Adsorption: definition and types
The charcoal in a water filter or gas mask traps smells on its surface; that is adsorption.
Adsorption is accumulation of a substance on the surface of a solid or liquid. Adsorbent provides the surface; adsorbate is what sticks. Absorption is uptake throughout the bulk. Desorption is the reverse.
In the figure : Adsorption versus absorption.
In the figure : Physisorption versus chemisorption.
Rule 1: Physisorption — van der Waals forces; ΔH ≈ 20–40 kJ/mol; reversible; stronger at low T; multilayer; not specific.
- Easy : Charcoal + NH₃ (low T).
- Medium : Silica gel drying air.
- Exam-type : Raising T releases the gas.
Rule 2: Chemisorption — Chemical bonds; ΔH ≈ 40–200 kJ/mol; irreversible; needs activation, higher T; monolayer; specific.
- Easy : H₂ on Ni (in hydrogenation).
- Medium : N₂ on Fe (in the Haber process).
- Exam-type : Physisorption at low T, chemisorption at high T (e.g. H₂ + Ni).
Rule 3: Why is adsorption exothermic? — ΔS < 0 (particles become ordered) and ΔG < 0 ⇒ ΔH = ΔG + TΔS < 0.
- Easy : Physisorption falls as T rises (Le Chatelier).
- Medium : More surface area ⇒ more adsorption.
- Exam-type : Powdered charcoal > a lump.
Reasoning: why is ΔH negative?
- Step 1: Free gas particles → bound on the surface ⇒ ΔS negative.
- Step 2: The process occurs ⇒ ΔG = ΔH − TΔS < 0.
- Step 3: With ΔS negative, ΔH must be even more negative ⇒ exothermic.
CET level (MCQ)
- CET 1) ΔH of physisorption? 1) 20–40 kJ/mol 2) 40–200 kJ/mol 3) > 400 4) zero — Answer: 1).
- CET 2) In adsorption? 1) ΔS > 0 2) ΔS < 0 3) ΔH > 0 4) ΔG > 0 — Answer: 2).
Real-life use: Gas masks, water purification, decolourising sugar, silica gel.
Adsorption = surface; physi 20–40, chemi 40–200; ΔH and ΔS negative.
Swapping adsorption and absorption.
Physisorption falls with T; chemisorption first rises, then falls.
Memory clue: "ad = on the surface, ab = into the bulk".
Spot the difference
| Item | Physi | Chemi |
|---|---|---|
| Force | vdW | chemical bond |
| ΔH | 20–40 | 40–200 |
| Layers | multi | mono |
Practice questions
- 1What is adsorption?
- 2Name adsorbent and adsorbate.
- 3Two differences between physi and chemisorption.
- 4Why is adsorption exothermic?
- 5Why is powdered charcoal more effective?
- 6What is desorption?
- 7Behaviour of H₂ + Ni with T?
- 8Use of silica gel?
Show answers (try them yourself first)
- 1Accumulation of particles on a surface.
- 2Charcoal / gas.
- 3Force and ΔH (or reversibility).
- 4ΔS < 0 and ΔG < 0.
- 5More surface area.
- 6Release of adsorbed particles.
- 7Physi at low T, chemi at high T.
- 8Drying air or gases.
Factors affecting adsorption and the Freundlich isotherm
In a crowded bus extra riders must stand; similarly a surface fills up and adsorption saturates.
An isotherm plots amount adsorbed (x/m) against pressure P at constant T. Freundlich: x/m = k·P^(1/n), where x = mass of gas adsorbed and m = mass of adsorbent.
In the figure : Freundlich isotherm and its log plot.
Factors affecting adsorption and the Freundlich isotherm
In the app you can move this figure with your finger.
Open in the appRule 1: Factors — Nature of adsorbate (easily liquefiable gases adsorb more); surface area ↑; pressure ↑ (to saturation); temperature ↑ ⇒ physisorption ↓.
- Easy : NH₃, SO₂ adsorb more; H₂, N₂ less.
- Medium : Activated charcoal is best.
- Exam-type : x/m falls as T rises.
Rule 2: Freundlich equation — log(x/m) = log k + (1/n) log P; slope = 1/n, intercept = log k. Low P: x/m ∝ P; high P: x/m ≈ constant.
- Easy : k = 2, 1/n = 0.5, P = 4 ⇒ x/m = 2 × 2 = 4.
- Medium : log k = 0.3 ⇒ k ≈ 2.
- Exam-type : P = 9 ⇒ x/m = 2 × 3 = 6.
Rule 3: Limitations — Freundlich is empirical and fails at very high pressure. Langmuir assumes a monolayer and gives saturation.
- Easy : 1/n = 0 ⇒ x/m constant (saturated).
- Medium : 1/n = 1 ⇒ x/m ∝ P.
- Exam-type : n > 1 so 1/n < 1.
Calculation: k and 1/n from the graph
- Step 1: log(x/m) against log P is a straight line.
- Step 2: slope = 1/n = 0.5; intercept = 0.3.
- Step 3: k = 10^0.3 ≈ 2; P = 4 ⇒ x/m = 2 × 4^0.5 = 4.
CET level (MCQ)
- CET 1) Slope of log(x/m) against log P? 1) n 2) 1/n 3) k 4) log k — Answer: 2).
- CET 2) k = 2, 1/n = 0.5, P = 9: x/m? 1) 3 2) 4 3) 6 4) 18 — Answer: 3).
Real-life use: Industrial gas purification, choosing charcoal filters.
slope 1/n; intercept log k; 0 < 1/n < 1; T ↑ physi ↓.
Writing the slope as n; it is 1/n.
Use log₁₀ and note 1/n = 0.5 is a square root.
Memory clue: "slope = one over n".
Spot the difference
| P | x/m |
|---|---|
| low | ∝ P |
| medium | ∝ P^(1/n) |
| high | constant |
Practice questions
- 1What is an isotherm?
- 2Write the Freundlich equation.
- 3How do you get k from the graph?
- 4k = 2, 1/n = 0.5, P = 4: x/m?
- 5Why does physisorption fall as T rises?
- 6Why is NH₃ adsorbed more?
- 7Meaning of 1/n = 0?
- 8Langmuir versus Freundlich.
Show answers (try them yourself first)
- 1x/m against P at constant T.
- 2x/m = k P^(1/n).
- 3Intercept = log k.
- 44.
- 5The process is exothermic.
- 6It is easily liquefied.
- 7x/m is constant.
- 8Langmuir assumes a monolayer.
Catalysis: homogeneous, heterogeneous and enzymes
A spoonful of curd turns milk into curd faster; it acts like a catalyst.
A catalyst speeds up a reaction, is unchanged at the end, and lowers activation energy; ΔH and K are unchanged. Enzymes are biological catalysts (proteins).
In the figure : Homogeneous, heterogeneous and enzyme catalysis.
Catalysis: homogeneous, heterogeneous and enzymes
In the app you can move this figure with your finger.
Open in the appRule 1: Types — Homogeneous: same phase; heterogeneous: different phases (adsorption on the surface).
- Easy : 2SO₂ + O₂ →(NO) 2SO₃: homogeneous.
- Medium : N₂ + 3H₂ →(Fe) 2NH₃: heterogeneous.
- Exam-type : Autocatalysis: KMnO₄ + oxalic acid (Mn²⁺).
Rule 2: Steps of heterogeneous catalysis — Diffusion → adsorption → surface reaction → desorption → diffusion of products. Promoters enhance; poisons reduce activity.
- Easy : Mo promotes Fe.
- Medium : As and S compounds poison Pt.
- Exam-type : More catalyst surface ⇒ faster.
Rule 3: Enzymes — Highly specific (lock-and-key / induced fit); optimum T ≈ 310 K and pH; E + S ⇌ ES → E + P.
- Easy : Starch + amylase → maltose.
- Medium : Urea + urease → NH₃ + CO₂.
- Exam-type : High T denatures the enzyme.
Why does a catalyst not change K?
- Step 1: It lowers Eₐ of both forward and reverse reactions.
- Step 2: Both rates rise by the same factor.
- Step 3: K = k₁/k₂ stays the same; equilibrium is just reached sooner.
CET level (MCQ)
- CET 1) Catalysis in the Haber process is? 1) homogeneous 2) heterogeneous 3) enzymatic 4) auto — Answer: 2).
- CET 2) A catalyst does not change? 1) Eₐ 2) rate 3) ΔH 4) mechanism — Answer: 3).
Real-life use: Catalytic converters (Pt/Pd), digestive enzymes, industrial Ni and Fe.
Eₐ ↓; ΔH, K same; heterogeneous = adsorption; enzyme at 310 K.
Writing that a catalyst raises K.
A promoter is not itself the catalyst; it helps the catalyst.
Memory clue: "catalyst = speed only".
Spot the difference
| Item | Homogeneous | Heterogeneous |
|---|---|---|
| Phase | same | different |
| Example | NO | Fe |
Practice questions
- 1What is a catalyst?
- 2An example of homogeneous catalysis.
- 3What is a promoter?
- 4What is a catalytic poison?
- 5Why are enzymes specific?
- 6An example of autocatalysis.
- 7Why doesn't a catalyst change K?
- 8Optimum T for enzymes?
Show answers (try them yourself first)
- 1A substance that raises rate and is unchanged.
- 22SO₂ + O₂ with NO.
- 3One that boosts the catalyst.
- 4One that reduces activity.
- 5The active site has a specific shape.
- 6KMnO₄ + oxalic acid.
- 7Both directions rise equally.
- 8≈ 310 K.
Colloids: classification and properties
Milk, fog, smoke and jelly are colloids; neither a true solution nor a suspension.
Colloid: particle size 1–1000 nm (the textbook text says 2–500 nm; solutions 0.1–2 nm); heterogeneous; dispersed phase in a dispersion medium. Lyophilic (solvent-loving) are stable; lyophobic are unstable.
In the figure : Types of colloids.
In the figure : Tyndall effect and Brownian motion.
Rule 1: Classification — By phase: sol, gel, emulsion, foam, aerosol. By particles: multimolecular (gold sol), macromolecular (starch), associated (soap).
- Easy : Milk: liquid-in-liquid emulsion.
- Medium : Fog: liquid-in-gas aerosol.
- Exam-type : Jelly: liquid-in-solid gel.
Rule 2: Optical and kinetic properties — Tyndall effect: particles scatter light ⇒ visible beam. Brownian motion: medium molecules bombard particles ⇒ zigzag; keeps the sol stable.
- Easy : Sunbeams visible through a misty forest.
- Medium : True solution: no Tyndall effect.
- Exam-type : Dust shows Brownian motion.
Rule 3: Electrical properties — Colloidal particles carry a like charge ⇒ mutual repulsion ⇒ stability. Electrophoresis: particle movement in an electric field.
- Easy : As₂S₃ is negative; Fe(OH)₃ is positive.
- Medium : Fe(OH)₃ sol moves to the cathode.
- Exam-type : Blood purification (dialysis).
Classification by particle size
- Step 1: < 1 nm ⇒ true solution.
- Step 2: 1–1000 nm ⇒ colloid.
- Step 3: > 1000 nm ⇒ suspension.
CET level (MCQ)
- CET 1) Colloidal particle size? 1) < 1 nm 2) 1–1000 nm 3) > 1 μm 4) 10 μm — Answer: 2).
- CET 2) Milk is a? 1) sol 2) emulsion 3) gel 4) foam — Answer: 2).
Real-life use: Paints, inks, medicines, fog, dairy processing.
1–1000 nm; Tyndall; Brownian; like charge ⇒ stable.
Calling a colloid a true solution; it is heterogeneous.
Milk = emulsion; jelly = gel (liquid dispersed in solid).
Memory clue: "one to one-thousand nm".
Spot the difference
| Type | Size | Tyndall |
|---|---|---|
| Solution | < 1 nm | no |
| Colloid | 1–1000 nm | yes |
| Suspension | > 1000 nm | yes |
Practice questions
- 1What is a colloid?
- 2State the Tyndall effect.
- 3Cause of Brownian motion?
- 4State the type of milk.
- 5Lyophilic versus lyophobic.
- 6What is electrophoresis?
- 7An example of an aerosol.
- 8Why is a colloid stable?
Show answers (try them yourself first)
- 1A heterogeneous system with 1–1000 nm particles.
- 2Particles scatter light.
- 3Medium molecules collide.
- 4Emulsion.
- 5Solvent-loving stable; solvent-hating unstable.
- 6Particle movement in an electric field.
- 7Fog or smoke.
- 8Like charge; Brownian motion.
Preparation and purification of colloids
Buttermilk and fridge fog show how colloids form and break.
Preparation: (1) condensation — joining small particles, (2) dispersion — breaking large ones. Purification: removing ions — dialysis, ultrafiltration, ultracentrifugation.
Rule 1: Condensation methods — Double decomposition: As₂O₃ + 3H₂S → As₂S₃ sol + 3H₂O; oxidation: SO₂ + 2H₂S → 3S sol + 2H₂O; hydrolysis: FeCl₃ + 3H₂O → Fe(OH)₃ sol + 3HCl.
- Easy : FeCl₃ in hot water gives a reddish sol.
- Medium : As₂S₃ is a yellow sol.
- Exam-type : Sulphur sol is milky.
Rule 2: Dispersion methods — Bredig's arc: electric arc between metal electrodes under water ⇒ metal sol. Peptization: a little electrolyte turns a fresh precipitate into a sol.
- Easy : Fe(OH)₃ precipitate + a little FeCl₃ ⇒ sol.
- Medium : Au, Ag, Pt sols by arc.
- Exam-type : Colloid mill: mechanical dispersion.
Rule 3: Purification — Dialysis: semipermeable membrane lets small ions out; ultrafiltration: special filters; ultracentrifugation: very fast spinning.
- Easy : Kidney dialysis.
- Medium : Removing HCl from a sol.
- Exam-type : Protein purification by ultracentrifugation.
Reasoning: how does peptization work?
- Step 1: A fresh precipitate is a clump of particles.
- Step 2: A few ions adsorb on the particles and give them charge.
- Step 3: Like charges repel ⇒ particles separate into a sol.
CET level (MCQ)
- CET 1) Bredig's arc is for? 1) metal sols 2) emulsions 3) gels 4) foams — Answer: 1).
- CET 2) Method for the Fe(OH)₃ sol? 1) hydrolysis 2) oxidation 3) arc 4) centrifugation — Answer: 1).
Real-life use: Paints, inks, medicines, dialysis machines.
Condensation and dispersion; Bredig = metals; peptization; dialysis.
Not recognising that peptization is the reverse of coagulation.
Dialysis removes ions, not colloidal particles.
Memory clue: "condense = join, disperse = break".
Spot the difference
| Method | Use |
|---|---|
| Bredig | metal sol |
| Peptization | precipitate → sol |
| Dialysis | purification |
Practice questions
- 1What are condensation methods?
- 2What is Bredig's arc?
- 3What is peptization?
- 4How is the Fe(OH)₃ sol made?
- 5Why is dialysis done?
- 6What is ultracentrifugation?
- 7How is As₂S₃ sol prepared?
- 8How is a sulphur sol prepared?
Show answers (try them yourself first)
- 1Making colloids by joining particles.
- 2Metal sols by electric arc.
- 3Converting a precipitate to a sol.
- 4Hydrolysis of FeCl₃ in hot water.
- 5To remove impurity ions.
- 6Separating by very fast spinning.
- 7As₂O₃ + H₂S.
- 8Oxidation of H₂S by SO₂.
Coagulation, Hardy–Schulze rule and gold number
Squeezing lemon into milk curdles it; that is coagulation.
Coagulation: neutralising the charge on colloidal particles so they clump. Hardy–Schulze: coagulating power rises with the charge of the counter-ion. Gold number: minimum mg of protective colloid that stops coagulation of 10 mL gold sol.
In the figure : Coagulation rule and micelle.
Rule 1: Hardy–Schulze rule — For negative sols: Al³⁺ > Ba²⁺ > Na⁺; for positive sols: [Fe(CN)₆]⁴⁻ > PO₄³⁻ > SO₄²⁻ > Cl⁻.
- Easy : AlCl₃ is the most effective on As₂S₃.
- Medium : K₄[Fe(CN)₆] for Fe(OH)₃.
- Exam-type : Delta formation at river mouths.
Rule 2: Gold number — The smaller the gold number, the better the protective colloid.
- Easy : Gelatin 0.005–0.01; starch 25.
- Medium : Gelatin is a better protector than starch.
- Exam-type : Gelatin in ice cream.
Rule 3: Applications of coagulation — Alum (Al³⁺) clears muddy water; Fe³⁺ stops bleeding; Cottrell precipitator removes smoke particles.
- Easy : Alum + muddy water.
- Medium : Applying alum on a cut.
- Exam-type : Removing ash from factory smoke.
Why is Al³⁺ more effective than Na⁺?
- Step 1: Positive ions are needed to neutralise negative particles.
- Step 2: Al³⁺ carries +3, so fewer ions neutralise the charge.
- Step 3: So a lower concentration suffices (lower flocculation value).
CET level (MCQ)
- CET 1) Most effective on As₂S₃ sol? 1) NaCl 2) BaCl₂ 3) AlCl₃ 4) KCl — Answer: 3).
- CET 2) Best protective colloid has gold number? 1) 25 2) 0.01 3) 5 4) 10 — Answer: 2).
Real-life use: Water clarification, alum on cuts, smoke cleaning, ice cream.
Negative sol ⇒ Al³⁺; positive sol ⇒ [Fe(CN)₆]⁴⁻; small gold number ⇒ better.
Saying a large gold number means more protection; it is the opposite.
The counter-ion has charge opposite to the sol.
Memory clue: "bigger charge, bigger coagulation".
Spot the difference
| Sol | Best ion |
|---|---|
| As₂S₃ (−) | Al³⁺ |
| Fe(OH)₃ (+) | [Fe(CN)₆]⁴⁻ |
Practice questions
- 1What is coagulation?
- 2State the Hardy–Schulze rule.
- 3What is the gold number?
- 4Why does alum clear water?
- 5How does a delta form?
- 6Compare gold numbers of gelatin and starch.
- 7Best ion for Fe(OH)₃?
- 8What does a Cottrell precipitator do?
Show answers (try them yourself first)
- 1Particles lose charge and settle.
- 2Higher counter-ion charge, stronger coagulation.
- 3Minimum mg of protective colloid for 10 mL gold sol.
- 4Al³⁺ neutralises the mud particles.
- 5Sea ions coagulate river silt.
- 6Gelatin is smaller ⇒ better.
- 7[Fe(CN)₆]⁴⁻.
- 8It precipitates smoke particles.
Emulsions, micelles and applications of colloids
Soap cleans a greasy plate because its molecules trap oil inside micelles.
An emulsion is one liquid dispersed in another (oil/water). An emulsifier stabilises it. A micelle is an associated colloid of soap or detergent that forms above the CMC (critical micelle concentration).
Rule 1: Types of emulsions — O/W: oil in water (milk); W/O: water in oil (butter, cold cream). Emulsifiers: soap, casein, gelatin.
- Easy : Milk is O/W; butter is W/O.
- Medium : Mayonnaise: egg lecithin.
- Exam-type : Dilution test: mixes with water ⇒ O/W.
Rule 2: Soap and micelles — Soap RCOO⁻Na⁺: hydrophobic tail + hydrophilic head; in a micelle the oil sits inside and the heads face out. Micelles form only above a certain temperature (the Kraft temperature).
- Easy : For soaps CMC ≈ 10⁻⁴–10⁻³ mol/L.
- Medium : Micelle size is colloidal.
- Exam-type : Soap lathers poorly in hard water (Ca²⁺ precipitate).
Rule 3: Applications — Medicines (colloidal silver), rubber latex, tanning leather, artificial rain, smoke removal, food processing.
- Easy : Tanning: coagulation of the colloid.
- Medium : Cloud seeding: AgI particles in clouds.
- Exam-type : Coagulating latex gives rubber.
Why do micelles form only above the CMC?
- Step 1: At low concentration soap ions sit singly at the surface.
- Step 2: Once the surface is full, tails huddle inside to avoid water.
- Step 3: Above the CMC micelles form and cleaning power rises.
CET level (MCQ)
- CET 1) Butter is which emulsion? 1) O/W 2) W/O 3) sol 4) gel — Answer: 2).
- CET 2) In a micelle the oil is? 1) outside 2) inside 3) in water 4) in air — Answer: 2).
Real-life use: Soap, detergents, butter, medicines, leather, cloud seeding.
Milk O/W; butter W/O; micelles above CMC; oil in, heads out.
Writing that hydrophilic heads face inward; they face outward.
Soap precipitates with Ca²⁺ in hard water; detergents do not.
Memory clue: "tail in, head out".
Spot the difference
| Item | O/W | W/O |
|---|---|---|
| Example | milk | butter |
| Mixes with water | yes | no |
Practice questions
- 1What is an emulsion?
- 2What is an emulsifier?
- 3What is a micelle?
- 4What is the CMC?
- 5How does soap remove grease?
- 6How is artificial rain made?
- 7Why does soap work poorly in hard water?
- 8Emulsion types of milk and butter.
Show answers (try them yourself first)
- 1One liquid dispersed in another.
- 2A substance stabilising an emulsion.
- 3An associated colloid of soap molecules.
- 4Critical micelle concentration.
- 5The grease is trapped inside the micelle.
- 6AgI particles are sprayed into clouds.
- 7Ca²⁺ precipitates the soap.
- 8O/W and W/O.
Quick revision of the whole lesson
| Concept | Key formula / fact |
|---|---|
| Adsorption | surface; physi 20–40, chemi 40–200 kJ/mol |
| Freundlich | x/m = k P^(1/n) |
| Catalyst | Eₐ ↓; ΔH, K same |
| Colloid | 1–1000 nm |
| Preparation | Bredig, peptization |
| Hardy–Schulze | Al³⁺ > Ba²⁺ > Na⁺ |
| Gold number | small ⇒ better |
| Micelle | above CMC; oil in |
🚀 Quick revision of the whole lesson
In the app you can move this figure with your finger.
Open in the app🎯 Most important points for the exam
- Adsorption and types.
- Freundlich isotherm.
- Catalysis and enzymes.
- Colloid classification and properties.
- Preparation and purification.
- Coagulation and gold number.
- Emulsions, micelles, uses.
understand the idea → remember the formula → solve the example → solve problems yourself.