Why classify elements? From triads to the modern periodic law
Link to Std 9–10 : You studied Mendeleev's table and the modern table briefly; now we see how the idea of "periodic" properties grew and why atomic number replaced atomic mass.
In a big library, books are arranged by subject and number so that you can find any book quickly. 118 elements are known; without an arrangement it would be very hard to study them.
The Modern Periodic Law states that the physical and chemical properties of elements are a periodic function of their atomic numbers. The same properties come back again and again after fixed intervals.
In the figure : Timeline of attempts at classification: Döbereiner (triads, 1829), Newlands (octaves, 1866), Mendeleev (1869), Moseley (atomic number, 1913).
Rule 1: Döbereiner's triads — Elements with similar properties come in threes, and the atomic mass of the middle one is about the average of the other two.
- Easy : Ca (40), Sr (88), Ba (137): average of Ca and Ba = 88.5, close to Sr.
- Medium : Cl (35.5), Br (80), I (127): average of Cl and I = 81.25, close to Br.
- Exam-type : Only a few triads were found, so the idea could not classify all known elements.
Rule 2: Newlands and Mendeleev — Newlands arranged elements by atomic mass and found that every eighth element was similar (law of octaves), but it failed beyond calcium. Mendeleev put elements in order of atomic mass, left gaps for undiscovered elements and predicted their properties (eka-aluminium became gallium, eka-silicon became germanium).
- Easy : Mendeleev's periodic law is based on atomic mass.
- Medium : His predictions for germanium matched the real element, which made his table widely accepted.
- Exam-type : Mendeleev placed some elements out of mass order (for example Te before I) to keep chemical similarity, a sign that atomic mass was not the true basis.
Rule 3: Moseley and the modern law — Moseley's X-ray work (1913) showed that atomic number, not atomic mass, is the basic property. The modern table has 7 periods and 18 groups.
- Easy : The modern periodic law is based on atomic number.
- Medium : With atomic number as the basis, Te (Z = 52) correctly comes before I (Z = 53).
- Exam-type : Isotopes of an element have different mass but the same Z, so they share one place in the table.
Rule 4: IUPAC names for Z above 100 — Use the digit roots: 0 nil, 1 un, 2 bi, 3 tri, 4 quad, 5 pent, 6 hex, 7 sept, 8 oct, 9 enn; add "ium" at the end. The symbol uses the first letter of each root.
- Easy : Z = 101 is un-nil-un-ium = unnilunium (Unu).
- Medium : Z = 120 is un-bi-nil-ium = unbinilium (Ubn).
- Exam-type : Z = 119 is un-un-enn-ium = ununennium (Uue).
The modern law uses atomic number; Mendeleev's law used atomic mass.
Saying "elements repeat after eight" for the whole table. The repetition interval grows (2, 8, 8, 18, 18, 32).
Memory clue: "Döbereiner 3, Newlands 8, Mendeleev mass, Moseley number".
Spot the difference
| Point | Mendeleev's law | Modern law |
|---|---|---|
| Basis | Atomic mass | Atomic number |
| Isotopes | Problem | No problem |
| Gaps | Left on purpose | Filled by new elements |
Practice questions
- 1State the modern periodic law.
- 2Who showed that atomic number is the basis of the periodic table?
- 3How many periods and groups are there in the modern table?
- 4Check whether Li (7), Na (23), K (39) form a Döbereiner triad.
- 5Write the IUPAC name of the element with Z = 121.
- 6Give one limitation of Newlands' law of octaves.
- 7Give the name and symbol of the element with Z = 130.
- 8Why was Mendeleev right to leave gaps in his table?
Show answers (try them yourself first)
- 1Properties of elements are a periodic function of their atomic numbers.
- 2Henry Moseley.
- 37 periods and 18 groups.
- 4(7 + 39) ÷ 2 = 23, equal to the atomic mass of Na, so yes.
- 5un-bi-un-ium = unbiunium (Ubu).
- 6It worked only up to calcium; it did not leave room for undiscovered elements.
- 7un-tri-nil-ium = untrinilium (Utn).
- 8Some elements were not discovered yet; the gaps allowed him to predict their properties, and later discoveries (gallium, germanium) matched.
Structure of the modern periodic table: blocks, position from configuration, metals and non-metals
Link to Std 9–10 : You located elements by group and period; now we use electronic configuration to find the position without a table.
A railway ticket gives coach and seat number. In the periodic table the period number is like the coach and the group number like the seat; both come from the electronic configuration.
Period number = the highest principal quantum number (n) of the atom. The table has four blocks (s, p, d, f), named after the sub-shell in which the last electron enters.
In the figure : Blocks of the modern table: s (groups 1–2), d (groups 3–12), p (groups 13–18) and f (two rows below).
Rule 1: Length of periods — Period 1 has 2 elements; periods 2 and 3 have 8 each; periods 4 and 5 have 18 each; period 6 has 32; period 7 is meant to hold 32.
- Easy : Period 2 (Li to Ne) has 8 elements.
- Medium : Period 4 has 18 because 4s, 3d and 4p (2 + 10 + 6) fill in turn.
- Exam-type : Lanthanoids (Z = 57–71) and actinoids (Z = 89–103) are placed below the main table as the f-block.
Rule 2: Finding group and period — s-block: group = number of valence electrons (ns¹ is group 1, ns² is group 2). p-block: group = 10 + number of electrons in the outermost shell (ns² np¹ is group 13). d-block: group = number of (n − 1)d electrons + number of ns electrons.
- Easy : Z = 20: [Ar] 4s², so period 4, group 2.
- Medium : Z = 35: [Ar] 3d¹⁰ 4s² 4p⁵, so period 4, group 10 + 7 = 17.
- Exam-type : Z = 26: [Ar] 3d⁶ 4s², so period 4, group 6 + 2 = 8 (d-block).
Rule 3: Metals, non-metals and metalloids — Metals (about three-quarters of the elements) lie on the left and centre, are good conductors and form cations. Non-metals lie at the upper right and form anions. Metalloids (B, Si, Ge, As, Sb, Te) lie along the zig-zag boundary and have intermediate properties.
- Easy : Na is a metal; Cl is a non-metal.
- Medium : Silicon is a metalloid and a semiconductor.
- Exam-type : Hydrogen is placed in group 1 for its ns¹ configuration, though it is not a metal at ordinary conditions.
Structure of the modern periodic table: blocks, position from configuration, metals and non-metals
In the app you can move this figure with your finger.
Open in the appNoble gases (group 18) have complete outer shells (ns² np⁶; helium 1s²) and are very unreactive.
Counting the 3d electrons wrongly while finding the group of a d-block element. Add (n − 1)d and ns electrons.
Memory clue: "s – 1, 2; d – 3 to 12; p – 13 to 18".
Spot the difference
| Point | s-block | p-block |
|---|---|---|
| Groups | 1 and 2 | 13 to 18 |
| General configuration | ns¹⁻² | ns² np¹⁻⁶ |
| Examples | Na, Ca | Al, Cl |
Practice questions
- 1To which block does an element with configuration [Ne] 3s² 3p⁴ belong?
- 2How many elements are there in the sixth period?
- 3Name the six metalloids.
- 4Find the period and group of the element with Z = 16.
- 5Which element is in the third period and group 17?
- 6Give the general outer configuration of the d-block.
- 7Locate the element with the outer configuration [Ar] 3d¹⁰ 4s² 4p² in terms of period and group.
- 8Locate the element with Z = 114 (configuration [Rn] 5f¹⁴ 6d¹⁰ 7s² 7p²).
Show answers (try them yourself first)
- 1p-block.
- 232.
- 3B, Si, Ge, As, Sb, Te.
- 4[Ne] 3s² 3p⁴: period 3, group 16.
- 5Chlorine (Z = 17).
- 6(n − 1)d¹⁻¹⁰ ns¹⁻².
- 7Period 4, group 14 (germanium).
- 8Period 7, group 14.
Atomic radius, ionic radius and isoelectronic species
Link to Std 9–10 : You knew that atoms get bigger down a group; now we explain the trend using nuclear charge and shielding.
A balloon becomes bigger as you add air, but a hot air balloon pulled by many ropes becomes smaller. In atoms, a stronger pull from the nucleus can shrink the electron cloud.
Atomic radius is an estimate of the size of an atom. Covalent radius is half the distance between two bonded identical non-metal atoms; metallic radius is half the distance between neighbouring atoms in a metal crystal. Isoelectronic species have the same number of electrons.
In the figure : Atomic radius (pm) across the third period: Na 186, Mg 160, Al 143, Si 117, P 110, S 104, Cl 99.
Rule 1: Trend in a period — Across a period (left to right) the nuclear charge increases but the electrons enter the same shell, so the pull increases and atomic radius decreases.
- Easy : Li 152 pm, Be 111 pm, B 88 pm, C 77 pm.
- Medium : Bond distance in Br₂ is 228 pm, so covalent radius of Br = 228 ÷ 2 = 114 pm.
- Exam-type : Distance between two adjacent sodium atoms in solid sodium is 372 pm, so metallic radius = 186 pm.
Rule 2: Trend in a group — Down a group a new shell is added and inner shells shield the nucleus, so atomic radius increases.
- Easy : Li 152, Na 186, K 231 pm.
- Medium : F 64, Cl 99, Br 114, I 133 pm.
- Exam-type : Noble gas radii are not compared with covalent radii, since they form no bonds and their van der Waals radii are larger.
Rule 3: Ionic radius — A cation is smaller than its atom (fewer electrons, same nuclear charge); an anion is larger (more electrons, more repulsion).
- Easy : Na 186 pm but Na⁺ 95 pm.
- Medium : F 64 pm but F⁻ 136 pm.
- Exam-type : Of Fe, Fe²⁺ and Fe³⁺ the order of size is Fe > Fe²⁺ > Fe³⁺.
Rule 4: Isoelectronic species — With the same number of electrons, a larger nuclear charge gives a smaller radius.
- Easy : O²⁻, F⁻, Na⁺, Mg²⁺ all have 10 electrons.
- Medium : Order of size: O²⁻ > F⁻ > Na⁺ > Mg²⁺.
- Exam-type : K⁺ and Cl⁻ both have 18 electrons; Cl⁻ (17 protons) is larger than K⁺ (19 protons).
Atomic radius, ionic radius and isoelectronic species
In the app you can move this figure with your finger.
Open in the appMore protons pulling the same number of electrons means a smaller size.
Thinking atoms get smaller down a group because the nucleus is bigger. The new outer shell dominates.
Memory clue: "Left to right, shrink; top to bottom, swell".
Spot the difference
| Point | Covalent radius | Metallic radius |
|---|---|---|
| Found in | Non-metals | Metals |
| Taken as | Half of bond length | Half of distance between metal cores |
Practice questions
- 1Which is larger, Na or Mg?
- 2Which is larger, K or Li?
- 3Is a cation smaller or larger than its atom?
- 4The bond length of I₂ is 266 pm. Find the covalent radius of I.
- 5Arrange Cl⁻, S²⁻, K⁺ in increasing order of size.
- 6Why is Cl smaller than Na?
- 7Arrange Al³⁺, Mg²⁺, Na⁺, F⁻ in decreasing order of size.
- 8Why is the radius of the Be atom (111 pm) greater than that of B (88 pm) even though B has more protons?
Show answers (try them yourself first)
- 1Na.
- 2K.
- 3Smaller.
- 4266 ÷ 2 = 133 pm.
- 5K⁺ < Cl⁻ < S²⁻ (all have 18 electrons; more protons, smaller size).
- 6Same shell but Cl has a larger nuclear charge, so the electrons are pulled closer.
- 7F⁻ > Na⁺ > Mg²⁺ > Al³⁺.
- 8B has more protons and its electrons are in the same shell, so they are pulled more strongly; the radius decreases across the period.
Ionisation enthalpy and electron gain enthalpy
Link to Std 9–10 : You know metals lose and non-metals gain electrons; now we measure how easily.
Pulling a loose button off a shirt takes little effort, but a stitched-in button needs much more. Electrons in alkali metals are like loose buttons.
Ionisation enthalpy (ΔᵢH) is the energy needed to remove an electron from an isolated gaseous atom in its ground state: X(g) → X⁺(g) + e⁻. Electron gain enthalpy (ΔegH) is the enthalpy change when a gaseous atom takes up an electron: X(g) + e⁻ → X⁻(g).
In the figure : First ionisation enthalpy (kJ/mol) of the second period: Li 520, Be 899, B 801, C 1086, N 1402, O 1314, F 1681, Ne 2081.
Rule 1: Trends of ionisation enthalpy — It increases across a period (more nuclear charge, smaller size) and decreases down a group (larger size, more shielding). Successive ionisation enthalpies always increase: ΔᵢH₁ < ΔᵢH₂ < ΔᵢH₃.
- Easy : Na 496 kJ/mol is lower than Mg 737 kJ/mol.
- Medium : Li 520 is higher than Na 496 and K 419 (group 1 decreases).
- Exam-type : For an element, ΔᵢH values of 577, 1817, 2745 and 11 577 kJ/mol show a big jump after the third, so it has 3 valence electrons (group 13, aluminium).
Rule 2: Exceptions — Be (899) is higher than B (801) because a 2s electron is held more tightly than a 2p electron. N (1402) is higher than O (1314) because N has a stable half-filled 2p³, while in O a paired electron in 2p⁴ is easier to remove.
- Easy : B < Be in ionisation enthalpy.
- Medium : O < N in ionisation enthalpy.
- Exam-type : Likewise Al (577) is less than Mg (737).
Rule 3: Electron gain enthalpy — It is generally more negative across a period and less negative down a group. Halogens have large negative values; noble gases have positive values because the new electron must enter a new shell. Cl (−349 kJ/mol) is more negative than F (−328 kJ/mol), because the small 2p subshell of F suffers more repulsion.
- Easy : Cl −349, F −328, Br −325, I −295 kJ/mol.
- Medium : O −141 and S −200 kJ/mol: S is more negative than O.
- Exam-type : Ne +116 kJ/mol: positive, so Ne does not accept an electron.
Ionisation enthalpy and electron gain enthalpy
In the app you can move this figure with your finger.
Open in the appThe second electron gain enthalpy of any element is positive, because you add an electron to an already negative ion.
Writing ionisation enthalpy as a negative number. Removing an electron always needs energy, so ΔᵢH is positive.
Memory clue: "Be-B, N-O dips" for the two exceptions in the second period.
Spot the difference
| Point | Ionisation enthalpy | Electron gain enthalpy |
|---|---|---|
| Process | Remove an electron | Add an electron |
| Sign | Always positive | Usually negative |
| Largest value in period | Noble gas | Halogen (most negative) |
Practice questions
- 1Define ionisation enthalpy.
- 2Which has a higher first ionisation enthalpy, Na or Cs?
- 3Which has a more negative electron gain enthalpy, Cl or Na?
- 4Why is the first ionisation enthalpy of oxygen lower than that of nitrogen?
- 5Why do noble gases have positive electron gain enthalpy?
- 6Why does the second ionisation enthalpy exceed the first?
- 7An element shows ΔᵢH values 737, 1450, 7733 kJ/mol. Which group does it belong to?
- 8Arrange Mg, Al, Si in increasing order of first ionisation enthalpy (Mg 737, Al 577, Si 786).
Show answers (try them yourself first)
- 1The energy needed to remove an electron from an isolated gaseous atom in its ground state.
- 2Na.
- 3Cl.
- 4In N the three 2p electrons are in separate orbitals (half-filled, stable); in O one 2p orbital holds two electrons, and their repulsion makes removal easier.
- 5Their shells are full, so an added electron must enter a new, higher shell.
- 6The ion is positive, so the remaining electrons are held more tightly by the same nuclear charge, and the next one needs more energy.
- 7The big jump comes after the second, so two valence electrons: group 2 (magnesium).
- 8Al < Mg < Si.
Electronegativity, valence and trends in chemical reactivity
Link to Std 9–10 : You wrote formulas using valency; here we see why valency changes in a regular way across the table.
In a tug of war, a stronger team pulls the rope towards itself. In a bond, the more electronegative atom pulls the shared electrons closer.
Electronegativity is the tendency of an atom in a molecule to attract the shared pair of electrons. On the Pauling scale fluorine is 4.0, the highest. The valence of an element is the number of electrons it uses to combine with others.
In the figure : Summary arrows: across a period atomic size falls, while ionisation enthalpy and electronegativity rise; down a group the opposite happens.
Rule 1: Trend of electronegativity (Pauling scale) — Increases across a period and decreases down a group.
- Easy : Period 2: Li 1.0, Be 1.5, B 2.0, C 2.5, N 3.0, O 3.5, F 4.0.
- Medium : Group 17: F 4.0, Cl 3.0, Br 2.8, I 2.5.
- Exam-type : The difference in electronegativity tells the bond type: H–Cl is 3.0 − 2.1 = 0.9 (polar covalent); Na–Cl is 3.0 − 0.9 = 2.1 (largely ionic); Cl–Cl is 0 (pure covalent).
Rule 2: Valence and oxides across period 3 — For main-group elements, the valence is the number of valence electrons (up to 4) or 8 minus that number. Oxides change from basic to acidic across a period: Na₂O and MgO are basic, Al₂O₃ is amphoteric, SiO₂, P₄O₁₀, SO₃ and Cl₂O₇ are acidic.
- Easy : Valence of Na is 1, of Mg 2, of Al 3.
- Medium : Valence of Cl is 8 − 7 = 1 in HCl.
- Exam-type : Mg + N → Mg₃N₂ (3 Mg²⁺ balance 2 N³⁻); Al + Cl → AlCl₃; Ca + O → CaO.
Rule 3: Chemical reactivity — Reactivity of metals increases down a group (easier to lose electrons) and falls across a period; reactivity of non-metals decreases down a group (harder to gain electrons) and increases across a period. Group 1: Li < Na < K < Rb < Cs. Group 17: F > Cl > Br > I.
- Easy : Potassium is more reactive than sodium.
- Medium : Fluorine is the most reactive halogen.
- Exam-type : Noble gases are least reactive; they have complete shells.
Rule 4: Anomalous behaviour of the second-period elements — Li, Be and B differ from the rest of their groups because of small size, high ionisation enthalpy, and the absence of d-orbitals (maximum covalence 4). They resemble elements diagonally below: Li–Mg, Be–Al, B–Si (diagonal relationship).
- Easy : Li behaves like Mg.
- Medium : Be (like Al) forms amphoteric oxide.
- Exam-type : Boron cannot have covalence 6, but aluminium can (AlF₆³⁻), as Al has vacant 3d orbitals.
Electronegativity, valence and trends in chemical reactivity
In the app you can move this figure with your finger.
Open in the appElectronegativity is not measured directly; it is a scale (Pauling, Mulliken).
Treating the noble gases as having a high electronegativity. They are normally left out of the scale.
Memory clue: "FONCl" (F, O, N, Cl) are the four most electronegative elements, in that order.
Spot the difference
| Point | Electronegativity | Electron gain enthalpy |
|---|---|---|
| Measured? | No, a relative scale | Yes, kJ/mol |
| Applies to | Atom in a molecule | Isolated gaseous atom |
Practice questions
- 1Name the most electronegative element.
- 2Which is more reactive, Cs or Li?
- 3Is Na₂O acidic or basic?
- 4Predict the formula of the compound of Al and O.
- 5Compute the electronegativity difference for H–F (H = 2.1, F = 4.0).
- 6Which pair shows a diagonal relationship: Li–Mg or Li–Na?
- 7Arrange N, O, F in the decreasing order of electronegativity.
- 8Why does fluorine, though more electronegative, have a less negative electron gain enthalpy than chlorine?
Show answers (try them yourself first)
- 1Fluorine.
- 2Cs.
- 3Basic.
- 4Al₂O₃.
- 54.0 − 2.1 = 1.9 (polar bond).
- 6Li–Mg.
- 7F > O > N.
- 8Fluorine's atom is so small that the added electron is strongly repelled by the electrons already in its 2p subshell.