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CBSE · Class 11 · Physics

Chapter 1: Units and Measurement

5 concepts · Free to read

SI units and the seven base quantities

From daily life

A tailor measures in centimetres, a shopkeeper in kilograms, a cricket scorer in overs — every answer is a number together with a unit. Link to earlier classes : the units of length, mass and time from classes 9-10 now become one complete worldwide system.

Simple definition

A unit is an agreed reference standard used to compare a quantity; a measurement = number × unit. The SI system (International System of Units) gives every quantity one common language, built on 7 base units.

Radian: arc equals radiusθrs = rθ = s ÷ r1 rad ≈ 57.3°2π rad = 360°when arc s = radius r, the angle is 1 radian

In the figure : When the arc is as long as the radius, the angle at the centre is exactly 1 radian.

Rule 1: Base and derived units — The 7 base quantities and units are : length (m), mass (kg), time (s), electric current (A), temperature (K), amount of substance (mol), luminous intensity (cd). Every other unit is a derived unit made from these, e.g. newton = kg m s⁻², joule = N m = kg m² s⁻².

  • Easy : Speed is measured in m s⁻¹, so it is a derived unit.
  • Medium : Convert 72 km/h to m/s : 72 × 1000 ÷ 3600 = 20 m/s.
  • Exam : Express 1 dyne in newton (1 dyne = 1 g cm s⁻²). Step 1 : 1 g = 10⁻³ kg and 1 cm = 10⁻² m. Step 2 : 1 dyne = 10⁻³ × 10⁻² kg m s⁻² = 10⁻⁵ N.

Rule 2: Plane angle and solid angle — θ = s ÷ r (s = arc length, r = radius) is measured in radian (rad); Ω = A ÷ r² (A = area cut on a sphere of radius r) is measured in steradian (sr). Both are dimensionless. A full circle = 2π rad; a full sphere = 4π sr.

  • Easy : Arc 6 cm on a circle of radius 4 cm ⇒ θ = 6 ÷ 4 = 1.5 rad.
  • Medium : 90° = 90 × π ÷ 180 = π ÷ 2 = 1.571 rad.
  • Exam : A 2 m² patch on a sphere of radius 5 m subtends Ω = 2 ÷ 25 = 0.08 sr.

Rule 3: Modern definitions and prefixes — Since 2019 SI units are fixed by giving exact values to natural constants (speed of light, Planck constant, elementary charge, Boltzmann constant, Avogadro number and others), so the units never drift. Prefixes : kilo 10³, mega 10⁶, giga 10⁹, milli 10⁻³, micro 10⁻⁶, nano 10⁻⁹, pico 10⁻¹².

  • Easy : 2.5 GHz = 2.5 × 10⁹ Hz.
  • Medium : Light of wavelength 450 nm = 450 × 10⁻⁹ m = 4.5 × 10⁻⁷ m.
  • Exam : 3 mm² in m² : 1 mm = 10⁻³ m ⇒ 1 mm² = 10⁻⁶ m² ⇒ 3 mm² = 3 × 10⁻⁶ m².
Remember

7 base units; all others are derived; rad and sr are dimensionless; a prefix is squared when the unit is squared.

Common mistake

Writing 1 mm² = 10⁻³ m². The prefix is squared too, so 1 mm² = 10⁻⁶ m².

Shortcut

Memory clue : "My Kind Student Always Keeps Many Candies" = metre, kilogram, second, ampere, kelvin, mole, candela.

Spot the difference

PropertyBase unitDerived unit
Number in SI7many
Made fromdefined on its owncombination of base units
Examplem, kg, sN, J, W, Pa
Dimensionone base quantityproduct of powers

Significant figures

From daily life

A kitchen scale shows 250 g, a jeweller's balance shows 250.00 g — the second reading tells you the weight to a much finer level. Link to earlier classes : rounding off decimals in classes 8-10 now becomes a way of showing how precise a measurement is.

Simple definition

Significant figures are all the digits that are certain plus the first uncertain digit in a measured value. They show the precision of the instrument.

Rule 1: Counting significant figures — (a) All non-zero digits are significant. (b) Zeros between non-zero digits are significant. (c) Zeros to the left of the first non-zero digit (as in 0.0045) are not significant. (d) Trailing zeros in a number without a decimal point are not significant. (e) Trailing zeros after a decimal point are significant. Changing the unit never changes the count.

  • Easy : 305.2 has 4 significant figures; 0.0045 has 2.
  • Medium : 2.50 m = 250 cm = 0.00250 km — each has 3 significant figures.
  • Exam : How many significant figures in 0.06700 and 4020? 0.06700 : digits 6, 7, 0, 0 ⇒ 4. 4020 : trailing zero with no decimal point is not counted ⇒ 3.

Rule 2: Scientific notation — Write a number as a × 10ᵇ with 1 ≤ a < 10. Every digit written in a is significant, so there is no confusion about trailing zeros. The power of 10 does not affect the count.

  • Easy : 0.000082 = 8.2 × 10⁻⁵ (2 significant figures).
  • Medium : 32000 m may mean 3.2 × 10⁴ m (2 figures) or 3.20 × 10⁴ m (3 figures); notation removes the doubt.
  • Exam : A rod is 4.700 m long. In mm it is 4700 mm, which looks like 2 figures; the correct way is 4.700 × 10³ mm (4 figures).

Rule 3: Exact numbers — Counted numbers and pure constants in formulae (the 2 in 2πr, the 10 in "10 oscillations", the ½ in ½mv²) are exact and have unlimited significant figures.

  • Easy : 20 swings of a pendulum take 36.4 s ⇒ T = 36.4 ÷ 20 = 1.82 s.
  • Medium : The 20 is exact, so the answer keeps the 3 figures of 36.4 s.
  • Exam : For r = d ÷ 2 with d = 7.40 cm, r = 3.70 cm (3 figures); the 2 never reduces the figures.
Remember

significant figures = certain digits + one uncertain digit; the number of figures shows precision, not size.

Common mistake

Counting leading zeros (0.0045 has 2 figures, not 5), and dropping trailing zeros after a decimal point (2.50 has 3 figures, not 2).

Shortcut

Memory clue : "Leading zeros leave, sandwiched zeros stay, trailing zeros need a decimal point." To count quickly, write in a × 10ᵇ and count the digits in a.

Spot the difference

NumberSignificant figuresReason
0.05603leading zeros out, trailing zero after the point counts
70054zeros between digits count
12002trailing zeros without a point
1200.4the point makes them count
1.200 × 10³4every digit in a counts

Calculations with significant figures, rounding and order of magnitude

From daily life

A calculator shows 2.6437500 for mass ÷ volume, but if the volume was read only to two figures, writing all those digits would pretend an accuracy that does not exist. Link to earlier classes : arithmetic and rounding of earlier classes are now controlled by the least precise reading.

Simple definition

A calculated result can never be more precise than the least precise measurement used in it.

Rule 1: Multiplication and division — Keep as many significant figures as the number with the fewest significant figures.

  • Easy : 8.46 g ÷ 3.2 cm³ = 2.64375 ⇒ 2.6 g cm⁻³ (2 figures).
  • Medium : Area = 12.35 cm × 4.2 cm = 51.87 ⇒ 52 cm² (2 figures).
  • Exam : A cyclist covers 150.0 m in 7.50 s. Fewest figures = 3 ⇒ speed = 150.0 ÷ 7.50 = 20.0 m s⁻¹.

Rule 2: Addition and subtraction — Keep as many decimal places as the number with the fewest decimal places.

  • Easy : 12.45 + 3.2 + 0.067 = 15.717 ⇒ 15.7 (1 decimal place).
  • Medium : 25.6 − 4.32 = 21.28 ⇒ 21.3.
  • Exam : 0.862 − 0.85 = 0.012 ⇒ 0.01. A subtraction of nearly equal numbers loses significant figures.

Rule 3: Rounding off — Look at the first digit to be dropped. If it is more than 5, raise the last kept digit by 1; if it is less than 5, leave it. If it is exactly 5, make the last kept digit even. In long calculations keep one extra digit in the middle steps and round only at the end.

  • Easy : 6.783 → 6.78 (3 figures).
  • Medium : 5.465 → 5.46 (6 is even) but 5.475 → 5.48 (7 is odd, so it is raised).
  • Exam : 2.745 → 2.74 and 2.735 → 2.74, because in both cases the kept digit ends up even.

Rule 4: Order of magnitude — Write the number as a × 10ᵇ. If a ≤ 5 the order of magnitude is b; if a > 5 it is b + 1.

  • Easy : A car of mass 1.2 × 10³ kg has order of magnitude 3.
  • Medium : Height 8.8 × 10³ m : a = 8.8 > 5 ⇒ order 4.
  • Exam : An atom of diameter 2 × 10⁻¹⁰ m (order −10) compared with a 1 mm grain of sand, 10⁻³ m (order −3) : sand is larger by −3 − (−10) = 7 orders of magnitude.
Remember

× and ÷ : count significant figures; + and − : count decimal places; round to even when the dropped digit is exactly 5.

Common mistake

Applying the "significant figures" rule to addition (it needs decimal places), and writing every digit shown by the calculator.

Shortcut

Memory clue : "Times-divide — Figures; Plus-minus — Places." Both start with the same letter pair: T-F and P-P.

Spot the difference

OperationRuleExample result
Multiply or dividefewest significant figures2.6 g cm⁻³
Add or subtractfewest decimal places15.7
Order of magnitudea ≤ 5 → b, a > 5 → b + 18.8 × 10³ → 4

Dimensions and dimensional formulae

From daily life

Whether a road is measured in kilometres or in miles, it is still "a length". The word dimension names the kind of quantity, not the unit. Link to earlier classes : units of area and volume (cm², m³) now become a general language for every quantity.

Simple definition

The dimensions of a quantity are the powers to which the base quantities must be raised to represent it. The base quantities are written in square brackets : [M] mass, [L] length, [T] time, [A] current, [K] temperature, [mol] amount, [cd] luminous intensity. The expression is the dimensional formula; setting it equal to the quantity gives the dimensional equation.

Rule 1: Writing a dimensional formula — Start from the simplest defining formula and replace each quantity by its dimensions. Common ones : velocity [L T⁻¹]; acceleration [L T⁻²]; force [M L T⁻²]; work and energy [M L² T⁻²]; power [M L² T⁻³]; pressure [M L⁻¹ T⁻²]; density [M L⁻³]; momentum [M L T⁻¹]; frequency [T⁻¹].

  • Easy : Volume = length × length × length ⇒ [L³].
  • Medium : Pressure = force ÷ area = [M L T⁻²] ÷ [L²] = [M L⁻¹ T⁻²].
  • Exam : From F = G m₁ m₂ ÷ r², G = F r² ÷ (m₁ m₂) = [M L T⁻²][L²] ÷ [M²] = [M⁻¹ L³ T⁻²].

Rule 2: Dimensionless quantities — Pure numbers, ratios of two like quantities (angle, strain, refractive index, relative density) and the arguments of sin, cos, log and exponential have no dimensions.

  • Easy : Angle = arc ÷ radius = [L] ÷ [L] ⇒ dimensionless.
  • Medium : In sin(ωt), the argument ωt must be dimensionless, so [ω] = [T⁻¹].
  • Exam : Strain = change in length ÷ original length ⇒ [L] ÷ [L] = dimensionless; so stress and Young's modulus have the same dimensions as pressure.

Rule 3: Dimensions do not identify the quantity — Different quantities can share a dimension (work and torque are both [M L² T⁻²]; frequency and angular speed are both [T⁻¹]), so a dimension alone cannot tell which quantity it is.

  • Easy : Energy and work have the same dimensions [M L² T⁻²].
  • Medium : Torque = force × distance = [M L T⁻²][L] = [M L² T⁻²], same as work, yet they are different quantities.
  • Exam : Dimension of power = work ÷ time = [M L² T⁻²] ÷ [T] = [M L² T⁻³].
Remember

dimensions depend on the kind of quantity, not on the unit; force = [M L T⁻²]; angle, strain and refractive index are dimensionless.

Common mistake

Confusing unit with dimension (kg is a unit; [M] is a dimension), and forgetting that a numerical factor like ½ or 2π has no dimension.

Shortcut

Memory clue : "Everything is built from force." Remember [M L T⁻²] and build the rest : work = force × length, pressure = force ÷ area, power = work ÷ time.

Spot the difference

PropertyUnitDimension
What it givessize of the standardkind of quantity
Changes with systemyes (m, cm, ft)no
Example for forcenewton, dyne[M L T⁻²]

Dimensional analysis and its uses

From daily life

If a recipe says "add 5 kg of salt to a cup of water", you know at once that something is wrong. Dimensions give the same quick check for formulae. Link to earlier classes : the habit of checking units in classes 9-10 becomes a systematic method.

Simple definition

Principle of homogeneity : only quantities with the same dimensions can be added, subtracted or equated, so every term of a correct equation has the same dimensions.

Rule 1: Checking an equation — Write the dimensions of every term. If they differ, the equation is wrong. If they match, it may be right, but this is not a proof.

  • Easy : s = ut + ½at² : [L] = [L T⁻¹][T] + [L T⁻²][T²] = [L] + [L] — consistent.
  • Medium : v = u + at² : [L T⁻¹] against [L T⁻²][T²] = [L]. Not equal ⇒ the equation is wrong.
  • Exam : P = ½ρv² + ρgh as pressure. ½ρv² : [M L⁻³][L² T⁻²] = [M L⁻¹ T⁻²]; ρgh : [M L⁻³][L T⁻²][L] = [M L⁻¹ T⁻²]; both equal pressure — consistent.

Rule 2: Deriving a relation — If a quantity depends on up to three others as a product, write it as k aˣ bʸ cᶻ (k = pure number), equate dimensions on both sides and solve for the powers.

  • Easy : Speed of a wave on a string depends on tension F [M L T⁻²] and mass per unit length μ [M L⁻¹] : v = k Fˣ μʸ. Mass : x + y = 0; length : x − y = 1; time : −2x = −1 ⇒ x = ½, y = −½ ⇒ v = k √(F ÷ μ).
  • Medium : Centripetal force F depends on m [M], v [L T⁻¹] and r [L] : F = k mᵃ vᵇ rᶜ. Mass : a = 1; time : −b = −2 ⇒ b = 2; length : b + c = 1 ⇒ c = −1 ⇒ F = k m v² ÷ r.
  • Exam : Time period T of a mass m on a spring of stiffness κ [M T⁻²] : T = k mˣ κʸ. Mass : x + y = 0; time : −2y = 1 ⇒ y = −½, x = ½ ⇒ T = k √(m ÷ κ).

Rule 3: Converting units — Use n₁u₁ = n₂u₂ together with the dimensional formula.

  • Easy : 5 N in dyne : 5 kg m s⁻² = 5 × 10³ g × 10² cm s⁻² = 5 × 10⁵ dyne.
  • Medium : 1 J in erg (1 erg = 1 g cm² s⁻²) : 1 kg m² s⁻² = 10³ g × 10⁴ cm² s⁻² = 10⁷ erg.
  • Exam : A pressure of 1 N m⁻² in dyne cm⁻² : [M L⁻¹ T⁻²] ⇒ 1 kg m⁻¹ s⁻² = 10³ g ÷ 10² cm ÷ s² = 10 dyne cm⁻².

Limits of the method : It cannot give pure numbers such as ½ or 2π (so k stays unknown); it cannot tell apart quantities with the same dimensions; it cannot deal with formulae that are sums of terms (such as s = ut + ½at²) or with trigonometric, logarithmic and exponential functions, and it fails when a quantity depends on more than three others as a simple product.

Remember

a dimensionally wrong equation is certainly wrong; a dimensionally correct equation need not be right.

Common mistake

Treating a consistent check as proof, and trying to find k (such as 2π) by dimensions.

Shortcut

Memory clue : "Fail = false, Pass = maybe." Dimensions can only reject an equation, never confirm it.

Spot the difference

Dimensional analysis canDimensional analysis cannot
check if an equation is consistentprove an equation is correct
derive the form of a relationfind numerical constants like 2π
convert units between systemsseparate quantities with equal dimensions