Rational numbers and their decimal forms
1 ÷ 4 = 0.25 stops quickly, but 1 ÷ 3 = 0.333... never stops. The denominator decides whether a fraction's decimal stops or repeats.
The decimal form of a rational number is either terminating (संपणारा) or non-terminating recurring (न संपणारा पुनरावृत्त).
Rule 1: Properties of rationals — For rational numbers a, b, c, addition and multiplication are commutative (a + b = b + a), associative, have an identity (0 for addition, 1 for multiplication) and an inverse (−a for addition; 1a for multiplication, a ≠ 0).
- Easy : Easy: 3 + 5 = 5 + 3.
- Medium : Medium: The additive inverse of 27 is −27.
- Exam-type : Exam: The multiplicative inverse of 38 is 83; check 38 × 83 = 1.
Rule 2: Terminating or recurring? — Reduce the fraction and look at the denominator's prime factors. Only 2 or 5 → terminating: 720 = 0.35 (20 = 2 × 2 × 5), 316 = 0.1875. Any other prime factor → recurring: 512 = 0.41666... (12 = 2 × 2 × 3), 47 = 0.571428571428...
In the figure : In the figure look at the prime factors of the denominator: only 2 or 5 means terminating; any other prime factor means non-terminating recurring.
- Easy : Easy: 18 = 0.125 terminates (8 = 2 × 2 × 2).
- Medium : Medium: 215 recurs, since 15 has the factor 3.
- Exam-type : Exam: Which terminates: 940 or 942? 40 = 2 × 2 × 2 × 5, so 940 = 0.225.
Rule 3: Recurring decimal to fraction — Multiply by 10, 100 or 1000 by the number of recurring digits, then subtract. x = 0.444...: 10x − x = 4, so x = 49. x = 0.2323...: 100x − x = 23, so x = 2399. x = 2.1515...: 100x − x = 213, so x = 21399 = 7133.
- Easy : Easy: 0.111... = 19.
- Medium : Medium: 0.666... = 69 = 23.
- Exam-type : Exam: Write 0.4545... as a fraction: 100x − x = 45, x = 4599 = 511.
Denominator only 2, 5 → terminating. Otherwise recurring.
Testing an unreduced fraction. 615 = 25 terminates even though 15 has 3.
Memory clue: "फक्त 2 आणि 5 = थांबतो".
Spot the difference
| Fraction | Denominator factors | Decimal |
|---|---|---|
| 720 | 2, 2, 5 | 0.35 (terminating |
| 512 | 2, 2, 3 | 0.41666... (recurring |
| 47 | 7 | 0.571428... (recurring |
Practice questions
- 1What are the two decimal forms of a rational number?
- 2Additive identity?
- 3Multiplicative identity?
- 4Decimal form of 316?
- 5Does 730 terminate?
- 6Write 0.333... as a fraction.
- 7Write 0.8181... as a fraction.
- 8Write 3.7777... as a fraction.
Show answers (try them yourself first)
- 1Terminating and non-terminating recurring.
- 20.
- 31.
- 40.1875.
- 5No, 30 has the factor 3.
- 613.
- 7100x − x = 81, x = 8199 = 911.
- 810x − x = 34, x = 349.
Irrational and real numbers
A square tile with side 1 m has a diagonal that cannot be written as a fraction of metres. Numbers like this need a new family.
An irrational number (अपरिमेय संख्या) cannot be written as pq; its decimal is non-terminating, non-recurring. Rational and irrational numbers together are real numbers (वास्तव संख्या).
Rule 1: √2 is irrational — Proof by contradiction: suppose √2 = pq with p, q having no common factor except 1. Then 2q2 = p2, so p is even; then q is even too, contradicting the assumption. Likewise √3, √5 and √7 are irrational. √2 = 1.41421..., √3 = 1.732...
In the figure : In the figure real numbers are either rational or irrational.
- Easy : Easy: √2 is irrational.
- Medium : Medium: √9 = 3 is rational.
- Exam-type : Exam: Is 0.101001000... rational? No, it does not repeat.
Rule 2: Real numbers and π — Every point on the number line is a unique real number, and every real number is a unique point. Every rational number is real, but not conversely (√2, π, 3 + √2 are not rational). π = circumference ÷ diameter is irrational, about 227 or 3.14. Aryabhat (499 CE) took π = 6283220000 = 3.1416.
In the figure : In the figure irrational numbers such as √2 and π also have their own places on the number line.
- Easy : Easy: π is irrational.
- Medium : Medium: 227 is only an approximation of π.
- Exam-type : Exam: Who used π = 3.1416 in 499 CE? Aryabhat.
Rule 3: Rules — A rational ± an irrational is irrational (3 + √5). A non-zero rational × or ÷ an irrational is irrational (2√3). But two irrationals can give a rational: √2 × √2 = 2, √3 + (−√3) = 0; or an irrational: √2 + √3.
Irrational and real numbers
In the app you can move this figure with your finger.
Open in the app- Easy : Easy: 5 + √2 is irrational.
- Medium : Medium: 4 × √3 is irrational.
- Exam-type : Exam: Give two irrationals whose product is rational. √5 and √5 give 5.
Irrational: non-terminating, non-recurring. Rational ± irrational = irrational.
Thinking 227 equals π. It is only close.
Memory clue: "परिमेय + अपरिमेय = वास्तव".
Spot the difference
| Type | Decimal | Example |
|---|---|---|
| Rational | Terminating or recurring | 38, 0.333... |
| Irrational | Non-terminating, non-recurring | √2, π |
| Real | Both | Every number-line point |
Practice questions
- 1What is an irrational number?
- 2Decimal form of an irrational number?
- 3Is √16 irrational?
- 4Name a famous irrational constant.
- 5Is 2 + √7 rational?
- 6Is √5 × √5 rational?
- 7Classify: 0.5, √10, 73, 0.2020020002....
- 8Why does the proof for √2 start by assuming it is rational?
Show answers (try them yourself first)
- 1A number that cannot be written as pq.
- 2Non-terminating, non-recurring.
- 3No, it equals 4.
- 4π.
- 5No, irrational.
- 6Yes, it is 5.
- 7Rational, irrational, rational, irrational.
- 8To reach a contradiction, which shows the assumption is false.
Surds, simplest form, like surds and comparison
The number √50 looks complicated, but 50 = 25 × 2 lets us write it as 5√2, which is much easier to compare and add.
A surd (करणी) is an irrational root of a positive rational number, written n√a.
Rule 1: What is a surd — In n√a, √ is the radical sign, n the order and a the radicand. ∛7 and ∜8 are surds; ∛27 = 3 and ∛8 = 2 are not, as they are rational. Order 2 surds are quadratic surds. The square root of a negative real number is not real.
In the figure : In the figure a surd is an irrational root of a positive rational number.
- Easy : Easy: √3 is a surd.
- Medium : Medium: ∛27 = 3 is not a surd.
- Exam-type : Exam: Which is a surd: √49, ∛5, ∛64? Only ∛5.
Rule 2: Simplest form and comparing — √72 = √36 × √2 = 6√2; √200 = √100 × √2 = 10√2; √75 = 5√3. Surds with equal order and equal radicand (in simplest form) are like surds (सजातीय करणी): √12 = 2√3 and √27 = 3√3. To compare, compare squares: (4√3)2 = 48 > 45 = (3√5)2, so 4√3 > 3√5; (5√2)2 = 50 > 49, so 5√2 > 7.
- Easy : Easy: √18 = 3√2.
- Medium : Medium: √12 and √27 are like surds.
- Exam-type : Exam: Compare 6√2 and 5√3: 72 < 75, so 6√2 < 5√3.
Simplify first (take out squares). Compare by squaring.
Calling √4 a surd. It equals 2, which is rational.
Memory clue: "वर्ग बाहेर काढा, मग तुलना".
Spot the difference
| Surd | Simplest form |
|---|---|
| √72 | 6√2 |
| √200 | 10√2 |
| √75 | 5√3 |
Practice questions
- 1What is a surd?
- 2What is the order in 3√5?
- 3Simplify √48.
- 4Simplify √98.
- 5Are 2√5 and 7√5 like surds?
- 6Which is greater: 3√5 or 4√3?
- 7Simplify √128.
- 8Why do we compare squares to compare surds?
Show answers (try them yourself first)
- 1An irrational root of a positive rational number.
- 23.
- 34√3.
- 47√2.
- 5Yes.
- 64√3, as 48 > 45.
- 7√64 × √2 = 8√2.
- 8Squaring removes the root and keeps the order for positive numbers.
Operations on surds and rationalizing factors
Like apples and apples add easily, but apples and mangoes don't. Like surds add like apples; unlike surds stay apart.
Only like surds can be added or subtracted; any surds can be multiplied or divided. A rationalizing factor (परिमेयकारक घटक) turns a surd into a rational number.
Rule 1: Add, subtract, multiply, divide — 5√2 + 3√2 = 8√2; 10√3 − 4√3 = 6√3. √18 + √50 − √8 = 3√2 + 5√2 − 2√2 = 6√2. √6 × √15 = √90 = 3√10. √72 ÷ √2 = √36 = 6. √12 × √27 = 2√3 × 3√3 = 18. The product or quotient of surds can be rational.
- Easy : Easy: 4√5 + √5 = 5√5.
- Medium : Medium: √8 + √32 = 2√2 + 4√2 = 6√2.
- Exam-type : Exam: Simplify √45 + √80 − √20 = 3√5 + 4√5 − 2√5 = 5√5.
Rule 2: Rationalizing factor — If the product of two surds is rational, each is a rationalizing factor of the other: √3 × √12 = 6. It is not unique; the simplest for √12 = 2√3 is √3. To remove a root from a denominator: 1√7 = √77; 52√3 = 5√36 (multiply top and bottom by √3).
- Easy : Easy: √5 × √5 = 5.
- Medium : Medium: 3√2 = 3√22.
- Exam-type : Exam: Rationalize 103√5 = 10√515 = 2√53.
Add only like surds. Multiply top and bottom by the rationalizing factor.
Adding √2 + √3 as √5. Unlike surds cannot be combined.
Memory clue: "सजातीय = मिळवा; छेदात करणी = घटकाने गुणा".
Spot the difference
| Operation | Example |
|---|---|
| Add like surds | 5√2 + 3√2 = 8√2 |
| Multiply | √6 × √15 = 3√10 |
| Divide | √72 ÷ √2 = 6 |
| Rationalize | 1√7 = √77 |
Practice questions
- 1Can we add √2 and √3 to get one surd?
- 26√7 − 2√7 = ?
- 3√6 × √6 = ?
- 4√50 ÷ √2 = ?
- 5Rationalize 1√7.
- 6Simplest rationalizing factor of √12?
- 7Simplify √12 × √27.
- 8Why is a rationalizing factor not unique?
Show answers (try them yourself first)
- 1No, they are unlike surds.
- 24√7.
- 36.
- 4√25 = 5.
- 5√77.
- 6√3.
- 72√3 × 3√3 = 18.
- 8Any multiple that still gives a rational product works.
Binomial surds, conjugates and absolute value
A shop price tag of ₹ (√5 + √3) is odd, but multiplying by its "mirror" (√5 − √3) gives plain 2. Such mirrors are called conjugates.
Surds like √5 + √3 are binomial surds; (√a + √b) and (√a − √b) are conjugates (संयुग) with product a − b. ∣x∣ is the absolute value (निरपेक्ष मूल्य).
Rule 1: Conjugates — (√a + √b)(√a − √b) = a − b, which is rational. (√7 + √2)(√7 − √2) = 5; (√6 + √3)(√6 − √3) = 3. The conjugate of 7 + √3 is 7 − √3. Each is the rationalizing factor of the other.
In the figure : In the figure multiplying by the conjugate removes the root from the denominator.
- Easy : Easy: Conjugate of 3 + √2 is 3 − √2.
- Medium : Medium: (√5 + 1)(√5 − 1) = 5 − 1 = 4.
- Exam-type : Exam: Rationalize 1(√7 − √2) = (√7 + √2)5.
Rule 2: Rationalizing with conjugates — 6(√5 + √2): multiply top and bottom by (√5 − √2). The denominator becomes 5 − 2 = 3. So the value is 6(√5 − √2)3 = 2√5 − 2√2.
In the figure : In the figure absolute value is a distance, so it is never negative.
- Easy : Easy: ∣−7∣ = 7.
- Medium : Medium: ∣4 − 9∣ = 5.
- Exam-type : Exam: ∣x − 3∣ = 4 gives x = 7 or x = −1.
Rule 3: Absolute value — ∣x∣ is the distance of x from zero: ∣x∣ = x if x > 0, ∣0∣ = 0, ∣x∣ = −x if x < 0. It is never negative. ∣x + 2∣ = 5 gives x + 2 = 5 or x + 2 = −5, so x = 3 or x = −7.
- Easy : Easy: ∣5∣ = 5.
- Medium : Medium: ∣−2.5∣ = 2.5.
- Exam-type : Exam: Solve ∣2x − 1∣ = 7: 2x − 1 = 7 or −7, so x = 4 or x = −3.
Conjugates multiply to a − b. ∣x∣ is a distance, never negative.
Writing ∣−3∣ = −3. It is 3.
Memory clue: "चिन्ह उलट = संयुग".
Spot the difference
| Expression | Conjugate | Product |
|---|---|---|
| √5 + √3 | √5 − √3 | 2 |
| 7 + √3 | 7 − √3 | 46 |
| √7 + √2 | √7 − √2 | 5 |
Practice questions
- 1What is the conjugate of √5 + √3?
- 2(√a + √b)(√a − √b) = ?
- 3Product of (√6 + √3)(√6 − √3)?
- 4∣−9∣ = ?
- 5Can ∣x∣ be negative?
- 6Solve ∣x − 5∣ = 2.
- 7Rationalize 1(√5 − √3).
- 8Find (7 + √3)(7 − √3).
Show answers (try them yourself first)
- 1√5 − √3.
- 2a − b.
- 33.
- 49.
- 5No.
- 6x = 7 or x = 3.
- 7(√5 + √3)2.
- 849 − 3 = 46.
Quick revision
- Terminating decimal: denominator has only 2 and 5 as prime factors. Irrational numbers have non-terminating, non-recurring decimals.
- A surd is an irrational root of a positive rational number; like surds can be added and subtracted.
- (√a + √b)(√a − √b) = a − b is rational; the conjugate is the rationalizing factor; ∣x∣ is never negative.