Trigonometric functions on the unit circle
A point moving round a circular track has two coordinates at every moment: how far east and how far north. Those two numbers are cos and sin.
On the unit circle (radius 1, centre at the origin), the point P at angle x has coordinates (cos x, sin x). Then tan x = sin x / cos x (cos x ≠ 0), cosec x = 1/sin x, sec x = 1/cos x, cot x = cos x / sin x.
Formula: cos x = x-coordinate sin x = y-coordinate
In the figure: At 60°, the point is (1/2, √3/2): cos 60° = 1/2 and sin 60° = √3/2.
Rule 1: Read from coordinates — If P(a, b) is on the unit circle at angle x, then cos x = a and sin x = b.
- Easy: P(0, 1): x = 90°, sin = 1, cos = 0.
- Medium: P(−1, 0): x = 180°, sin = 0, cos = −1.
- Exam-type: P(3/5, 4/5): cos x = 3/5, sin x = 4/5, tan x = 4/3.
Rule 2: Reciprocal functions — Flip the value.
- Easy: If sin x = 1/2, cosec x = 2.
- Medium: If cos x = 3/5, sec x = 5/3.
- Exam-type: If tan x = 2/3, cot x = 3/2.
Since the radius is 1: sin²x + cos²x = 1.
Mixing up which coordinate is sin and which is cos. Cos = x (horizontal), Sin = y (vertical).
Alphabetical order: C comes before S, just as x comes before y.
Practice questions
- 1P(1, 0) is at angle 0°. Find sin 0° and cos 0°.
- 2Find tan 45° from P(1/√2, 1/√2).
- 3If sin x = 3/5 and cos x = 4/5, find tan x.
- 4If cos x = 5/13, find sec x.
- 5Check that P(5/13, 12/13) is on the unit circle.
- 6Find cot x if sin x = 12/13 and cos x = 5/13.
- 7If sin x = 0.6 on the unit circle in quadrant I, find cos x.
- 8If cos x = −3/5 in quadrant II, find sin x.
Show answers (try them yourself first)
- 1sin 0° = 0, cos 0° = 1
- 21
- 33/4
- 413/5
- 5(5/13)² + (12/13)² = 25/169 + 144/169 = 169/169 = 1 ✓
- 65/12
- 7√(1 − 0.36) = 0.8
- 84/5
Signs in the four quadrants
North-east, north-west, south-west, south-east: the sign of east–west and north–south positions changes from quarter to quarter.
The signs of sin x and cos x depend on the sign of the y and x coordinates. I: all positive; II: only sin and cosec positive; III: only tan and cot positive; IV: only cos and sec positive.
In the figure: Read the quadrant, then which functions stay positive.
Rule 1: Find the sign — Find the quadrant first.
- Easy: sin 120°: quadrant II, positive.
- Medium: cos 200°: quadrant III, negative.
- Exam-type: tan 300°: quadrant IV, negative.
Rule 2: Reduce to an acute angle — Use the nearest x-axis: 180° − x, x − 180° or 360° − x.
- Easy: sin 150° = sin 30° = 1/2.
- Medium: cos 120° = −cos 60° = −1/2.
- Exam-type: tan 225° = tan 45° = 1.
Quadrant I: All. II: Sin. III: Tan. IV: Cos.
Forgetting the sign when the angle is reduced to an acute one.
All Students Take Chocolates (I: All, II: Sin, III: Tan, IV: Cos).
Practice questions
- 1Sign of sin 250°?
- 2Sign of cos 330°?
- 3Sign of tan 100°?
- 4Find sin 210°.
- 5Find cos 300°.
- 6Find tan 135°.
- 7If sin x > 0 and cos x < 0, in which quadrant is x?
- 8If tan x > 0 and sin x < 0, in which quadrant is x?
Show answers (try them yourself first)
- 1Quadrant III, negative
- 2Quadrant IV, positive
- 3Quadrant II, negative
- 4−sin 30° = −1/2
- 5cos 60° = 1/2
- 6−tan 45° = −1
- 7Quadrant II
- 8Quadrant III
Values for standard angles
A carpenter keeps a set-square with 30°-60° and 45° corners. The numbers they give are used everywhere.
Learn this table; the other values are obtained from it with signs.
Rule 1: Use the table — Read the value and fix the sign by the quadrant.
- Easy: sin 30° = 1/2, cos 60° = 1/2.
- Medium: sin 45° = cos 45° = 1/√2.
- Exam-type: sin 60° = √3/2, tan 60° = √3.
Rule 2: Combine values — Replace each part by its table value.
- Easy: sin 30° + cos 60° = 1/2 + 1/2 = 1.
- Medium: sin²45° + cos²45° = 1/2 + 1/2 = 1.
- Exam-type: tan 60° × tan 30° = √3 × 1/√3 = 1.
sin and cos are swapped between 30° and 60°: sin 30° = cos 60°.
Writing tan 90° = 1. It is not defined, because cos 90° = 0.
sin: 0, 1/2, 1/√2, √3/2, 1 → √0/2, √1/2, √2/2, √3/2, √4/2.
Quick table
| angle | 0° | 30° | 45° | 60° | 90° |
|---|---|---|---|---|---|
| sin | 0 | 1/2 | 1/√2 | √3/2 | 1 |
| cos | 1 | √3/2 | 1/√2 | 1/2 | 0 |
| tan | 0 | 1/√3 | 1 | √3 | not defined |
Practice questions
- 1Find sin 60° × cos 30°.
- 2Find tan 45° + sin 90°.
- 3Find cos 0° + sin 0°.
- 4Find 2 sin 30° + 3 cos 60°.
- 5Find sin 45° × cos 45°.
- 6Find (sin 30° + cos 60°)².
- 7Find the value of 4 tan²45° − sin²60°.
- 8Find cos 60° cos 30° − sin 60° sin 30°.
Show answers (try them yourself first)
- 1(√3/2)(√3/2) = 3/4
- 22
- 31
- 41 + 1.5 = 2.5
- 51/2
- 61
- 74 − 3/4 = 3.25
- 8(1/2)(√3/2) − (√3/2)(1/2) = 0
Domain and range of the six functions
A thermometer reading rises and falls but never goes beyond its maximum and minimum. sin and cos do the same between −1 and 1.
sin x and cos x are defined for every real x and lie between −1 and 1. tan x and sec x are not defined where cos x = 0 (x = π/2, 3π/2, …). cot x and cosec x are not defined where sin x = 0 (x = 0, π, 2π, …). tan x and cot x can take any real value; sec x and cosec x never lie strictly between −1 and 1.
Rule 1: Range — sin and cos: [−1, 1]. tan and cot: R. sec and cosec: (−∞, −1] ∪ [1, ∞).
- Easy: 2 sin x has range [−2, 2].
- Medium: 3 cos x + 1 has range [−2, 4].
- Exam-type: sin x = 2 is impossible.
Rule 2: Period — sin, cos, sec, cosec repeat every 2π; tan and cot repeat every π.
- Easy: sin(x + 2π) = sin x.
- Medium: tan(x + π) = tan x.
- Exam-type: cos 390° = cos 30° = √3/2.
sin²x + cos²x = 1, 1 + tan²x = sec²x, 1 + cot²x = cosec²x.
Saying sin x can be 3/2 for some x.
Sin and Cos live inside the strip [−1, 1].
Practice questions
- 1Is sin x = 1.5 possible?
- 2Find the range of 5 sin x.
- 3Find the range of cos x − 2.
- 4At which x in [0, 2π] is tan x not defined?
- 5Find the range of 4 − 3 sin x.
- 6Find sin 765°.
- 7If sin x = 1/3 in quadrant I, find cos x and tan x.
- 8If tan x = 3/4 in quadrant III, find sin x and cos x.
Show answers (try them yourself first)
- 1No — sin x never exceeds 1.
- 2[−5, 5]
- 3[−3, −1]
- 4π/2 and 3π/2
- 5[1, 7]
- 6765 = 2 × 360 + 45, so sin 45° = 1/√2
- 7cos x = √(1 − 1/9) = 2√2/3, tan x = 1/(2√2)
- 8sin x = −3/5, cos x = −4/5
Basic identities
Like an exchange rate that always holds, an identity is a statement true for every allowed angle.
Because the point (cos x, sin x) lies on the unit circle: sin²x + cos²x = 1. Dividing by cos²x gives 1 + tan²x = sec²x; dividing by sin²x gives 1 + cot²x = cosec²x.
Formula: sin²x + cos²x = 1
Rule 1: Find one ratio from another — Use the identity and fix the sign by the quadrant.
- Easy: sin x = 3/5 (quadrant I): cos²x = 16/25, cos x = 4/5.
- Medium: tan x = 1 (quadrant I): sec x = √2.
- Exam-type: cos x = −1/2 (quadrant II): sin x = √3/2.
Rule 2: Prove an identity — Change everything to sin and cos, then simplify.
- Easy: (1 − sin x)(1 + sin x) = cos²x.
- Medium: sec x − cos x = sin x tan x.
- Exam-type: tan x + cot x = sec x cosec x.
In proofs, work on the more complicated side only.
Cancelling terms across a sum, such as (sin x + cos x)/cos x = sin x + 1 (wrong).
Pythagoras on the unit circle.
Practice questions
- 1Simplify 1 − sin²x.
- 2Simplify sec²x − tan²x.
- 3Simplify (sin x + cos x)² − 2 sin x cos x.
- 4If cos x = 12/13 in quadrant IV, find sin x.
- 5If tan x = −5/12 in quadrant II, find sin x and cos x.
- 6Prove: sin x cosec x = 1.
- 7Simplify (1 + tan²x) cos²x.
- 8Prove: 1/(1 + sin x) + 1/(1 − sin x) = 2 sec²x.
Show answers (try them yourself first)
- 1cos²x
- 21
- 31
- 4−5/13
- 5sin x = 5/13, cos x = −12/13
- 6cosec x = 1/sin x, so the product is 1.
- 7sec²x · cos²x = 1
- 8(1 − sin x + 1 + sin x)/(1 − sin²x) = 2/cos²x