Inequalities and their rules
A lift allows "at most 8 persons"; a bus ticket for children is "below 12 years". Real life uses "less than" and "more than" far more than "equal to".
An inequality compares two quantities with <, >, ≤ or ≥. Linear inequality in one variable has the form ax + b < 0 (or >, ≤, ≥). Rules: (1) adding or subtracting the same number on both sides keeps the sign; (2) multiplying or dividing by a positive number keeps the sign; (3) multiplying or dividing by a negative number reverses the sign.
Formula: a < b ⟹ a + c < b + c; a < b and c < 0 ⟹ ac > bc
Rule 1: Add and subtract — The direction stays the same.
- Easy: x − 4 < 6 gives x < 10.
- Medium: x + 7 ≥ 2 gives x ≥ −5.
- Exam-type: 3 < 5 gives 3 + 2 < 5 + 2, i.e. 5 < 7.
Rule 2: Multiply or divide — Flip the sign when the multiplier is negative.
- Easy: 2x < 10 gives x < 5.
- Medium: −2x < 10 gives x > −5 (sign flips).
- Exam-type: −x ≥ 3 gives x ≤ −3.
Test with numbers: 2 < 3 but −2 > −3, so multiplying by −1 flips the sign.
Forgetting to flip the sign after dividing by a negative number.
Negative number: Not the same sign — flip it.
Practice questions
- 1Solve x + 5 < 9.
- 2Solve 3x ≥ 12.
- 3Solve −x < 7.
- 4Solve −4x ≤ 20.
- 5Solve 2x − 3 > 7.
- 6If a > b, is −a > −b?
- 7If x < −2, then 5 − 3x is greater than what number?
- 8Is it true that if a < b then 1/a > 1/b for positive a, b?
Show answers (try them yourself first)
- 1x < 4
- 2x ≥ 4
- 3x > −7
- 4x ≥ −5
- 5x > 5
- 6No — it flips: −a < −b.
- 7−3x > 6, so 5 − 3x > 11
- 8Yes — e.g. 2 < 4 and 1/2 > 1/4.
Solving a linear inequality
You have ₹500 and each notebook costs ₹30. How many notebooks can you buy? The answer is not one number but a whole range.
Solve like an equation: collect x on one side, numbers on the other, divide by the coefficient (flip the sign if it is negative). The answer is a range of values, drawn on the number line with an open circle for < or > and a filled circle for ≤ or ≥.
In the figure: x > 2: open circle at 2 and the line going right.
Rule 1: One-step and two-step — Do the same on both sides.
- Easy: 3x − 5 ≤ 7 gives 3x ≤ 12, x ≤ 4.
- Medium: 5 − 2x < 1 gives −2x < −4, x > 2.
- Exam-type: 4(x − 1) ≥ 2x + 6 gives 2x ≥ 10, x ≥ 5.
Rule 2: With fractions — Multiply by the common denominator (positive).
- Easy: x/3 + 2 < 4 gives x < 6.
- Medium: (x − 1)/2 ≥ (x + 2)/3 gives 3x − 3 ≥ 2x + 4, x ≥ 7.
- Exam-type: 2x/5 − 1 > 3 gives x > 10.
Check your answer by choosing one number from the solution and one outside.
Using a filled circle for < or >.
Open circle = not allowed, filled = allowed.
Practice questions
- 1Solve 2x + 3 < 11.
- 2Solve 7 − x ≥ 2.
- 3Solve 3(x + 2) > 12.
- 4Solve (2x − 1)/3 ≤ 5.
- 5Solve 5x − 2 < 3x + 8.
- 6Solve x/2 − x/3 ≥ 1.
- 7Solve 6 − 4x > 2(x − 3).
- 8Solve (x + 1)/2 < (2x − 3)/3.
Show answers (try them yourself first)
- 1x < 4
- 2x ≤ 5
- 3x > 2
- 42x − 1 ≤ 15, x ≤ 8
- 52x < 10, x < 5
- 6x/6 ≥ 1, x ≥ 6
- 76 − 4x > 2x − 6, 12 > 6x, x < 2
- 83x + 3 < 4x − 6, so x > 9
Replacement sets and graph of the solution
"Number of notebooks" can only be whole numbers, but "length of a rope" can be any real. The same inequality gives different answer sets.
The solution depends on the replacement set (the allowed values of x): natural numbers N, integers Z or real numbers R. First solve in R, then list or draw only the allowed values.
In the figure: −2 ≤ x ≤ 3: filled circles at both ends of the segment.
Rule 1: Same inequality, different sets — Solve first, then pick.
- Easy: x < 4: in N the solution is {1, 2, 3}.
- Medium: x < 4: in Z it is {…, 0, 1, 2, 3}.
- Exam-type: x < 4: in R it is the interval (−∞, 4).
Rule 2: Double inequality — Work on all three parts at once.
- Easy: −3 < 2x + 1 ≤ 9 gives −4 < 2x ≤ 8, so −2 < x ≤ 4.
- Medium: 1 ≤ 3x − 2 < 7 gives 3 ≤ 3x < 9, so 1 ≤ x < 3.
- Exam-type: −6 ≤ 4 − 2x < 2 gives −10 ≤ −2x < −2, so 1 < x ≤ 5.
Write the solution as an interval or a number-line graph; both are accepted.
Listing real numbers one by one when the replacement set is R.
Solve in R, then filter by the set.
Spot the difference
| x ∈ N | x ∈ R |
|---|---|
| Counting numbers only | Every point on the line |
| Dots on the line | A continuous segment |
Practice questions
- 1Solve x + 2 < 6 for x ∈ N.
- 2Solve 2x − 1 ≤ 5 for x ∈ Z, x ≥ 0.
- 3Solve −2 < x ≤ 3 for x ∈ Z.
- 4Solve −5 ≤ 2x − 1 < 7 and write as an interval.
- 5How many natural numbers satisfy 3x − 4 ≤ 20?
- 6Solve 2 < (3x − 4)/2 ≤ 7.
- 7Find the integers x with 5 < 2x + 1 < 15.
- 8Find all prime numbers p satisfying 2p − 3 < 15.
Show answers (try them yourself first)
- 1x < 4: {1, 2, 3}
- 2x ≤ 3: {0, 1, 2, 3}
- 3{−1, 0, 1, 2, 3}
- 4−4 ≤ 2x < 8, so −2 ≤ x < 4, i.e. [−2, 4)
- 5x ≤ 8: 8 natural numbers
- 64 < 3x − 4 ≤ 14, 8 < 3x ≤ 18, 8/3 < x ≤ 6
- 72 < x < 7: {3, 4, 5, 6}
- 8p < 9: {2, 3, 5, 7}
Inequalities in word problems
Budgets, speed limits, marks to pass: they all give "at least" or "at most" conditions.
Translate words into symbols: "at least" means ≥; "at most" means ≤; "more than" means >; "less than" means <. Let the unknown be x, write the condition, then solve.
Rule 1: Budget — Total cost is at most the money you have.
- Easy: A pen costs ₹12. With ₹100, 12x ≤ 100 gives x ≤ 8, so at most 8 pens.
- Medium: A taxi costs ₹40 plus ₹15 per km; with ₹250: 40 + 15x ≤ 250 gives x ≤ 14 km.
- Exam-type: To get an average of at least 60 in 3 tests with 55 and 62, the third score y satisfies (117 + y)/3 ≥ 60, so y ≥ 63.
Rule 2: Number problems — Form the expression carefully.
- Easy: Three times a number decreased by 4 is more than 11: 3x − 4 > 11, x > 5.
- Medium: The sum of two consecutive odd numbers is more than 40 and the smaller is x: 2x + 2 > 40, x > 19.
- Exam-type: A rectangle's length is 3 m more than its width x and its perimeter is at most 50 m: 4x + 6 ≤ 50, x ≤ 11.
Always check that the answer makes sense (a count cannot be negative or fractional).
Choosing ≤ when the problem says "less than".
At least = floor (≥). At most = ceiling (≤).
Practice questions
- 1A box holds at most 20 kg. Each book weighs 1.5 kg. Write an inequality for the number of books x.
- 2A student needs at least 40 marks. She has 28. Write an inequality for the marks y she still needs.
- 3Solve 2x + 5 < 19 and say how many natural numbers fit.
- 4A phone plan costs ₹200 plus ₹2 per message. For how many messages is the bill at most ₹500?
- 5The marks in two tests are 62 and 71. How many marks are needed in the third test for an average of at least 70?
- 6Find the largest integer x with 4x − 7 < 25.
- 7A rectangle has width 5 m and a perimeter of less than 40 m. What lengths are possible?
- 8Find two consecutive even numbers whose sum is more than 30 with the smaller x; list the smallest pair.
Show answers (try them yourself first)
- 11.5x ≤ 20
- 2y ≥ 12
- 3x < 7: 6 natural numbers
- 4200 + 2x ≤ 500, x ≤ 150
- 5133 + y ≥ 210, y ≥ 77
- 6x < 8, so 7
- 72(l + 5) < 40, l < 15, so 0 < l < 15
- 82x + 2 > 30, x > 14, smallest even x is 16: (16, 18)