answers (try them yourself first)
- 11/v − 1/u = 1/f
- 21/f
- 3P₁ + P₂
- 4v = 22.5 cm; m = −0.5
- 5+2 D
- 615 cm
- 7+3 D ⇒ f = 33.3 cm
- 8Adding the two surface refractions
Dispersion and prisms
Sunlight through a glass can paint a coloured band on a wall.
Dispersion is the splitting of white light into its colours.
In the figure : Red bends least; violet bends most.
Dispersion and prisms
In the app you can move this figure with your finger.
Open in the appRule 1: Prism formula — n = sin[(A + δ_m) ÷ 2] ÷ sin(A ÷ 2); for small A, δ = (n − 1) A.
- Easy : A = 60°, n = 1.5 ⇒ δ_m = 37.2°.
- Medium : A = 4°, n = 1.5 ⇒ δ = 2°.
- Exam (CET) : At minimum deviation the ray inside is? (1) parallel to the base (2) perpendicular (3) reflected (4) doubled → answer 1)
Rule 2: Dispersion — n decreases with λ : n_V > n_R; violet deviates more. Dispersive power ω = (n_V − n_R) ÷ (n_Y − 1); angular dispersion = (n_V − n_R) A.
- Easy : n_V = 1.532, n_R = 1.513, n_Y = 1.519 ⇒ ω = 0.0366.
- Medium : A = 5° ⇒ angular dispersion = 0.095°.
- Exam (CET) : Deviates least? (1) red (2) green (3) blue (4) violet → answer 1) Trick : 'red is lazy'.
Rule 3: Achromatic combination — Cancel dispersion, keep deviation : ω₁ δ₁ + ω₂ δ₂ = 0 (two thin prisms placed oppositely). For lenses : ω₁/f₁ + ω₂/f₂ = 0.
- Easy : Crown ω = 0.02, δ = 5.2°; flint ω = 0.04 ⇒ δ₂ = 2.6°.
- Medium : Lens : f₁ = 20 (ω₁ = 0.02) ⇒ f₂ = −40 (ω₂ = 0.04).
- Exam (CET) : Achromatic means? (1) colour-free (2) monochrome (3) thick (4) transparent → answer 1)
Derivation : δ = (n − 1) A (small A)
- Step 1 : Small angles ⇒ sin x ≈ x.
- Step 2 : At the first face i = n r₁; at the second e = n r₂.
- Step 3 : δ = i + e − A = n (r₁ + r₂) − A.
- Step 4 : r₁ + r₂ = A ⇒ δ = (n − 1) A.
δ = (n − 1)A; ω = (n_V − n_R)/(n_Y − 1).
The small-A formula fails for large A; ω has no unit.
Memory clue : "Red is lazy, violet is quick".
Spot the difference
| Colour | n (glass) | Deviation |
|---|---|---|
| Red | 1.513 | least |
| Yellow | 1.519 | medium |
| Violet | 1.532 | most |
Practice questions
- 1What is dispersion?
- 2Formula for ω?
- 3Which colour has the largest n?
- 4A = 6°, n = 1.5 : δ?
- 5n_V = 1.65, n_R = 1.61, n_Y = 1.63 : ω?
- 6A = 60°, δ_m = 30° : n?
- 7Why ω₁δ₁ + ω₂δ₂ = 0?
- 8Derive δ = (n − 1)A.
Show answers (try them yourself first)
- 1Splitting white light into colours
- 2(n_V − n_R)/(n_Y − 1)
- 3Violet
- 43°
- 50.063
- 61.41
- 7Equal and opposite angular dispersion
- 8Small angles; r₁ + r₂ = A
Natural phenomena and lens defects
Some cannot read the board; some hold a book far away to read.
Eye defects are corrected by lenses; sky phenomena arise from scattering/refraction.
In the figure : Myopia, hypermetropia and a normal eye.
Rule 1: Myopia — Distant objects blurred; image forms before the retina. Concave lens : f = −(far point). Far point x ⇒ P = −1/x.
- Easy : Far point 50 cm ⇒ f = −50 cm, P = −2 D.
- Medium : Far point 2 m ⇒ P = −0.5 D.
- Exam (CET) : Myopia correction? (1) concave (2) convex (3) cylindrical (4) plane → answer 1)
Rule 2: Hypermetropia — Near objects blurred; near point > 25 cm. Convex lens : an object at 25 cm gets a virtual image at the near point : 1/f = 1/v − 1/u.
- Easy : Near point 100 cm : 1/f = −1/100 + 1/25 = 0.03 ⇒ f = 33.3 cm, P = +3 D.
- Medium : Near point 50 cm ⇒ P = +2 D.
- Exam (CET) : For hypermetropia? (1) convex (2) concave (3) plane (4) prism → answer 1)
Rule 3: Natural phenomena — Rainbow : refraction + TIR + dispersion (red ≈ 42°, violet ≈ 40°). Blue sky : Rayleigh : I ∝ 1/λ⁴. Twinkling : changing n of air.
- Easy : λ_red = 700 nm, λ_blue = 450 nm ⇒ scattering ratio = (700/450)⁴ = 5.9.
- Medium : Red at sunset : blue is scattered away, red arrives.
- Exam (CET) : Why is the sky blue? (1) Rayleigh scattering (2) reflection (3) TIR (4) diffraction → answer 1)
Derivation : Lens for hypermetropia
- Step 1 : Normal object at u = −25 cm.
- Step 2 : The lens gives a virtual image at v = −near point (e.g. −100 cm).
- Step 3 : 1/f = 1/v − 1/u = −1/100 + 1/25.
- Step 4 : 1/f = 0.03 cm⁻¹ ⇒ P = +3 D.
Myopia : concave; hypermetropia : convex; I ∝ 1/λ⁴.
P = 1/f (in metres); P is negative for myopia.
Memory clue : "Near-sighted = concave, far-sighted = convex".
Spot the difference
| Defect | Cause | Lens |
|---|---|---|
| Myopia | image before retina | concave |
| Hypermetropia | image behind retina | convex |
| Astigmatism | uneven curvature | cylindrical |
| Presbyopia | weak muscles with age | bifocal |
Practice questions
- 1What is myopia?
- 2Which lens for hypermetropia?
- 3Rayleigh's law?
- 4Far point 25 cm : P?
- 5Near point 40 cm : P (u = −25)?
- 6λ halved ⇒ scattering?
- 7−2 D spectacles : far point?
- 8How does a rainbow form?
Show answers (try them yourself first)
- 1Far objects blurred, image before the retina
- 2Convex
- 3I ∝ 1/λ⁴
- 4−4 D
- 5+1.5 D
- 616 times
- 750 cm
- 8Refraction, dispersion, TIR, refraction
Optical instruments
A telescope brings far objects near; a microscope enlarges small ones.
Angular magnification m = β/α.
In the figure : A two-lens telescope.
Rule 1: Simple microscope — m = 1 + D/f (image at near point); m = D/f (at infinity). D = 25 cm.
- Easy : f = 5 cm ⇒ m = 1 + 5 = 6; at infinity 5.
- Medium : f = 2.5 cm ⇒ m = 11.
- Exam (CET) : Smaller f ⇒ m? (1) larger (2) smaller (3) same (4) 0 → answer 1)
Rule 2: Compound microscope — m = (L ÷ f₀)(D ÷ f_e) (image at infinity), L = tube length; the objective has a small f₀.
- Easy : f₀ = 1 cm, f_e = 5 cm, L = 15 cm ⇒ m = 15 × 5 = 75.
- Medium : f_e halved ⇒ m doubles.
- Exam (CET) : m = ? (1) (L/f₀)(D/f_e) (2) f₀/f_e (3) L/D (4) 1 + D/f → answer 1)
Rule 3: Telescope — m = f₀ ÷ f_e (normal adjustment); tube L = f₀ + f_e; reflecting telescope : large aperture, no chromatic fault.
- Easy : f₀ = 100, f_e = 5 ⇒ m = 20; L = 105 cm.
- Medium : L = 60, m = 9 ⇒ f_e = 6, f₀ = 54 cm.
- Exam (CET) : Telescope objective f₀? (1) large (2) small (3) zero (4) equal f_e → answer 1) Trick : far-seeing ⇒ large f₀.
Derivation : Telescope : m = f₀/f_e
- Step 1 : The objective forms an image at f₀; angle subtended α = h/f₀.
- Step 2 : The angle seen through the eyepiece β = h/f_e.
- Step 3 : m = β/α.
- Step 4 : m = f₀ ÷ f_e.
m = 1 + D/f; m = (L/f₀)(D/f_e); m = f₀/f_e.
D = 25 cm; large f₀ in a telescope, small in a microscope.
Memory clue : "Telescope = f₀ / f_e".
Spot the difference
| Instrument | m | Length |
|---|---|---|
| Simple microscope | 1 + D/f | — |
| Compound | (L/f₀)(D/f_e) | L |
| Telescope | f₀/f_e | f₀ + f_e |
Practice questions
- 1m of a simple microscope?
- 2m of a telescope?
- 3What is D?
- 4f = 10 cm : m (near point)?
- 5f₀ = 80, f_e = 4 : m and L?
- 6f₀ = 2, f_e = 10, L = 20 : m?
- 7L = 55, m = 10 : f₀, f_e?
- 8Why use a reflecting telescope?
Show answers (try them yourself first)
- 11 + D/f
- 2f₀/f_e
- 325 cm (near point)
- 43.5
- 5m = 20; L = 84 cm
- 6(20/2)(25/10) = 25
- 7f_e = 5, f₀ = 50 cm
- 8Large aperture, no chromatic fault
Quick revision of the whole lesson
| Concept | Key formula / fact | Unit / dimensions |
|---|---|---|
| Mirror | 1/v + 1/u = 1/f; m = −v/u | m; — |
| Snell | n₁ sin i = n₂ sin r | — |
| Critical angle | sin C = 1/n | — |
| Lens | 1/v − 1/u = 1/f | m |
| Power | P = 1/f | D = m⁻¹ |
| Prism | δ = (n − 1)A | — |
| Rayleigh | I ∝ 1/λ⁴ | — |
| Telescope | m = f₀/f_e | — |
🎯 Most important points for the exam
- Mirror : 1/v + 1/u = 1/f; u is always −.
- Dense = toward the normal; apparent = real/n.
- TIR : dense → rare, i > C; sin C = 1/n.
- Lens : 1/v − 1/u = 1/f; P = 1/f.
- Red bends least, violet most.
- Myopia : concave; hypermetropia : convex.
- Telescope m = f₀/f_e; compound microscope m = (L/f₀)(D/f_e).
Mirror → Snell → TIR → lens → prism → eye → instruments.